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Use the ratio test for absolute convergence (Theorem \(-9.6 .5)\) to determine whether the series converges or diverges. If the test is inconclusive, say so. $$\sum_{k=1}^{\infty}(-1)^{k+1} \frac{2^{k}}{k !}$$

Short Answer

Expert verified
The series converges by the Ratio Test.

Step by step solution

01

Identify the terms of the series

The given series is \( \sum_{k=1}^{\infty}(-1)^{k+1} \frac{2^{k}}{k!} \). We are interested in the absolute value of the terms, which is \( a_k = \frac{2^{k}}{k!} \).
02

Set up the Ratio Test

According to the Ratio Test, we need to calculate \( \lim_{k \to \infty} \left| \frac{a_{k+1}}{a_k} \right| \). Here, \( a_k = \frac{2^k}{k!} \). Thus, \( a_{k+1} = \frac{2^{k+1}}{(k+1)!} \).
03

Compute the ratio \( \frac{a_{k+1}}{a_k} \)

Calculate the ratio: \( \frac{a_{k+1}}{a_k} = \frac{\frac{2^{k+1}}{(k+1)!}}{\frac{2^k}{k!}} = \frac{2^{k+1} \cdot k!}{2^k \cdot (k+1)!} \). This simplifies to \( \frac{2 \cdot 2^k \cdot k!}{2^k \cdot (k+1) \cdot k!} = \frac{2}{k+1} \).
04

Take the limit as \( k \to \infty \)

Now, we find \( \lim_{k \to \infty} \left| \frac{a_{k+1}}{a_k} \right| = \lim_{k \to \infty} \frac{2}{k+1} \). As \( k \to \infty \), \( \frac{2}{k+1} \to 0 \).
05

Apply the conclusion of the Ratio Test

Since \( \lim_{k \to \infty} \left| \frac{a_{k+1}}{a_k} \right| = 0 \), which is less than 1, the Ratio Test implies that the series \( \sum_{k=1}^{\infty} \frac{2^k}{k!} \) is absolutely convergent. Hence, the original series \( \sum_{k=1}^{\infty}(-1)^{k+1} \frac{2^{k}}{k!} \) is convergent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Absolute Convergence
In mathematical analysis, absolute convergence is a stronger form of convergence for infinite series. When we say a series is absolutely convergent, it means that even if we take the absolute value of each term in the series and add them all together, the resulting series still converges. This property is very useful because it guarantees the convergence of the original series, regardless of the order of terms, which is not the case for conditionally convergent series.
For instance, if we consider the series \[ \ \sum_{k=1}^{\infty}(-1)^{k+1} \frac{2^{k}}{k!} \ \] and take absolute values, we focus on \[ a_k = \frac{2^{k}}{k!} \ \]. Applying the Ratio Test to determine absolute convergence, we see that the result indicates the absolute values of the terms form a series that converges. This guarantees that our original series is absolutely convergent. In practical terms, knowing a series is absolutely convergent makes it easier to manipulate and apply in various mathematical contexts.
Series Convergence
Series convergence tells us whether the infinite sum of all terms in a sequence approaches a specific, finite value. Knowing if a series converges is fundamental in calculus and analysis because it determines the limits and behaviors of functions and expressions built on these series.
The concept of convergence is closely tied to the idea of limits. If the partial sums of a series approach a limit, the series converges. Otherwise, it diverges.
Various tests exist to determine convergence, one of which is the Ratio Test used here. The Ratio Test is particularly effective for series involving factorials or exponential functions, as it examines the ratio of successive terms. In our problem, the test showed that \[ \ \lim_{k \to \infty} \left| \frac{a_{k+1}}{a_k} \right| = 0, \ \] indicating convergence because the limit is less than one. This helped confirm that the given series is convergent.
Factorials
Factorials are a mathematical operation that involves multiplying all positive integers up to a certain number. For example, the factorial of 4, written as 4!, is equal to 4 × 3 × 2 × 1 = 24. Factorials grow very rapidly with each additional number, making them powerful in solving combinatorial problems and series calculations.
In calculus, factorials often appear in series, particularly in exponential functions and combinatorial expressions, due to their growth properties. They play a crucial role in ensuring convergence in various series tests, including the Ratio Test. In the given series, \[ \ \frac{2^{k}}{k!}, \ \] we see factorials in the denominator, which help tame the rapid growth of powers of two in the numerator, leading to favorable conditions for convergence. When you apply the Ratio Test here, factorials lead to simplifications that make it easier to observe diminishing terms, resulting in a straightforward conclusion about the series convergence.

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Most popular questions from this chapter

Show that the nth Taylor polynomial for sinh \(x\) about \(x=\ln 4\) is $$\sum_{k=0}^{n} \frac{16-(-1)^{k}}{8 k !}(x-\ln 4)^{k}$$

(a) Use the relationship $$\int \frac{1}{\sqrt{1+x^{2}}} d x=\sinh ^{-1} x+C$$ to find the first four nonzero terms in the Maclaurin series for \(\sinh ^{-1} x\) (b) Express the series in sigma notation. (c) What is the radius of convergence?

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