Chapter 9: Problem 5
Determine whether the series converges, and if so find its sum. $$\sum_{k=1}^{\infty}(-1)^{k-1} \frac{7}{6^{k-1}}$$
Short Answer
Expert verified
The series converges and its sum is 6.
Step by step solution
01
Identify the Series Type
The series is \( \sum_{k=1}^{\infty} (-1)^{k-1} \frac{7}{6^{k-1}} \). It has alternating terms and the general form of a geometric series with alternating signs. We need to determine both convergence and the sum, if it converges.
02
Recognize the Alternating Series
The given series \( \sum_{k=1}^{\infty} (-1)^{k-1} \frac{7}{6^{k-1}} \) is an alternating series, where the terms can be rewritten as \( 7 (-1)^{k-1} \left(\frac{1}{6}\right)^{k-1} \).
03
Write as a Geometric Series
Rewrite the series using the properties of geometric series: \( 7 \sum_{k=0}^{\infty} \left(\frac{-1}{6}\right)^{k} \). This representation shows that it is a geometric series with the first term \( a = 7 \) and a common ratio \( r = -\frac{1}{6} \).
04
Convergence Condition for Geometric Series
For a geometric series \( \sum a r^k \), it converges if \( |r| < 1 \). Here, \( |r| = \left| -\frac{1}{6} \right| = \frac{1}{6} < 1 \), so the series converges.
05
Sum of the Geometric Series
The sum \( S \) of an infinite geometric series is given by the formula \( S = \frac{a}{1-r} \). Substitute \( a = 7 \) and \( r = -\frac{1}{6} \) into this formula: \[ S = \frac{7}{1 - \left(-\frac{1}{6}\right)} = \frac{7}{1 + \frac{1}{6}} \].
06
Simplify the Sum Expression
Calculate the sum by simplifying the denominator: \[ S = \frac{7}{1 + \frac{1}{6}} = \frac{7}{\frac{6}{6} + \frac{1}{6}} = \frac{7}{\frac{7}{6}} \]. This simplifies further to \[ S = 7 \times \frac{6}{7} = 6 \].
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Geometric Series
A geometric series is a series of the form \(a + ar + ar^2 + ar^3 + \ldots\), where \(a\) is the first term, and \(r\) is the common ratio between successive terms. The nature of the common ratio \(r\) greatly influences whether the series converges or diverges.
- If \(|r| < 1\), the series converges.
- If \(|r| \geq 1\), the series diverges.
Alternating Series
An alternating series is one where the signs of the terms alternate, typically represented as \((-1)^n a_n\) or \((-1)^{n-1} a_n\). This alternation in sign is key in determining convergence through the Alternating Series Test.Key properties of an alternating series:
- The terms of the series must decrease in absolute value as the series progresses.
- As \(n\) approaches infinity, the absolute value of the terms must approach zero, i.e., \(\lim_{n \to \infty} a_n = 0\).
Sum of Infinite Series
The sum of an infinite series can be a complex topic, especially depending on the type of series. For geometric series and alternating series, distinct formulas and tests help find these sums when conditions for convergence are met.- **Geometric Series Sum**: If the series is geometric and converges, the sum is given by \(S = \frac{a}{1-r}\). This formula simplifies finding sums of convergent geometric series efficiently.- **Alternating Series**: While there's no direct formula like geometric series, convergence can be established using the Alternating Series Test. Once convergence is confirmed, the remainder/error after \(n\) terms is less than the first omitted term, providing a means to approximate the sum.For the specific case of \(7 \sum_{k=0}^{\infty} \left(\frac{-1}{6}\right)^{k}\), we use the geometric series formula once convergence is confirmed. The sum simplifies to 6, illustrating that with correct application of these principles, analyzing infinite series becomes more approachable.