Chapter 9: Problem 20
Determine whether the series converges. $$\sum_{k=1}^{\infty} \frac{1}{\sqrt{k^{2}+1}}$$
Short Answer
Expert verified
The series diverges.
Step by step solution
01
Understand the Series Form
We are given the series \( \sum_{k=1}^{\infty} \frac{1}{\sqrt{k^2 + 1}} \). The convergence of this series needs to be determined. A series converges if the sequence of its partial sums \( S_n = a_1 + a_2 + \ldots + a_n \) has a finite limit as \( n \to \infty \).
02
Identify a Comparison Series
For series convergence tests, particularly the Comparison Test, we identify a simpler series to compare with \( \sum_{k=1}^{\infty} \frac{1}{\sqrt{k^2 + 1}} \). Observe that for large \( k \), \( \sqrt{k^2 + 1} \approx k \), so we approximate the terms as \( \frac{1}{\sqrt{k^2 + 1}} \approx \frac{1}{k} \).
03
Apply the Comparison Test
The series \( \sum_{k=1}^{\infty} \frac{1}{k} \) is a well-known divergent series (the harmonic series). Since \( 1/k \leq \frac{1}{\sqrt{k^2+1}} \) for all \( k \geq 1 \), and since a larger or equal series than a divergent one also diverges, the comparison test implies that \( \sum_{k=1}^{\infty} \frac{1}{\sqrt{k^2+1}} \) diverges.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Comparison Test
The Comparison Test is a valuable tool in determining the convergence or divergence of an infinite series. It involves comparing a given series to another series whose convergence properties are already known. The logic behind this test is simple. If you have a series \( \sum_{k=1}^{\infty} a_k \) and you want to compare it with \( \sum_{k=1}^{\infty} b_k \), you examine the terms of both series:
- If \( a_k \leq b_k \) for all \( k \) starting from some point, and \( \sum_{k=1}^{\infty} b_k \) is known to converge, then \( \sum_{k=1}^{\infty} a_k \) will also converge.
- If \( a_k \geq b_k \) for all \( k \) starting from some point, and \( \sum_{k=1}^{\infty} b_k \) is known to diverge, then \( \sum_{k=1}^{\infty} a_k \) will also diverge.
Divergent Series
A divergent series is one that does not have a finite sum. This means its sequence of partial sums does not approach a finite limit as the number of terms grows indefinitely. Understanding divergence is crucial when working with infinite series. Unlike convergent series, divergent series do not equal a specific number; instead, their partial sums either oscillate or grow without bound.
The exercise dealt with a series that was shown to diverge by comparison with the harmonic series. A series is labeled divergent if:
The exercise dealt with a series that was shown to diverge by comparison with the harmonic series. A series is labeled divergent if:
- The partial sums do not settle towards a single value.
- The behavior of the series closely resembles a known divergent series.
Harmonic Series
The harmonic series is a well-known example of a divergent series, frequently encountered in calculus. It is expressed as:\[ \sum_{k=1}^{\infty} \frac{1}{k} \]Despite the terms individually becoming very small as \( k \) increases, the sum of the series grows indefinitely. This counterintuitive nature is what makes it fascinating. When dealing with series convergence, the harmonic series often serves as a benchmark:
- If a series term behaves similarly to \( \frac{1}{k} \) for large \( k \), there's a strong likelihood of divergence.
- It is used often in the Comparison Test to establish divergence of more complex series.