Chapter 9: Problem 2
Use the difference \(a_{n+1}-a_{n}\) to show that the given sequence \(\left\\{a_{n}\right\\}\) is strictly increasing or strictly decreasing. $$\left\\{1-\frac{1}{n}\right\\}_{n=1}^{+\infty}$$
Short Answer
Expert verified
The sequence \(\left\{a_n\right\}\) is strictly increasing.
Step by step solution
01
Identify the Subsequent Term
The given sequence is \(\left\{1-\frac{1}{n}\right\}_{n=1}^{+\infty}\). First, identify the general term \(a_n = 1 - \frac{1}{n}\) and the subsequent term \(a_{n+1} = 1 - \frac{1}{n+1}\).
02
Calculate the Difference
Calculate the difference \(a_{n+1} - a_n = \left(1 - \frac{1}{n+1}\right) - \left(1 - \frac{1}{n}\right) = \frac{1}{n} - \frac{1}{n+1}\).
03
Simplify the Difference
Simplify the expression \(\frac{1}{n} - \frac{1}{n+1}\). Rewrite it with a common denominator: \(\frac{1\cdot(n+1) - 1\cdot n}{n(n+1)} = \frac{1}{n(n+1)}\).
04
Determine the Sign of the Difference
Since \(\frac{1}{n(n+1)} > 0\) for all positive integers \(n\), it follows that \(a_{n+1} - a_n > 0\).
05
Conclude the Sequence Behavior
Since \(a_{n+1} - a_n > 0\) for all \(n\), the sequence \(\left\{a_n\right\}\) is strictly increasing.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Strictly Increasing
When we say a sequence is "strictly increasing," we mean that each term in the sequence is greater than the one before it. This concept is like climbing a set of stairs, where each step is higher than the last. In mathematical terms, a sequence \( \{a_n\} \) is strictly increasing if for every \( n \), \( a_{n+1} > a_n \). This ensures there is a constant upward trend without any plateaus or dips.
For example, consider the sequence \( 1 - \frac{1}{n} \). To show it's strictly increasing, we look at the difference \( a_{n+1} - a_n \). If this difference is positive for all \( n \), then each term is truly larger than the last, confirming the sequence is strictly increasing.
For example, consider the sequence \( 1 - \frac{1}{n} \). To show it's strictly increasing, we look at the difference \( a_{n+1} - a_n \). If this difference is positive for all \( n \), then each term is truly larger than the last, confirming the sequence is strictly increasing.
- Climbing stairs analogy: each term is a step higher.
- Mathematical criterion: \( a_{n+1} - a_n > 0 \).
- A positive difference assures strict increase.
Difference of Terms
The difference between consecutive terms in a sequence is a powerful tool to determine if the sequence is increasing or decreasing. This involves calculating \( a_{n+1} - a_n \), which gives the numerical gap between the subsequent term and the current term. If this gap - or difference - is positive, then the sequence is increasing. If negative, the sequence is decreasing.
In our sequence \( 1 - \frac{1}{n} \), we calculated the difference as \( \frac{1}{n} - \frac{1}{n+1} = \frac{1}{n(n+1)} \). Notice the positive result, \( \frac{1}{n(n+1)} \), which means each term surpasses the one before it, confirming a strictly increasing pattern.
In our sequence \( 1 - \frac{1}{n} \), we calculated the difference as \( \frac{1}{n} - \frac{1}{n+1} = \frac{1}{n(n+1)} \). Notice the positive result, \( \frac{1}{n(n+1)} \), which means each term surpasses the one before it, confirming a strictly increasing pattern.
- Difference calculation shows trends in the sequence.
- Positive difference indicates increase, negative indicates decrease.
- This calculation solidifies understanding of the sequence's behavior.
General Term
The general term \( a_n \) offers a formula to calculate any term in the sequence, which is foundational in understanding the sequence's behavior. In our sequence, the general term is expressed as \( a_n = 1 - \frac{1}{n} \). This form provides a snapshot of how terms are generated based on their position \( n \) in the sequence.
The importance of the general term lies in its predictability; it helps you find any term without listing all previous terms. For instance, if you want to find the 100th term of the sequence, simply plug in \( n = 100 \) to get \( a_{100} = 1 - \frac{1}{100} \).
The importance of the general term lies in its predictability; it helps you find any term without listing all previous terms. For instance, if you want to find the 100th term of the sequence, simply plug in \( n = 100 \) to get \( a_{100} = 1 - \frac{1}{100} \).
- General term allows calculation of any term directly.
- Offers insight into the sequence's formation and progression.
- Facilitates deeper understanding and is vital for analysis.