Chapter 9: Problem 16
Determine whether the series converges. $$\sum_{k=1}^{\infty} \frac{\tan ^{-1} k}{1+k^{2}}$$
Short Answer
Expert verified
The series converges by the comparison test with \( \sum \frac{1}{k^2} \).
Step by step solution
01
Identify the series
The series given is \( \sum_{k=1}^{\infty} \frac{\tan ^{-1} k}{1+k^{2}} \). We need to determine if it converges.
02
Use a comparison test
To determine the convergence of the series, let's compare \( \frac{\tan^{-1} k}{1 + k^2} \) with another known series. Notice that \( \tan^{-1} k \) is a bounded function, approximately equal to \( \frac{\pi}{2} \) for large \( k \). Thus, we can approximate:\[0 \leq \frac{\tan^{-1} k}{1 + k^2} \leq \frac{\pi/2}{1 + k^2}.\]
03
Compare with a known convergent series
Consider the series \( \sum_{k=1}^{\infty} \frac{1}{k^2} \), which is known to converge (the p-series with \( p = 2 \), where \( p > 1 \)). Since \( \frac{\tan^{-1} k}{1 + k^2} \leq \frac{\pi/2}{k^2} \), by the comparison test, the series \( \sum_{k=1}^{\infty} \frac{\tan^{-1} k}{1 + k^2} \) converges.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Comparison Test
To determine whether a series converges, one common and effective method is the Comparison Test. This test helps us analyze whether a series converges by comparing it with another series that has known convergence properties.
Let's break it down:
Let's break it down:
- Suppose we have two series, \( ext{Series A} = \sum_{k=1}^{\infty} a_k \) and \( ext{Series B} = \sum_{k=1}^{\infty} b_k \).
- If \( 0 \leq a_k \leq b_k \) for all values of \( k \) beyond some index, and if Series B is known to converge, then Series A also converges.
- On the flip side, if \( a_k \geq b_k \geq 0 \) and Series B diverges, so does Series A.
Bounded Functions
In mathematics, understanding bounded functions can simplify complex series analysis. A function like \( \tan^{-1} k \) is an excellent example, as its values lie within a fixed range.
Why is this important? Imagine trying to understand the behavior of a series that seems complex at first glance. Knowing that certain elements are bounded can dramatically simplify your work.
A bounded function has values that never exceed a particular upper limit and never go below a specific lower limit. For instance:
Why is this important? Imagine trying to understand the behavior of a series that seems complex at first glance. Knowing that certain elements are bounded can dramatically simplify your work.
A bounded function has values that never exceed a particular upper limit and never go below a specific lower limit. For instance:
- For \( \tan^{-1} k \), as \( k \) approaches infinity, the value tends toward \( \frac{\pi}{2} \), making it bounded above by \( \frac{\pi}{2} \).
- This predictable behavior implies that for the given series, \( \frac{\tan^{-1} k}{1+k^2} \) can never exceed the bound \( \frac{\pi}{2(1+k^2)} \).
P-Series
The P-Series is a critical concept in understanding series convergence, specifically related to the behavior of the series \( \sum_{k=1}^{\infty} \frac{1}{k^p} \). With this series type:
In this exercise, the \( \sum_{k=1}^{\infty} \frac{1}{k^2} \) series functions as a classic example of how P-series provide straightforward benchmarks. Recognizing a series as a P-series can immediately inform about its convergence, letting you apply techniques like the Comparison Test efficiently.
- Convergence depends critically on the value of \( p \).
- It converges when \( p > 1 \) and diverges when \( p \leq 1 \).
In this exercise, the \( \sum_{k=1}^{\infty} \frac{1}{k^2} \) series functions as a classic example of how P-series provide straightforward benchmarks. Recognizing a series as a P-series can immediately inform about its convergence, letting you apply techniques like the Comparison Test efficiently.