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Classify each series as absolutely convergent, conditionally convergent, or divergent. $$\sum_{k=1}^{\infty} \frac{(-1)^{k+1}}{3 k}$$

Short Answer

Expert verified
The series is conditionally convergent.

Step by step solution

01

Identify the Series Type

The given series is \( \sum_{k=1}^{\infty} \frac{(-1)^{k+1}}{3 k} \), which is an alternating series because the terms have the factor \((-1)^{k+1}\) that causes them to alternate in sign.
02

Apply the Alternating Series Test

To determine if the series converges, apply the Alternating Series Test. For this test, ensure the non-alternating part of the series, \( \frac{1}{3k} \), is (1) positive, (2) decreasing, and (3) approaches zero as \( k \to \infty \). Indeed, \( \frac{1}{3k}\) is positive for all \( k \geq 1 \), it is decreasing since as \( k \) increases, the denominator increases, making the fraction smaller, and it approaches zero as \( k \to \infty \). Therefore, the series converges by the Alternating Series Test.
03

Check for Absolute Convergence

To check if the series is absolutely convergent, examine the absolute series \( \sum_{k=1}^{\infty} \left| \frac{(-1)^{k+1}}{3k} \right| = \sum_{k=1}^{\infty} \frac{1}{3k} \). This is a harmonic series, which is known to diverge. Therefore, the series does not converge absolutely.
04

Classify the Series

Since the series converges by the Alternating Series Test but does not converge absolutely, it is conditionally convergent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Convergence
Conditional convergence occurs when a series converges due to its alternating nature but does not converge when the absolute values of its terms are summed. In other words, a conditionally convergent series will pass the Alternating Series Test but fail the test for absolute convergence.

To decide if a series is conditionally convergent, follow these steps:
  • First, apply the Alternating Series Test. Ensure the sequence being summed is decreasing and approaching zero.
  • Next, examine the series formed by taking the absolute value of each term. Check if this new series converges absolutely.
If the original series converges but the absolute series does not, the series is conditionally convergent. This unique type of convergence is important because it allows for convergence without the requirement of the complete series summing to a finite number in terms of absolute values.
Absolute Convergence
Absolute convergence means that a series converges even when you take the absolute value of each term. This type of convergence is stronger than conditional convergence.

Here's how to determine absolute convergence:
  • First, look at the series without considering the alternating sign (use absolute values).
  • If this absolute series converges, then the original series is absolutely convergent.
Absolute convergence guarantees that rearranging the terms of the series won't change its sum. This is because summing positive numbers (thanks to the absolute values) always gives a well-defined result. In our example, after applying the Alternating Series Test, we found that the absolute series diverges; hence, the original series is not absolutely convergent.
Divergence of Harmonic Series
The harmonic series is a well-known example of a divergent series. It can be represented as \[\sum_{k=1}^{fty} \frac{1}{k}.\]Despite the terms tending to zero, the series itself grows without bound due to the slow rate of decay.

In the context of absolute convergence, such as in our problem example where the absolute series \[\sum_{k=1}^{\infty} \frac{1}{3k}\]is essentially a constant multiple of the harmonic series, it too diverges. This means that absolute convergence is not achieved.

Understanding why the harmonic series diverges helps in recognizing similar patterns in other series and in appreciating the delicate nature of infinite sums. The harmonic series defies our intuitive expectation that zero-vanishing terms would lead to a finite sum, highlighting the need for careful examination in series convergence problems.

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Most popular questions from this chapter

(a) Use the relationship $$\int \frac{1}{\sqrt{1-x^{2}}} d x=\sin ^{-1} x+C$$ to find the first four nonzero terms in the Maclaurin series for \(\sin ^{-1} x\) (b) Express the series in sigma notation. (c) What is the radius of convergence?

Exercise will show how a partial sum can be used to obtain upper and lower bounds on the sum of a series when the hypotheses of the integral test are satisfied. This result will be needed in Exercises. It was stated in Exercise 35 that $$\sum_{k=1}^{\infty} \frac{1}{k^{4}}=\frac{\pi^{4}}{90}$$ (a) Let \(s_{n}\) be the \(n\) th partial sum of the series above. Show that $$ s_{n}+\frac{1}{3(n+1)^{3}} < \frac{\pi^{4}}{90} < s_{n}+\frac{1}{3 n^{3}} $$ (b) We can use a partial sum of the series to approximate \(\pi^{4} / 90\) to three decimal-place accuracy by capturing the sum of the series in an interval of length 0.001 (or less). Find the smallest value of \(n\) such that the interval containing \(\pi^{4} / 90\) in part (a) has a length of 0.001 or less. (c) Approximate \(\pi^{4} / 90\) to three decimal places using the midpoint of an interval of width at most 0.001 that contains the sum of the series. Use a calculating utility to confirm that your answer is within 0.0005 of \(\pi^{4} / 90\).

Suppose that the power series \(\sum c_{k}\left(x-x_{0}\right)^{k}\) has a finite radius of convergence \(R,\) and the power series \(\sum d_{k}\left(x-x_{0}\right)^{k}\) has a radius of convergence of \(+\infty\) What can you say about the radius of convergence of \(\sum\left(c_{k}+d_{k}\right)\left(x-x_{0}\right)^{k} ?\) Explain your reasoning.

Suppose that the power series \(\sum c_{k}\left(x-x_{0}\right)^{k}\) has a finite radius of convergence \(R_{1}\) and the power series \(\sum d_{k}\left(x-x_{0}\right)^{k}\) has a finite radius of convergence \(R_{2}\) What can you say about the radius of convergence of \(\sum\left(c_{k}+d_{k}\right)\left(x-x_{0}\right)^{k} ?\) Explain your reasoning. [Hint: The case \(\left.R_{1}=R_{2} \text { requires special attention. }\right]\)

Find the first four distinct Taylor polynomials about \(x=x_{0},\) and use a graphing utility to graph the given function and the Taylor polynomials on the same screen. $$f(x)=\cos x ; x_{0}=\pi$$

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