Chapter 8: Problem 2
Solve the differential equation by the method of integrating factors. $$\frac{d y}{d x}+2 x y=x$$
Short Answer
Expert verified
The solution is \( y = \frac{1}{2} + Ce^{-x^2} \).
Step by step solution
01
Identify the form of the differential equation
The given differential equation \( \frac{d y}{d x} + 2xy = x \) is a first-order linear differential equation, which can be written in the standard form \( \frac{dy}{dx} + P(x)y = Q(x) \) where \( P(x) = 2x \) and \( Q(x) = x \).
02
Find the integrating factor
The integrating factor \( \mu(x) \) can be found using the formula \( \mu(x) = e^{\int P(x) \, dx} \). Since \( P(x) = 2x \), calculate the integral: \( \int 2x \, dx = x^2 \). So, \( \mu(x) = e^{x^2} \).
03
Multiply the whole equation by the integrating factor
Multiply both sides of the equation \( \frac{dy}{dx} + 2xy = x \) by the integrating factor \( e^{x^2} \), resulting in: \( e^{x^2}\frac{dy}{dx} + 2x e^{x^2} y = x e^{x^2} \).
04
Express the left-hand side as a derivative
Recognize that the left side of the equation \( e^{x^2}\frac{dy}{dx} + 2x e^{x^2} y \) is the derivative of \((e^{x^2} y)\) with respect to \( x \). So it becomes: \( \frac{d}{dx} (e^{x^2} y) = x e^{x^2} \).
05
Integrate both sides
Integrate both sides with respect to \( x \): \( \int \frac{d}{dx}(e^{x^2} y) \, dx = \int x e^{x^2} \, dx \). The left side simplifies to \( e^{x^2} y \). The right side requires integration by parts or substitution. Here, using substitution, let \( u = x^2 \), then \( du = 2x \, dx \), or \( x \, dx = \frac{du}{2} \). The integral becomes \( \frac{1}{2} \int e^u \, du = \frac{1}{2} e^u + C = \frac{1}{2} e^{x^2} + C \).
06
Solve for y
Setting \( e^{x^2} y = \frac{1}{2} e^{x^2} + C \), divide both sides by \( e^{x^2} \) to solve for \( y \): \( y = \frac{1}{2} + Ce^{-x^2} \), where \( C \) is the constant of integration.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
First-Order Linear Differential Equation
A first-order linear differential equation is a specific type of differential equation of the form \( \frac{dy}{dx} + P(x)y = Q(x) \), where \( P(x) \) and \( Q(x) \) are functions of \( x \). It is called 'first-order' because it involves only the first derivative of the function \( y \). Linear means that the function \( y \) and its derivative appear to the power of 1.
Here's how to recognize these equations:
Here's how to recognize these equations:
- Looks similar to a straight line equation in algebra, but involves derivatives.
- The term \( P(x)y \) is the part that multiplies \( y \) by a function of \( x \).
- \( Q(x) \) functions as the "source term" or constant term.
Integrating Factor
The integrating factor is a clever technique used to solve first-order linear differential equations. It transforms the equation into a form that is easier to integrate. The integrating factor, \( \mu(x) \), is found using the formula \( \mu(x) = e^{\int P(x) \, dx} \), where \( P(x) \) is the function multiplying the \( y \) term in the differential equation.
Using an integrating factor involves the following steps:
Using an integrating factor involves the following steps:
- Find \( P(x) \) from the differential equation.
- Compute the indefinite integral \( \int P(x) \, dx \).
- Exponentiate the result to get \( \mu(x) = e^{\int P(x) \, dx} \).
Method of Integration by Parts
Integration by parts is a technique derived from the product rule for derivatives, useful when integrating products of functions. While tackling problems involving functions such as \( xe^{x^2} \), integration by parts becomes particularly handy.
Here's the basic formula for integration by parts: \[ \int u \, dv = uv - \int v \, du \]Where:
Here's the basic formula for integration by parts: \[ \int u \, dv = uv - \int v \, du \]Where:
- \( u \) and \( dv \) are parts chosen from the integral \( \int u \, dv \).
- \( du \) is the derivative of \( u \), and \( v \) is the antiderivative of \( dv \).
Constant of Integration
In indefinite integration, the result always includes a constant of integration, denoted as \( C \). This constant accounts for the family of all possible solutions to a differential equation or indefinite integral.
Why is it important?
Why is it important?
- Represents all vertical shifts of a given integral function.
- Vital in initial value problems where you find a unique solution by determining \( C \).
- Signals that a solution has a residual part that can vary by a constant amount.