/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 In each part, use integration by... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In each part, use integration by parts or other methods to derive the reduction formula. (a) \(\int \sec ^{n} x d x=\frac{\sec ^{n-2} x \tan x}{n-1}+\frac{n-2}{n-1} \int \sec ^{n-2} x d x\) (b) \(\int \tan ^{n} x d x=\frac{\tan ^{n-1} x}{n-1}-\int \tan ^{n-2} x d x\) (c) \(\int x^{n} e^{x} d x=x^{n} e^{x}-n \int x^{n-1} e^{x} d x\)

Short Answer

Expert verified
Reduction formulas derived using integration by parts: (a) Secant, (b) Tangent, and (c) Polynomial with exponential.

Step by step solution

01

Integration by Parts Formula

The integration by parts formula is given by \( \int u \, dv = uv - \int v \, du \). This formula will be used to derive the reduction formula for each integral.
02

Part (a) - Choose Functions for Integration by Parts

For \( \int \sec^n x \, dx \), choose \( u = \sec^{n-2} x \) and \( dv = \sec^2 x \, dx \). Then, differentiate and integrate to find \( du = (n-2) \sec^{n-3} x \sec x \tan x \, dx \) and \( v = \tan x \).
03

Part (a) - Apply Integration by Parts

Using the choices from Step 2, apply the integration by parts formula: \[ \int \sec^n x \, dx = \sec^{n-2} x \tan x - (n-2) \int \sec^{n-2} x \tan^2 x \, dx. \]
04

Part (a) - Simplify and Rearrange

Notice that \( \tan^2 x = \sec^2 x - 1 \), thus \( \int \sec^{n} x \, dx = \frac{\sec^{n-2} x \tan x}{n-1} + \frac{n-2}{n-1} \int \sec^{n-2} x \, dx \).
05

Part (b) - Choose Functions for Integration by Parts

For \( \int \tan^n x \, dx \), choose \( u = \tan^{n-1} x \) and \( dv = \sec^2 x \, dx \). Then, differentiate and integrate to find \( du = (n-1) \tan^{n-2} x \sec^2 x \, dx \) and \( v = \tan x \).
06

Part (b) - Apply Integration by Parts

Apply the formula: \( \int \tan^n x \, dx = \tan^{n-1} x \tan x - (n-1) \int \tan^{n-2} x \tan x \sec^2 x \, dx \).
07

Part (b) - Simplify and Rearrange

Simplify to get \( \int \tan^n x \, dx = \frac{\tan^{n-1} x}{n-1} - \int \tan^{n-2} x \, dx \).
08

Part (c) - Choose Functions for Integration by Parts

For \( \int x^n e^x \, dx \), choose \( u = x^n \) and \( dv = e^x \, dx \). Then, differentiate and integrate to find \( du = n x^{n-1} \, dx \) and \( v = e^x \).
09

Part (c) - Apply Integration by Parts

Apply the formula: \( \int x^n e^x \, dx = x^n e^x - n \int x^{n-1} e^x \, dx \).
10

Summary of Reduction Formulas

The reduction formulas derived are: (a) \( \int \sec^n x \, dx \) given by the formula from Step 4.(b) \( \int \tan^n x \, dx \) given by the formula from Step 7.(c) \( \int x^n e^x \, dx \) given by the formula from Step 9.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integration by Parts
Integration by parts is a powerful technique used to solve integrals, especially when the integrand is a product of two functions. It is based on the product rule for differentiation, but works in reverse. The formula for integration by parts is \( \int u \, dv = uv - \int v \, du \). Here, we strategically choose parts of the integral as \( u \) and \( dv \).
Deciding which function to choose as \( u \) and which as \( dv \) often depends on which functions are easier to differentiate or integrate. A handy rule is the LIPET rule, favoring Logarithmic, Inverse trigonometric, Polynomial, Exponential, and Trigonometric functions, in that order. For example, when integrating \( \int x^n e^x \, dx \), \( u = x^n \) and \( dv = e^x \, dx \) would be a logical choice due to the simplification potential during differentiation. Once \( u \) and \( dv \) are selected, differentiate \( u \) to get \( du \) and integrate \( dv \) to get \( v \).
Remember, integration by parts not only simplifies the integration process but often leads to recursive reduction formulas, helping in solving repeated integrals.
Secant Function Integration
Integrating the secant function raised to a power, \( \int \sec^n x \, dx \), can be complex but is manageable with integration by parts. A reduction formula allows this type of integral to be expressed in terms of a simpler integral, making it easier to compute.
For example, in our exercise, we chose function parts to integrate \( \sec^n x \):
  • Set \( u = \sec^{n-2} x \) because it allows for easy differentiation.
  • Choose \( dv = \sec^2 x \, dx \) as integrals of \( \sec^2 x \) are well known (resulting in \( v = \tan x \)).
After applying integration by parts, simplify using the identity \( \tan^2 x = \sec^2 x - 1 \). This identity is crucial, allowing us to rearrange and obtain the reduction formula:
```\[ \int \sec^n x \, dx = \frac{\sec^{n-2} x \tan x}{n-1} + \frac{n-2}{n-1} \int \sec^{n-2} x \, dx \]```
These steps transform a complex integration problem into repeatable, manageable pieces.
Tangent Function Integration
Integrating a tangent function raised to a power, such as \( \int \tan^n x \, dx \), can also be simplified using a clever application of integration by parts. We start by setting parts of the integrand as follows:
  • Let \( u = \tan^{n-1} x \), as this leads to a decrease in power after differentiation.
  • Choose \( dv = \sec^2 x \, dx \), knowing its integral is \( \tan x \).
Applying the integration by parts formula simplifies the problem setup. Further simplification revolves around algebraic rearrangement, ultimately yielding the formula:
```\[ \int \tan^n x \, dx = \frac{\tan^{n-1} x}{n-1} - \int \tan^{n-2} x \, dx \]```
By utilizing the reduction method, each step reduces the power of the tangent function. Essentially, the reduction formula helps break down higher-degree expressions into simpler forms that are easier to integrate or evaluate.
Exponential Function Integration
The integration of functions like \( \int x^n e^x \, dx \) marries exponential functions with polynomials, often necessitating the use of integration by parts whenever polynomial terms appear. Here's the thought process:
  • Choose \( u = x^n \), as differentiating it reduces the exponent, often making subsequent processes easier.
  • Select \( dv = e^x \, dx \), as \( e^x \) simply integrates to itself, which helps in keeping calculations straightforward.
By applying the integration by parts formula, the problem reduces to:
```\[ \int x^n e^x \, dx = x^n e^x - n \int x^{n-1} e^x \, dx \]```
The exponential function retains its form through integration, making it particularly pleasant to work with. By iterating this procedure, you obtain a sequence of simpler integrals, ultimately reducing it down to a basic form where standard integration techniques easily apply.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.