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Evaluate the integral. $$\int \frac{3 x^{2}-10}{x^{2}-4 x+4} d x$$

Short Answer

Expert verified
The integral is \( 3x + 2 \ln |x-2| - \frac{18}{x-2} + C \).

Step by step solution

01

Identify the Structure of the Integrand

Examine the given integral \( \int \frac{3x^2 - 10}{x^2 - 4x + 4} \, dx \). Notice that the denominator can be simplified further since \( x^2 - 4x + 4 \) can be rewritten as \((x-2)^2\). This suggests breaking the function down into simpler parts or consider polynomial division if possible.
02

Perform Polynomial Long Division

Perform polynomial long division of \( 3x^2 - 10 \) by \( x^2 - 4x + 4 \). The result is: the quotient is \( 3 \) and the remainder is \( 2x - 22 \). Thus, the integral becomes \( \int \left( 3 + \frac{2x - 22}{(x-2)^2} \right) \, dx \).
03

Split the Integral

Split the integral into two parts for easier handling: \[ \int 3 \, dx + \int \frac{2x - 22}{(x-2)^2} \, dx \]. The first integral is straightforward, but the second requires more work.
04

Integrate the Constant

Integrate the constant \( 3 \). The result is: \[ \int 3 \, dx = 3x + C_1 \].
05

Simplify the Second Integral

Consider the second integral \( \int \frac{2x - 22}{(x-2)^2} \, dx \). Substitute \( u = x-2 \), so \( du = dx \) and \( x = u + 2 \). This transforms the integral into: \[ \int \frac{2(u+2) - 22}{u^2} \, du = \int \frac{2u + 4 - 22}{u^2} \, du \].
06

Separate the Terms in the Numerator

Separate the integral of the transformed expression: \[ \int \frac{2u - 18}{u^2} \, du = \int \left( \frac{2u}{u^2} - \frac{18}{u^2} \right) \, du = \int \left( \frac{2}{u} - \frac{18}{u^2} \right) \, du \].
07

Integrate Separated Terms

Integrate the terms: \[ \int \frac{2}{u} \, du = 2 \ln |u| + C_2 \] and \[ \int -\frac{18}{u^2} \, du = 18 \cdot \frac{1}{u} + C_3 = -\frac{18}{u} + C_3 \].
08

Substitute Back to Original Variable

Substitute back \( u = x - 2 \) to convert back to the original variable:\[ 2\ln |x-2| - \frac{18}{x-2} + C_4 \].
09

Combine All Parts

Combine all parts including the constant term:\[ 3x + 2\ln |x-2| - \frac{18}{x-2} + C \] where \( C = C_1 + C_2 + C_3 + C_4 \) is a constant of integration.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polynomial Long Division
Polynomial long division is similar to the arithmetic long division we learn in elementary school. However, here we deal with polynomials instead of numbers. This technique is particularly useful when you are faced with a rational expression like \( \frac{3x^2 - 10}{x^2 - 4x + 4} \).

In the exercise example, the dividend is \( 3x^2 - 10 \) while the divisor is \( x^2 - 4x + 4 \), which can be rewritten as \((x-2)^2\). Through division, we obtain a quotient of 3 and a remainder of \( 2x - 22 \).

This results in splitting the original integral into two simpler parts: \( \int (3) \, dx + \int \frac{2x - 22}{(x-2)^2} \, dx \). With this step completed, tackling the problem becomes significantly easier as it reduces complexity, allowing us to deal with simpler individual integrals.
U-substitution
U-substitution, also known as the method of integration by substitution, is a technique used to simplify integration involving composite functions. It's akin to the chain rule used in differentiation.

In the step-by-step exercise, we needed to tackle the integral \( \int \frac{2x - 22}{(x-2)^2} \, dx \). To simplify, you can let \( u = x - 2 \), making \( du = dx \), and then rewrite \( x \) in terms of \( u \) as \( x = u + 2 \).

This transforms the integral: \( \int \frac{2(x-2+2) - 22}{(x-2)^2} \, dx \) becomes \( \int \frac{2(u + 2) - 22}{u^2} \, du \). The goal of substitution is to make the integral easier to evaluate by changing variables.
Logarithmic Integration
Logarithmic integration often applies when you have a fraction with a linear numerator and its derivative in the denominator, or when a term is in the form \( \frac{1}{x} \). This is particularly relevant after simplifying terms via substitution or division.

In our example, U-substitution paved the way to integral forms like \( \int \frac{2}{u} \, du \). This integrates nicely to a natural logarithm: \( 2 \ln|u| + C_2 \).

Logarithmic integration is essential when dealing with functions that result in terms like \( \frac{1}{x} \), lending itself to form \( \ln|x| + C \), representing a broad class of integrals in calculus.
Constants of Integration
When performing indefinite integration, the result is a family of functions. The constant of integration \( C \) accounts for this family, representing undetermined values that can shift the function vertically.

During the integration in our example, various parts conclude with a constant term, such as \( C_1 \), \( C_2 \), and so forth. Upon combining all parts of the integrated expression, these constants combine into a general \( C \), encapsulating all constants previously introduced.

Thus, the final integral expression \[ 3x + 2 \ln|x-2| - \frac{18}{x-2} + C \] reflects these constants. Remembering to add \( C \) is crucial, as it assures that the solution covers all potential shifts of the antiderivative.

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Most popular questions from this chapter

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