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Find the exact arc length of the curve over the interval. $$y=x^{2 / 3} \text { from } x=1 \text { to } x=8$$

Short Answer

Expert verified
The exact arc length of the curve from \(x=1\) to \(x=8\) is calculated using the arc length formula with an integral.

Step by step solution

01

Calculate the Derivative

The formula for arc length of a curve given by \(y = f(x)\) from \(x = a\) to \(x = b\) is \(\int_{a}^{b} \sqrt{1 + \left(\frac{dy}{dx}\right)^2} \, dx\). First, we need to find the derivative \(\frac{dy}{dx}\). Given \(y = x^{2/3}\), use the power rule to find \(\frac{dy}{dx} = \frac{2}{3}x^{-1/3}\).
02

Substitute Derivative into Arc Length Formula

Now that we have \(\frac{dy}{dx} = \frac{2}{3}x^{-1/3}\), substitute it into the arc length formula to get \[ \int_{1}^{8} \sqrt{1 + \left(\frac{2}{3}x^{-1/3}\right)^2} \, dx. \] Simplify under the square root: \(\left(\frac{2}{3}x^{-1/3}\right)^2 = \frac{4}{9}x^{-2/3}\). So, the arc length integral becomes \(\int_{1}^{8} \sqrt{1 + \frac{4}{9}x^{-2/3}} \, dx\).
03

Simplify the Integral Expression

To simplify \(\sqrt{1 + \frac{4}{9}x^{-2/3}}\), factor out \(\frac{1}{9}x^{-2/3}\) from the expression under the square root: \(\sqrt{1 + \frac{4}{9}x^{-2/3}} = \sqrt{\frac{9x^{2/3} + 4}{9x^{2/3}}} = \frac{\sqrt{9x^{2/3} + 4}}{3x^{1/3}}\).
04

Calculate the Definite Integral

Now the integral becomes \[ \int_{1}^{8} \frac{\sqrt{9x^{2/3} + 4}}{3x^{1/3}} \, dx. \] This integral can be simplified by further substitution or recognized patterns, and with a suitable substitution, calculate the definite integral using techniques such as a trigonometric or hyperbolic substitution if needed.
05

Evaluate the Integral from 1 to 8

Once the integral is in a solvable form, evaluate it from 1 to 8 by substituting these bounds into the antiderivative found in the previous step, ensuring proper simplification at each stage. This will require both algebraic manipulation and recognizing integration patterns.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calculus Integration
Calculus integration is a fundamental tool used to find accumulated quantities, such as areas under curves and the lengths of curves themselves. The concept of integration involves adding up infinitesimally small quantities over a continuous range. This is especially useful in calculating the arc length of a curve, which can be thought of as a series of tiny straight line segments stretched along the curve.

When finding the arc length of a curve defined by a function like \(y = x^{2/3}\) from \(x = a\) to \(x = b\), a specific formula is used:
  • \( L = \int_{a}^{b} \sqrt{1 + \left(\frac{dy}{dx}\right)^2} \, dx \)
  • This formula calculates the total length by considering both the horizontal and vertical changes along the curve.
This integration problem can be simplified by substituting a previously calculated derivative into the arc length formula, followed by simplifying the integrand before solving.
Understanding this concept requires practice in integrating different forms of functions, often needing techniques like substitution or pattern recognition to simplify the expression to a solvable form.
Power Rule for Differentiation
The power rule is one of the most straightforward differentiation techniques in calculus. It allows us to find the derivative of terms in the form of \(x^n\), where \ is any real number. The rule states that the derivative of \(x^n\) is given by \(nx^{n-1}\).

In our exercise, we applied the power rule to find the derivative of \(y = x^{2/3}\). Following the power rule:
  • Derivative: \((2/3)x^{-1/3}\)
  • The exponent \((2/3)\) drops down, and we subtract one from the original exponent resulting in \(-1/3\).
By finding the derivative using the power rule, we provide the necessary component for the arc length formula. This step requires precision as errors in differentiation will propagate, affecting subsequent calculations.
Differentiation is crucial here as it reflects the dynamic changes in the curve, which directly impact the arc length calculation.
Definite Integral Evaluation
Evaluating a definite integral involves calculating the accumulated value of a function between specified limits. It's a two-step process: first, find the antiderivative of the integrand, and then apply the limits to obtain a numerical result.

In our task, the integral is \(\int_{1}^{8} \frac{\sqrt{9x^{2/3} + 4}}{3x^{1/3}} \, dx\). To evaluate this integral:
  • Simplify the integrand by substituting if necessary, which might involve finding a pattern or utilizing known identities.
  • Calculate the antiderivative, ensuring all steps are performed correctly.
  • Substitute the limits \((1, 8)\) into the antiderivative and take the difference to find the arc length.
This process often requires algebraic manipulation and a deep understanding of how substitution works in integration.
Ultimately, evaluating the definite integral provides a concrete answer to the problem, yielding the exact arc length of the curve from \(x = 1 \) to \ x = 8\.

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