Chapter 6: Problem 25
Find \(d y / d x\). $$y=\cosh ^{-1}(\cosh x)$$
Short Answer
Expert verified
\(\frac{dy}{dx} = \text{sgn}(x)\).
Step by step solution
01
Recall the Hyperbolic Identity
The inverse hyperbolic cosine function is defined such that \( ext{cosh}^{-1}( ext{cosh}(x)) = |x|\) for real numbers \(x\). This is because the range of \( ext{cosh}^{-1}\) is \([0, ext{infinity})\).
02
Evaluate Derivative for Different Cases
The function \(y = ext{cosh}^{-1}( ext{cosh}(x))\) can be simplified to \(|x|\). The derivative of \(y\) depends on whether \(x\) is positive or negative, which affects the absolute value function.
03
Compute Derivative when x >= 0
When \(x \geq 0\), \(|x| = x\), so \(y = x\). Thus, \(\frac{dy}{dx} = 1.\)
04
Compute Derivative when x < 0
When \(x < 0\), \(|x| = -x\), so \(y = -x\). Thus, \(\frac{dy}{dx} = -1.\)
05
Combine Results
Therefore, the derivative \(\frac{dy}{dx}\) is piecewise defined: \(\frac{dy}{dx} = 1\) when \(x \geq 0\) and \(\frac{dy}{dx} = -1\) when \(x < 0\). This can also be expressed using the sign function: \(\frac{dy}{dx} = \text{sgn}(x).\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Hyperbolic Functions
Hyperbolic functions are analogs of trigonometric functions but for a hyperbola, as opposed to a circle. Among them, the cosh function, or hyperbolic cosine function, is significant. It is defined as
- \( \cosh(x) = \frac{e^x + e^{-x}}{2} \).
- [0, \(\infty\)], for which it always yields non-negative values.
Absolute Value Function
The absolute value function is a fundamental mathematical concept represented as \( |x| \). It returns the non-negative value of \( x \) regardless of whether \( x \) is positive or negative. In simpler terms, it measures how far \( x \) is from zero on a number line.
There is a straightforward definition for the absolute value:
In terms of differentiation, the absolute value function poses a unique challenge but is manageable once you utilize its piecewise nature. For \( y = |x| \):
There is a straightforward definition for the absolute value:
- If \( x \geq 0 \), then \(|x| = x \).
- If \( x < 0 \), then \(|x| = -x \).
In terms of differentiation, the absolute value function poses a unique challenge but is manageable once you utilize its piecewise nature. For \( y = |x| \):
- \( \frac{dy}{dx} = 1 \) when \( x \geq 0 \), because the graph is increasing directly.
- \( \frac{dy}{dx} = -1 \) when \( x < 0 \), since the graph decreases as it approaches zero.
Piecewise Function
A piecewise function is made up of several sub-functions, each sub-function applies to a certain interval of the main function's domain. This is necessary when a function behaves differently based on the input value of \( x \).
In the exercise provided, the piecewise nature arises due to the presence of the absolute value function. As \( x \) shifts from being negative to non-negative, the function itself alters its form. This is where the definition splits as:
In the exercise provided, the piecewise nature arises due to the presence of the absolute value function. As \( x \) shifts from being negative to non-negative, the function itself alters its form. This is where the definition splits as:
- For \( x \geq 0 \), the function behaves as \( y = x \).
- For \( x < 0 \), the function becomes \( y = -x \).
- \( \frac{dy}{dx} = 1 \) when \( x \geq 0 \).
- \( \frac{dy}{dx} = -1 \) when \( x < 0 \).