/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 Find \(d y / d x\). $$y=\opera... [FREE SOLUTION] | 91Ó°ÊÓ

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Find \(d y / d x\). $$y=\operatorname{sech}\left(e^{2 x}\right)$$

Short Answer

Expert verified
\(-2e^{2x} \operatorname{sech}(e^{2x}) \tanh(e^{2x})\).

Step by step solution

01

Identify the Components

We need to identify the components in the function to apply the chain rule effectively. The function is \( y = \operatorname{sech}(u) \), where \( u = e^{2x} \).
02

Differentiate Outer Function

Differentiate the outer function \( \operatorname{sech}(u) \) with respect to \( u \). The derivative of \( \operatorname{sech}(u) \) is \( -\operatorname{sech}(u) \tanh(u) \).
03

Differentiate Inside Function

Differentiate the inside function \( u = e^{2x} \) with respect to \( x \). The derivative is obtained by first differentiating \( e^{2x} \) as \( 2e^{2x} \).
04

Apply the Chain Rule

Use the chain rule to find \( \frac{dy}{dx} \). Multiply the derivative of the outer function by the derivative of the inner function: \(-\operatorname{sech}(u) \tanh(u) \times 2e^{2x} \).
05

Substitute Back the Inner Function

Replace \( u \) with its expression in terms of \( x \): \(-\operatorname{sech}(e^{2x}) \tanh(e^{2x}) \times 2e^{2x} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
The Chain Rule is a fundamental tool in calculus for finding the derivative of composite functions. It is particularly useful when dealing with functions that are nested within each other, much like an "operation within an operation." To apply the chain rule, you differentiate the outer function with respect to the inner function, and then multiply by the derivative of the inner function with respect to the variable of interest. This is mathematically expressed as:
  • If you have a function composed like this: \(y = f(g(x))\), then the derivative \(\frac{dy}{dx}\) is \(f'(g(x)) \cdot g'(x)\).
In our given exercise, the function is \(y = \operatorname{sech}(u)\), and the inside function \(u\) is \(e^{2x}\). Applying the chain rule simplifies the process:
  • Differentiating \(\operatorname{sech}(u)\) gives us \(-\operatorname{sech}(u) \tanh(u)\).

  • Differentiating the inner function \(u = e^{2x}\) results in \(2e^{2x}\).
Finally, these derivatives are multiplied together according to the chain rule to find the derivative of the original function with respect to \(x\).
Exponential Functions
Exponential functions are a type of mathematical function where the variable appears in the exponent. These functions have the general form \(f(x) = a^{x}\), where \(a\) is a positive constant. One of the most common bases for exponential functions in calculus is \(e\), the natural exponential base approximately equal to 2.71828.
In calculus, differentiating exponential functions of the form \(e^{ax}\) is straightforward:
  • The derivative of \(e^{ax}\) is \(ae^{ax}\).

In the exercise at hand, our inside function is an exponential function, specifically: \(u = e^{2x}\). Differentiating this gives us \(2e^{2x}\), which represents how quickly the exponential function changes with respect to \(x\). These derivatives play an important role when applying the chain rule.
Hyperbolic Functions
Hyperbolic functions are analogs of the more familiar trigonometric functions but relate to the hyperbola in a geometric sense. Among these functions, the hyperbolic secant, denoted as \(\operatorname{sech}(x)\), is defined as the reciprocal of the hyperbolic cosine: \(\operatorname{sech}(x) = \frac{2}{e^x + e^{-x}}\).
The derivatives of hyperbolic functions can be derived similarly to their trigonometric counterparts. For \(\operatorname{sech}(x)\), the derivative is:
  • \(-\operatorname{sech}(x) \tanh(x)\)

In our example, the function to differentiate is \(y = \operatorname{sech}(e^{2x})\). Applying the chain rule required finding this derivative and using it as part of the composite differentiation process. Hyperbolic functions, though similar to trigonometric functions in form, often lead to distinct but surprisingly parallel results in calculus.

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Most popular questions from this chapter

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