/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 71 (a) Let $$I=\int_{0}^{a} \frac... [FREE SOLUTION] | 91Ó°ÊÓ

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(a) Let $$I=\int_{0}^{a} \frac{f(x)}{f(x)+f(a-x)} d x$$ Show that \(I=a / 2\) [Hint: Let \(u=a-x,\) and then note the difference between the resulting integrand and \(1 .\) (b) Use the result of part (a) to find $$\int_{0}^{3} \frac{\sqrt{x}}{\sqrt{x}+\sqrt{3-x}} d x$$ (c) Use the result of part (a) to find $$\int_{0}^{\pi / 2} \frac{\sin x}{\sin x+\cos x} d x$$]

Short Answer

Expert verified
(a) \( I = \frac{a}{2} \); (b) \( \frac{3}{2} \); (c) \( \frac{\pi}{4} \).

Step by step solution

01

Change of Variables

Let \( I = \int_{0}^{a} \frac{f(x)}{f(x)+f(a-x)} \, dx \). We perform a change of variable by letting \( u = a - x \). This implies that \( du = -dx \), so when \( x = 0, u = a \) and when \( x = a, u = 0 \). The limits of integration are reversed, thus:\[ I = \int_{a}^{0} \frac{f(a-u)}{f(a-u) + f(u)} (-du) = \int_{0}^{a} \frac{f(a-u)}{f(a-u) + f(u)} \, du. \]
02

Simplify Expression

From the above, we have two expressions for \(I\):\[ I = \int_{0}^{a} \frac{f(x)}{f(x) + f(a-x)} \, dx \]and\[ I = \int_{0}^{a} \frac{f(a-u)}{f(a-u) + f(u)} \, du. \]Adding these two expressions gives:\[ 2I = \int_{0}^{a} \left( \frac{f(x)}{f(x) + f(a-x)} + \frac{f(a-x)}{f(a-x) + f(x)} \right) \] dx. Notice the integrand becomes 1:\[ \frac{f(x) + f(a-x)}{f(x) + f(a-x)} = 1. \] Hence,\[ 2I = \int_{0}^{a} 1 \, dx = a. \]So, \( I = \frac{a}{2} \).
03

Apply the Result from Part (a) to Part (b)

To solve \( \int_{0}^{3} \frac{\sqrt{x}}{\sqrt{x}+\sqrt{3-x}} \, dx \), identify \( f(x) = \sqrt{x} \) which fits the criteria given in Part (a) with \( a = 3 \). Thus, the integral evaluates to \( \frac{3}{2} \).
04

Apply the Result from Part (a) to Part (c)

For \( \int_{0}^{\pi/2} \frac{\sin x}{\sin x + \cos x} \, dx \), identify \( f(x) = \sin(x) \) and \( f(\pi/2 - x) = \cos(x) \). Applying the result from Part (a) with \( a = \pi/2 \), the integral evaluates to \( \frac{\pi}{4} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Definite Integrals
Definite integrals are a fundamental concept in calculus that provide a way to calculate the accumulated quantities, such as areas under curves or total distances traveled. Unlike indefinite integrals, which result in a family of functions, definite integrals result in a specific numerical value.The notation for a definite integral is often \[\int_{a}^{b} f(x) \; dx,\] where \(a\) and \(b\) are the limits of integration, and \(f(x)\) is the integrand. Here, \(a\) is the lower limit, and \(b\) is the upper limit. When evaluating a definite integral:
  • First, find the antiderivative of the integrand.
  • Then, apply the limits of integration by calculating the difference between the evaluation of the antiderivative at the upper and lower limits: \[F(b) - F(a).\]
This exercise demonstrates the use of definite integrals by manipulating an integral into a simpler form through symmetry and change of variables, leading to straightforward evaluation.
Change of Variables
The technique known as "change of variables" or "substitution" is a powerful tool in calculus used to simplify integration. By transforming the original variable to a new one, the integration process can become more manageable. This is particularly useful when the integral's function or limits make it difficult to evaluate directly.For example, in the exercise, we perform a change of variable by letting \( u = a - x \). This substitution changes the integrand's form and reverses the limits of integration. The steps involved in using substitution include:
  • Selecting a new variable, \( u \), to simplify the integrand.
  • Calculating \( du \) by differentiating the substitution equation, typically leading to \( du = -dx \) or other forms based on the relationship.
  • Applying the new limits when \( x \) is replaced by \( u \).
In this exercise, substituting \( u = a - x \) helped show that adding two different forms of the integral results in a simpler expression, ultimately allowing for the integration to yield a conceptually and computationally easier result.
Trigonometric Integrals
Trigonometric integrals involve integration of functions that include trigonometric functions like sine, cosine, or tangent. These integrals often require specific techniques, such as trigonometric identities, substitutions, or symmetry, to simplify them.In this exercise, a specific trigonometric integral is explored:\[ \int_{0}^{\pi / 2} \frac{\sin x}{\sin x + \cos x} \, dx. \]The integral takes advantage of the symmetry of sine and cosine around \( \pi/4 \) to simplify the integration process. By recognizing \( f(x) = \sin(x) \) and \( f(\pi/2 - x) = \cos(x) \), the problem can be framed similarly to the general form discussed in the first part of this assessment.Here, the properties of trigonometric functions – particularly their behavior over specified intervals –
  • Symmetry and periodicity play crucial roles in simplifying the integral.
  • Recognizing relationships between the integrand's components aids in transforming and evaluating expressions efficiently.
Ultimately, these insights allow for employing previously obtained results to swiftly compute the trigonometric integral, showcasing the power of strategic mathematical analysis and symmetry.

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Most popular questions from this chapter

Sketch the curve and find the total area between the curve and the given interval on the \(x\) -axis. $$y=\frac{x^{2}-1}{x^{2}} ;\left[\frac{1}{2}, 2\right]$$

A traffic engineer monitors the rate at which cars enter the main highway during the afternoon rush hour. From her data she estimates that between 4: 30 PM. and 5: 30 P.M. the rate \(R(t)\) at which cars enter the highway is given by the formula \(R(t)=100\left(1-0.0001 t^{2}\right)\) cars per minute, where \(t\) is the time (in minutes) since 4: 30 PM. (a) When does the peak traffic flow into the highway occur? (b) Estimate the number of cars that enter the highway during the rush hour.

(a) Show that the area under the graph of \(y=x^{3}\) and over the interval \([0, b]\) is \(b^{4} / 4\) (b) Find a formula for the area under \(y=x^{3}\) over the interval \([a, b],\) where \(a \geq 0\)

(a) Over what open interval does the formula $$ F(x)=\int_{0}^{x} \sec t d t $$ represent an antiderivative of \(f(x)=\sec x ?\) (b) Find a point where the graph of \(F\) crosses the \(x\) -axis.

(a) If \(h^{\prime}(t)\) is the rate of change of a child's height measured in inches per year, what does the integral \(\int_{0}^{10} h^{\prime}(t) d t\) represent, and what are its units? (b) If \(r^{\prime}(t)\) is the rate of change of the radius of a spherical balloon measured in centimeters per second, what does the integral \(\int_{1}^{2} r^{\prime}(t) d t\) represent, and what are its units? (c) If \(H(t)\) is the rate of change of the speed of sound with respect to temperature measured in \(\mathrm{ft} / \mathrm{s}\) per "F. what does the integral \(\int_{32}^{100} H(t) d t\) represent. and what are its units? (d) If \(v(t)\) is the velocity of a particle in rectilinear motion, measured in \(\mathrm{cm} / \mathrm{h}\), what does the integral \(\int_{t_{1}}^{t_{2}} v(t) d t\) represent, and what are its units?

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