Chapter 5: Problem 47
Find a function \(f\) and a number \(a\) such that $$ 4+\int_{a}^{x} f(t) d t=e^{2 x} $$
Short Answer
Expert verified
The function is \( f(x) = 2e^{2x} \) and \( a = \frac{\ln(4)}{2} \).
Step by step solution
01
Identify the Relationship
We are given an equation: \( 4 + \int_{a}^{x} f(t) \, dt = e^{2x} \). This equation suggests that the integral of \( f(t) \) from \( a \) to \( x \) plus 4 gives us the expression \( e^{2x} \).
02
Differentiate Both Sides
To find the function \( f \), differentiate both sides of the equation with respect to \( x \). On the left side, using the Fundamental Theorem of Calculus, \( \frac{d}{dx} \int_{a}^{x} f(t) \, dt = f(x) \). Thus, we differentiate: \[ \frac{d}{dx} \left( 4 + \int_{a}^{x} f(t) \, dt \right) = \frac{d}{dx} e^{2x} \]This gives us:\[ f(x) = \frac{d}{dx} e^{2x} = 2 e^{2x} \]
03
Solve for Constant \( a \)
Next, solve for \( a \) using the condition that the integral plus 4 equals \( e^{2x} \). Evaluate the equation at \( x = a \):\[ 4 + \int_{a}^{a} f(t) \, dt = e^{2a} \]Since \( \int_{a}^{a} f(t) \, dt = 0 \), we have:\[ 4 = e^{2a} \]Solving for \( a \):\[ e^{2a} = 4 \]Take the natural logarithm of both sides:\[ 2a = \ln(4) \]\[ a = \frac{\ln(4)}{2} \]
04
Confirm the Solution
Check that the calculated values satisfy the original equation. When you substitute \( f(x) = 2e^{2x} \) and \( a = \frac{\ln(4)}{2} \) back into the original equation, both sides should remain equal for any \( x \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Differentiation
Differentiation is a key concept in calculus that involves finding the derivative of a function. It measures how a function changes as its input changes. In this context, differentiation helps us determine the function \( f(x) \) given the equation \( 4 + \int_{a}^{x} f(t) \, dt = e^{2x} \). By differentiating both sides of the equation with respect to \( x \), we use the Fundamental Theorem of Calculus which states that \( \frac{d}{dx} \int_{a}^{x} f(t) \, dt = f(x) \). This allows us to find \( f(x) \), the derivative of the given integral, which results in \( f(x) = 2e^{2x} \).Understanding differentiation:
- The process involves finding the slope or the rate of change of a function.
- For exponential functions like \( e^{2x} \), differentiation involves using the chain rule.
- The chain rule states that if you have a function inside another function, you differentiate the outer function and multiply it by the derivative of the inner function.
Definite Integral
A definite integral calculates the accumulation of quantities, such as areas under a curve, from one point to another. In our equation, \( \int_{a}^{x} f(t) \, dt \), we are integrating the function \( f(t) \) from the lower limit \( a \) to the upper limit \( x \).What does this mean and how do you solve it?- It represents the total accumulation of the function \( f(t) \) between these limits.- In our example, this sum, when added to the constant \( 4 \), equals \( e^{2x} \).- By setting \( x = a \), we evaluate the integral from \( a \) to \( a \), which equals zero.- This fact helps establish the constant \( 4 = e^{2a} \), leading to finding the value of \( a \).Thus, definite integrals play a vital role in linking the accumulation of a function with algebraic expressions.
Exponential Functions
Exponential functions are functions where the variable exponent is the independent variable. They have the form \( e^{u(x)} \), where \( e \) is approximately 2.71828, and \( u(x) \) is a function of \( x \).Understanding exponential functions in our example:
- Exponential functions exhibit rapid growth, which means small changes in \( x \) can lead to large changes in the value of the function.
- In our original equation \( 4 + \int_{a}^{x} f(t) \, dt = e^{2x} \), the right side, \( e^{2x} \), is an exponential function whose differentiation gives \( 2e^{2x} \).
- This differentiation reveals the underlying function \( f(x) = 2e^{2x} \), showing how the rate of change corresponds with the behavior of exponential growth.