Chapter 5: Problem 3
Express the integral in terms of the variable \(u\), but do not evaluate it. (a) \(\int_{0}^{1} e^{2 x-1} d x ; u=2 x-1\) (b) \(\int_{e}^{e^{2}} \frac{\ln x}{x} d x ; u=\ln x\)
Short Answer
Expert verified
(a) \(\frac{1}{2} \int_{-1}^{1} e^{u} \, du\); (b) \(\int_{1}^{2} u \, du\).
Step by step solution
01
Substitution for Part (a)
Identify the substitution for the integral \( \int_{0}^{1} e^{2x - 1} \, dx \) using \( u = 2x - 1 \). This implies that \( du = 2 \, dx \) or \( dx = \frac{1}{2} \, du \).
02
Change of Limits for Part (a)
Using the substitution \( u = 2x - 1 \), calculate the new limits of integration. When \( x = 0 \), \( u = 2(0) - 1 = -1 \). When \( x = 1 \), \( u = 2(1) - 1 = 1 \). Thus, the new limits are from \( -1 \) to \( 1 \).
03
Express the Integral in Terms of \( u \) for Part (a)
Substitute \( u = 2x - 1 \) and \( dx = \frac{1}{2} \, du \) into the integral: \[ \int_{-1}^{1} e^{u} \frac{1}{2} \, du = \frac{1}{2} \int_{-1}^{1} e^{u} \, du \].
04
Substitution for Part (b)
Identify the substitution for the integral \( \int_{e}^{e^2} \frac{\ln x}{x} \, dx \) using \( u = \ln x \). This implies that \( du = \frac{1}{x} \, dx \), so \( dx = x \, du \).
05
Change of Limits for Part (b)
Using the substitution \( u = \ln x \), calculate the new limits of integration. When \( x = e \), \( u = \ln(e) = 1 \). When \( x = e^2 \), \( u = \ln(e^2) = 2 \). Thus, the new limits are from \( 1 \) to \( 2 \).
06
Express the Integral in Terms of \( u \) for Part (b)
Substitute \( u = \ln x \) and \( dx = x \, du \) into the integral. Since \( x = e^u \), the integral becomes \[ \int_{1}^{2} u \, du \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Change of Variables
The change of variables, also known as substitution, is a crucial technique in integration. It simplifies a complex integral by converting it into a simpler form. The idea is to replace a variable with a new one, usually denoted as \( u \), which makes the integration process easier. Here's how it works.
- Identify a part of the integrand (the function being integrated) that can be substituted with a new variable \( u \).
- Express the new variable in terms of the original variable. For example, in part (a) of the exercise, \( u = 2x - 1 \).
- Determine \( dx \) in terms of \( du \) using the derivative of \( u \) with respect to \( x \). In our case, for part (a), this gives \( dx = \frac{1}{2} \, du \).
Definite Integrals
Definite integrals are used to calculate the exact area under a curve within specified bounds. They are expressed with specified upper and lower limits of integration.
- In the context of substitution, definite integrals require us to change the bounds of integration along with the variable.
- The integral notation \( \int_{a}^{b} f(x) \, dx \) represents integration of \( f(x) \) from \( x = a \) to \( x = b \).
- In the exercise, this is witnessed when transforming the original limits of integration from \( x = 0 \) to \( x = 1 \) into new limits as \( u = -1 \) to \( u = 1 \) in part (a).
Limits of Integration
When performing a change of variables in definite integrals, it's essential to accurately convert the limits of integration. These limits define the bounds over which the integral is calculated.
- The original limits of integration with respect to \( x \) must be converted to the corresponding limits in terms of \( u \).
- In our example, when \( x = 0 \), substitute into \( u = 2x - 1 \) to find the new lower limit; similarly, when \( x = 1 \), compute the new upper limit.
- In part (b), transforming \( x = e \) to \( u = \ln(e) = 1 \) and \( x = e^2 \) to \( u = \ln(e^2) = 2 \) exemplifies this conversion.