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The function \(s(t)\) describes the position of a particle moving along a coordinate line, where \(s\) is in meters and \(t\) is in seconds. (a) Make a table showing the position, velocity, and acceleration to two decimal places at times \(t=1,2,3,4,5\) (b) At each of the times in part (a), determine whether the particle is stopped; if it is not, state its direction of motion. (c) At each of the times in part (a), determine whether the particle is speeding up, slowing down, or neither. $$s(t)=\sin \frac{\pi t}{4}$$

Short Answer

Expert verified
Calculate position, velocity, and acceleration for each time. Determine stop state and motion direction. Identify if speeding up or slowing down.

Step by step solution

01

Calculate Position at Given Times

Use the formula given for the position, \( s(t) = \sin \left( \frac{\pi t}{4} \right) \), to compute the position of the particle at \( t = 1, 2, 3, 4, 5 \). Calculate each and round to two decimal places.
02

Derive Velocity Function

The velocity \( v(t) \) is the derivative of the position function \( s(t) \). Compute the derivative: \[ v(t) = \frac{d}{dt}\left( \sin \frac{\pi t}{4} \right) = \cos \left( \frac{\pi t}{4} \right) \cdot \frac{\pi}{4} \] which simplifies to: \[ v(t) = \frac{\pi}{4} \cos \left( \frac{\pi t}{4} \right) \].
03

Calculate Velocity at Given Times

Use the derived velocity function \( v(t) = \frac{\pi}{4} \cos \left( \frac{\pi t}{4} \right) \) to compute the velocity at \( t = 1, 2, 3, 4, 5 \). Calculate each and round to two decimal places.
04

Derive Acceleration Function

The acceleration \( a(t) \) is the derivative of the velocity function \( v(t) \). Compute \[ a(t) = \frac{d}{dt} \left( \frac{\pi}{4} \cos \left( \frac{\pi t}{4} \right) \right) = -\frac{\pi^2}{16} \sin \left( \frac{\pi t}{4} \right) \].
05

Calculate Acceleration at Given Times

Using the derived acceleration function \( a(t) = -\frac{\pi^2}{16} \sin \left( \frac{\pi t}{4} \right) \), compute the acceleration at \( t = 1, 2, 3, 4, 5 \). Calculate each and round to two decimal places.
06

Analyze Velocity to Determine if the Particle is Stopped

A particle is considered stopped when its velocity \( v(t) = 0 \). Check the velocity values calculated in Step 3 to see if they are equal to zero at any of the given times. If \( v(t) eq 0 \), determine the direction based on the sign of \( v(t) \):- Positive \( v(t) \) indicates motion to the right.- Negative \( v(t) \) indicates motion to the left.
07

Analyze Speeding Up or Slowing Down

The particle speeds up when the signs of velocity and acceleration are the same, and slows down when the signs are opposite. Compare the sign of \( v(t) \) from Step 3 and \( a(t) \) from Step 5 at each time to determine if the particle is speeding up, slowing down, or neither.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative
The derivative is a core concept in calculus used to determine the rate at which a function changes. In the context of a moving particle along a coordinate line, the function \( s(t) \) represents the position, and its derivative \( v(t) \) represents the velocity. The velocity is essentially the rate of change of position over time, and it tells us how fast and in which direction the particle is moving.

To find the velocity, you compute the derivative of the position function:\[ v(t) = \frac{d}{dt}\left( \sin \frac{\pi t}{4} \right) = \cos \left( \frac{\pi t}{4} \right) \cdot \frac{\pi}{4} \].

This provides a new function, \( v(t) = \frac{\pi}{4} \cos \left( \frac{\pi t}{4} \right) \), which can be evaluated to find the velocity at any given time \( t \). Calculating this at specific points gives insight into how fast the particle is moving at those times.
Trigonometric functions
Trigonometric functions like sine and cosine are fundamental in describing periodic or oscillating phenomena such as the movement of a particle in certain contexts.

In this exercise, the function \( s(t) = \sin \frac{\pi t}{4} \) models the position of a particle over time. The use of sine implies that the particle's position follows a smooth, wave-like path that repeats over intervals. This is characteristic of trigonometric functions, allowing for modeling scenarios where movement is cyclical.

Understanding these functions is key, as they help describe not only the position but also how fast (velocity) and how acceleratively (acceleration) the particle is moving at any point. The cyclical nature of sine and cosine functions means that there will be points where their values (hence the positions and velocities derived from them) reach maximum, minimum, or zero values as time progresses.
Particle motion analysis
Particle motion analysis involves examining the behavior of a moving particle by assessing its position, velocity, and acceleration over time. This entails understanding the relationship between these quantities, all of which are derivatives of each other.

Analyzing whether a particle is stopped or moving involves checking its velocity, \( v(t) \). When \( v(t) = 0 \), the particle is stationary. The direction of motion is indicated by the sign of \( v(t) \): a positive sign indicates movement in one direction, while a negative sign indicates the opposite.
  • Positive velocity: Particle is moving to the right.
  • Negative velocity: Particle is moving to the left.
Beyond just movement, we consider acceleration \( a(t) \) to determine if the particle is speeding up or slowing down. This is done by comparing signs of velocity and acceleration:
  • If \( v(t) \) and \( a(t) \) share the same sign, the particle speeds up.
  • If they have opposite signs, the particle slows down.
Knowing these aspects is vital for fully understanding the particle's trajectory and its variations throughout the designated time intervals.

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