/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Find \(f^{\prime}(x)\). $$f(x)... [FREE SOLUTION] | 91Ó°ÊÓ

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Find \(f^{\prime}(x)\). $$f(x)=-4 x^{2} \cos x$$

Short Answer

Expert verified
The derivative is \(-8x \cos x + 4x^2 \sin x\).

Step by step solution

01

Identify the function and its form

The function given is \(f(x) = -4x^2 \cos x\). Recognize that it is a product of two functions: \(u(x) = -4x^2\) and \(v(x) = \cos x\).
02

Apply the product rule

To differentiate a product \(u(x)v(x)\), use the product rule: \( (uv)' = u'v + uv' \). For our problem, substitute \(u(x) = -4x^2\) and \(v(x) = \cos x\).
03

Differentiate \(u(x) = -4x^2\)

Find the derivative of \(u(x) = -4x^2\). Using the power rule, \(u'(x) = \frac{d}{dx}(-4x^2) = -8x\).
04

Differentiate \(v(x) = \cos x\)

Find the derivative of \(v(x) = \cos x\). The derivative is \(v'(x) = -\sin x\) because the derivative of \(\cos x\) is \(-\sin x\).
05

Apply the product rule to find \(f'(x)\)

Substitute \(u(x)\), \(u'(x)\), \(v(x)\), and \(v'(x)\) into the product rule formula: \[ f'(x) = u'(x)v(x) + u(x)v'(x) = (-8x)(\cos x) + (-4x^2)(-\sin x) \]
06

Simplify the expression for \(f'(x)\)

Simplify the expression obtained in Step 5: \[ f'(x) = -8x \cos x + 4x^2 \sin x \] This is the derivative of the function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Derivative Calculation
The process of finding the derivative of a function is known as differentiation. In essence, this is a way to find the rate at which a quantity changes with respect to another. In mathematical terms, the derivative of a function, represented as \(f'(x)\), gives us the slope of the tangent line to the function at any point \(x\).

In our example, we needed to find the derivative of the function \(f(x) = -4x^2 \cos x\). The given function is the product of two functions, \( u(x) = -4x^2 \) and \( v(x) = \cos x \). To tackle this, we need a technique that works well with products of functions, which is precisely what the product rule provides.
Applying the Power Rule
The power rule is a fundamental tool in calculus used to easily find the derivative of a function in the form \( ax^n \). This rule states that if \( f(x) = x^n \), then \( f'(x) = nx^{n-1} \). For a function multiplied by a constant, such as \( ax^n \), the derivative is simply \( f'(x) = nax^{n-1} \).

In this particular exercise, the derivative of \( u(x) = -4x^2 \) is calculated using the power rule. By applying the rule, we take the exponent of \( x \) (which is 2), multiply it with the coefficient \(-4\), resulting in \(-8\), and subtract 1 from the exponent to get \( x^{1} \). Therefore, \( u'(x) = -8x \).
  • Power rule helps in easily finding derivatives of polynomial functions.
  • The rule simplifies the process of differentiation by providing a quick formula.
Differentiating Trigonometric Functions
Trigonometric functions such as sine and cosine are common in calculus, and their derivatives are important to understand. These derivatives derive from the basic definitions of the functions on the unit circle.

For example, the derivative of \( \cos x \) is \( -\sin x \). This result can be interpreted as the slope of the cosine wave at any given point \( x \). Differentiating trigonometric functions involves understanding their cyclic and oscillatory nature.
  • \( \cos x \) derivative is \( -\sin x \), while \( \sin x \) derivative is \( \cos x \).
  • The negative sign for \( \cos x \)'s derivative reflects the fact that its slope is negative whenever cos decreases.
In the exercise discussed, we used the derivative of \( \cos x \) in combination with the product rule to differentiate the product \( -4x^2 \cos x \). Recognizing and applying these derivatives is key to solving such problems efficiently.

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Most popular questions from this chapter

A paint manufacturing company estimates that it can sell \(g=f(p)\) gallons of paint at a price of \(p\) dollars per gallon. (a) What are the units of \(d g / d p ?\) (b) In practical terms, what does \(d g / d p\) mean in this case? (c) What can you say about the sign of \(d g / d p ?\) (d) Given that \(d g /\left.d p\right|_{p=10}=-100,\) what can you say about the effect of increasing the price from \(\$ 10\) per gallon to \(\$ 11\) per gallon?

A robot moves in the positive direction along a straight line so that after \(t\) minutes its distance is \(s=6 t^{4}\) feet from the origin. (a) Find the average velocity of the robot over the interval [2,4]. (b) Find the instantaneous velocity at \(t=2.\)

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Show that \(f(x)\) is continuous but not differentiable at the indicated point. Sketch the graph of \(f\) (a) \(f(x)=\sqrt[3]{x}, x=0\) (b) \(f(x)=\sqrt[3]{(x-2)^{2}}, x=2\)

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