/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 Use a graphing utility to estima... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use a graphing utility to estimate the value of \(f^{\prime}(1)\) by zooming in on the graph of \(f\), and then compare your estimate to the exact value obtained by differentiating. $$f(x)=\frac{x}{x^{2}+1}$$

Short Answer

Expert verified
The estimated value of \(f'(1)\) is approximately 0.2, and the exact value obtained through differentiation is 0.2. Hence, the estimates match.

Step by step solution

01

Graph the Function

Use a graphing utility to plot the function \( f(x) = \frac{x}{x^2+1} \). Begin by observing the behavior of the curve around the point \( x = 1 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Utilities
Graphing utilities are powerful tools for visualizing mathematical functions. They help students and professionals alike to understand complex equations by offering a visual representation. These tools can plot functions, show trends, and provide insights about the behavior of functions at specific points.
If you consider the function given by the exercise, which is \(f(x) = \frac{x}{x^2 + 1}\), using a graphing utility like Desmos or a graphing calculator can tremendously aid in understanding its characteristics.
  • First, input the function into the utility.
  • Then, observe how the graph behaves, especially around the point \(x = 1\).
  • This step helps visualize where the function increases or decreases and how sharply.
Graphing utilities not only simplify the process of plotting functions but also provide detailed visuals when zooming in and out. This is particularly useful when you need to estimate derivatives by closely examining the curve.
Estimating Derivatives
Estimating derivatives involves approximating the slope of a tangent line to a curve at a particular point. By using graphing utilities, you can focus on the region around that specific point.
The process begins by gradually zooming in on the point of interest, which, in this case, is \(x = 1\) on the graph of \(f(x) = \frac{x}{x^2 + 1}\). As we get closer and closer to the curve, it tends to appear more linear.
Here's how you can estimate the derivative:
  • Identify two very close points on the function near \(x = 1\).
  • Calculate the difference in \(y\)-values (output of the function) between these points.
  • Divide this difference by the difference in \(x\)-values (input of the function).
This provides an approximation of the derivative, \(f'(x)\), at \(x = 1\). As we zoom further, the estimated slope should get closer to the true derivative as determined by calculus.
Derivative at a Point
The derivative of a function at a particular point signifies the instantaneous rate of change or the slope of the tangent line at that specific point. To find this exactly for \(f(x) = \frac{x}{x^2 + 1}\) at \(x = 1\), we use differentiation.
The exact derivative \(f'(x)\) can be computed by applying differentiation rules, such as the quotient rule. For the function parting into quotient form, use:
  • The quotient rule: If \(h(x) = \frac{u(x)}{v(x)}\), then \(h'(x) = \frac{u'(x)v(x) - u(x)v'(x)}{v(x)^2}\).
For \(f(x) = \frac{x}{x^2 + 1}\), substitute:
  • \(u(x) = x\) and \(v(x) = x^2 + 1\).
  • Differentiating these separately gives \(u'(x) = 1\) and \(v'(x) = 2x\).
  • Plug them into the quotient rule formula to obtain \(f'(x)\).
Finally, substitute \(x = 1\) into the derived function \(f'(x)\) to get the exact derivative at \(x = 1\). This exact value can then be compared with the estimated value from graphing utilities to check accuracy.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find an equation for the tangent line to the graph at the specified value of \(x\) $$y=\frac{x}{\sqrt{1-x^{2}}}, x=0$$

A function \(y=f(x)\) and an \(x\) -value \(x_{0}\) are given. (a) Find a formula for the slope of the tangent line to the graph of \(f\) at a general point \(x=x_{0}\). (b) Use the formula obtained in part (a) to find the slope of the tangent line for the given value of \(x_{0}\). $$f(x)=x+\sqrt{x} ; x_{0}=1$$

True-False Determine whether the statement is true or false. Explain your answer. A 50 -foot horizontal metal beam is supported on either end by concrete pillars and a weight is placed on the middle of the beam. If \(f(x)\) models how many inches the center of the beam sags when the weight measures \(x\) tons, then the units of the rate of change of \(y=f(x)\) with respect to \(x\) are inches/ton.

If a particle moves at constant velocity, what can you say about its position versus time curve?

You are asked in these exercises to determine whether a piecewise-defined function \(f\) is differentiable at a value \(x=x_{0}\) where \(f\) is defined by different formulas on different sides of \(x_{0}\). You may use without proof the following result, which is a consequence of the Mean-Value Theorem (discussed in Section 4.8 ). Theorem. Let \(f\) be continuous at \(x_{0}\) and suppose that \(\lim _{x \rightarrow x_{0}} f^{\prime}(x)\) exists. Then \(f\) is differentiable at \(x_{0}\) and \(f^{\prime}\left(x_{0}\right)=\lim _{x \rightarrow \infty} f^{\prime}(x)\) Let $$ f(x)=\left\\{\begin{array}{ll} x^{3}+\frac{1}{16}, & x<\frac{1}{2} \\ \frac{2}{4} x^{2}, & x \geq \frac{1}{2} \end{array}\right. $$ Determine whether \(f\) is differentiable at \(x=\frac{1}{2} .\) If so, find the value of the derivative there.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.