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Find \(f^{\prime}(x)\) $$f(x)=\frac{1}{\left(x^{5}-x+1\right)^{9}}$$

Short Answer

Expert verified
\(f'(x) = -9(5x^4 - 1)(x^5 - x + 1)^{-10}\)

Step by step solution

01

Identify the Differentiation Rule

The function given is \[ f(x) = \frac{1}{(x^5 - x + 1)^9} \]This can be rewritten as \[ f(x) = (x^5 - x + 1)^{-9} \]We need to use the chain rule for differentiation.
02

Apply the Chain Rule

The chain rule states that if you have a function \( y = u^n \), then \( y' = nu^{n-1} \cdot u' \). Here, \( u = x^5 - x + 1 \) and \( n = -9 \). First, apply the outer derivative:\[ \frac{d}{dx}[u^n] = n \cdot u^{n-1} \cdot u'\]Substitute \( u \) and \( n \):\[ -9 \cdot (x^5 - x + 1)^{-10} \]Multiply by the derivative of \( u \) (\( u' \)).
03

Find the Inner Derivative

Calculate \( u' \) for \( u = x^5 - x + 1 \):\[ \frac{d}{dx}(x^5 - x + 1) = 5x^4 - 1 \]
04

Combine Results

Combine the results from Steps 2 and 3:\[ f'(x) = -9 imes (x^5 - x + 1)^{-10} imes (5x^4 - 1)\]This can be simplified to:\[ f'(x) = -9(5x^4 - 1)(x^5 - x + 1)^{-10} \]
05

Write the Final Answer

The derivative of the function \( f(x) = \frac{1}{(x^5 - x + 1)^{9}} \) is \[ f'(x) = -9(5x^4 - 1)(x^5 - x + 1)^{-10} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
The chain rule is a fundamental tool in calculus for finding the derivative of composite functions. These are functions that are formed by applying one function to the result of another function. In simpler terms, the chain rule helps you differentiate functions that are "nested," or within other functions.

For example, if you have a function like \[ f(x) = (x^5 - x + 1)^{-9} \], you're dealing with a composite because one function, say \( u(x) = x^5 - x + 1 \), is inside another function, \(u^n = u^{-9} \). The chain rule formula is:
  • \( y' = u' \, n \, u^{n-1} \)
Here, you first take the derivative of the outer function \(u^n\), assuming \(u\) is a constant, and then multiply it by the derivative of \(u\). This combination allows you to handle complex derivatives step by step.
Power Rule
The power rule is one of the simplest and most frequently used rules in differentiation. It applies to functions of the form \( x^n \), where \( n \) is any real number. According to the power rule, the derivative of \( x^n \) is \( n \cdot x^{n-1} \).

In the problem at hand, where the expression \((x^5 - x + 1)^{-9}\) is treated as the function \(u(x)^{-9}\), it simplifies the differentiation process.
  • The formula \( n\cdot u^{n-1} \) means you multiply \( u \) raised to the new power \( n-1 \) by the original power \( n \).
When dealing with functions like \(x^5 - x + 1\), apply the power rule by differentiating each term separately first.
Derivative Calculations
Derivative calculations involve identifying the appropriate rule or combination of rules to apply, simplifying terms, and computing the necessary derivatives. In this example, the derivative of \( f(x) = \frac{1}{(x^5 - x + 1)^9} \) was approached by first rewriting it in a form suitable for the chain and power rules.

Steps to calculating the derivative include:
  • Identifying composite functions to use the chain rule.
  • Applying the power rule to simplify derivatives of terms like \( x^n \).
  • Finding the derivative of the inner function, \( x^5 - x + 1 \), by treating each term separately, yielding \( 5x^4 - 1 \).
  • Combining these results using multiplication to complete the chain rule calculation.
The final result is a product of all these derivatives, simplified to provide a clean answer, \(-9(5x^4 - 1)(x^5 - x + 1)^{-10}\). Practice these steps regularly to become proficient in derivative calculations.

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Most popular questions from this chapter

Writing The "co" in "cosine" comes from "complementary," since the cosine of an angle is the sine of the complementary angle, and vice versa: $$ \cos x=\sin \left(\frac{\pi}{2}-x\right) \quad \text { and } \quad \sin x=\cos \left(\frac{\pi}{2}-x\right) $$ Suppose that we define a function \(g\) to be a cofunction of a function \(f\) if $$ g(x)=f\left(\frac{\pi}{2}-x\right) \quad \text { for all } x $$ Thus, cosine and sine are cofunctions of each other, as are cotangent and tangent, and also cosecant and secant. If \(g\) is the cofunction of \(f\), state a formula that relates \(g^{\prime}\) and the cofunction of \(f^{\prime}\), Discuss how this relationship is exhibited by the derivatives of the cosine, cotangent, and cosecant functions.

Given the following table of values, find the indicated derivatives in parts (a) and (b). $$\begin{array}{|c|c|c|} \hline x & f(x) & f^{\prime}(x) \\ \hline 2 & 1 & 7 \\\ \hline 8 & 5 & -3 \\ \hline \end{array}$$ (a) \(g^{\prime}(2),\) where \(g(x)=[f(x)]^{3}\) (b) \(h^{\prime}(2),\) where \(h(x)=f\left(x^{3}\right)\)

An automobile is driven down a straight highway such that after \(0 \leq t \leq 12\) seconds it is \(s=4.5 t^{2}\) feet from its initial position. (a) Find the average velocity of the car over the interval [0,12]. (b) Find the instantaneous velocity of the car at \(t=6.\)

A robot moves in the positive direction along a straight line so that after \(t\) minutes its distance is \(s=6 t^{4}\) feet from the origin. (a) Find the average velocity of the robot over the interval [2,4]. (b) Find the instantaneous velocity at \(t=2.\)

Find a formula for $$ \frac{d}{d x}[f(g(h(x)))] $$

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