/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 Find the area of the region desc... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the area of the region described. The region that is common to the circles \(r=2 \cos \theta\) and \(r=2 \sin \theta\)

Short Answer

Expert verified
The area common to both circles is \(\frac{\pi}{2} - 1\).

Step by step solution

01

Understand the Problem

We need to find the area that is common to the circles described by the polar equations \(r=2 \cos \theta\) and \(r=2 \sin \theta\). These are circles with diameters along the x-axis and y-axis, respectively. Our task is to find the overlapping area of these two circles.
02

Convert Equations to Cartesian Form

Convert the polar equations to Cartesian forms. The first equation \(r = 2\cos\theta\) converts to \(x^2 + y^2 = 2x\), and the second equation \(r = 2\sin\theta\) converts to \(x^2 + y^2 = 2y\). These represent circles centered at \((1,0)\) and \((0,1)\) respectively, both with radius 1.
03

Find Points of Intersection

Set the two equations equal to find the points of intersection. Solve \(2x = 2y\) to get \(x=y\). Substituting \(x=y\) into either equation gives \(x=1/2, y=1/2\). Thus, points of intersection in polar coordinates are \((1/\sqrt{2}, \pi/4)\) and \((1/\sqrt{2}, 5\pi/4)\).
04

Determine the Sector Area of Each Circle

Calculate the area of the sector for each circle that is part of the intersection. For circle \(r=2\cos\theta\), the sector goes from \(\theta = 0\) to \(\theta = \pi/2\). For circle \(r=2\sin\theta\), it is from \(\theta = \pi/2\) to \(\theta = \pi\). Use the formula for the area of a sector \(\text{Area} = \frac{1}{2} \int r^2 \, d\theta\) for each circle.
05

Compute Integral for Each Sector

Compute the integrals for each sector. For circle \(r=2\cos\theta\), compute \(\int_0^{\pi/4} (2\cos\theta)^2\,d\theta\). For the circle \(r=2\sin\theta\), compute \(\int_{\pi/4}^{\pi/2} (2\sin\theta)^2\,d\theta\).
06

Evaluate the Integrals

Evaluate the integrals computed in Step 5. - For the circle \(r=2\cos\theta\): \[ \int_0^{\pi/4} 4\cos^2\theta\,d\theta \]. - For the circle \(r=2\sin\theta\): \[ \int_{\pi/4}^{\pi/2} 4\sin^2\theta\,d\theta \].After evaluation, each integral covers half the area of a circle with radius 1, resulting in \(\frac{\pi}{4} - \frac{1}{2}\) for each.
07

Sum the Area Contributions

Add the areas calculated from both sectors to find the total common area. Since both integrals yield the same area of \(\frac{\pi}{4} - \frac{1}{2}\), and we have two such areas overlapping, the total area is \(\frac{\pi}{2} - 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Equations
Polar equations are a way to represent curves on a plane using the radius and angle from the origin. Unlike Cartesian coordinates, where the position is identified by x and y, polar coordinates use a radius (\(r\)) and an angle (\(\theta\)). In the context of circles, these equations offer a simplified way to express curves. For instance, the polar equations \(r=2\cos\theta\) and \(r=2\sin\theta\) describe circles. The first circle has its diameter along the x-axis, and the second on the y-axis.

When solving problems involving polar equations, it's necessary to understand the geometric nature they reveal. They tell us how far a point is from a central reference (the pole) and the direction in which the point lies. This makes polar equations particularly useful in problems dealing with circles and other cyclic forms in mathematics.

To find overlapping regions like the common area of circles in this exercise, analyzing the angles and radii in polar forms becomes essential. It can be helpful to graph these equations in a polar coordinate system for better visualization and understanding.
Cartesian Coordinates
Cartesian coordinates provide a method to describe the position of a point using two dimensions, \(x\) and \(y\). When converting from polar equations to Cartesian form, the relationships \(x = r\cos\theta\) and \(y = r\sin\theta\) are used. In this problem, the equations \(r = 2\cos\theta\) and \(r = 2\sin\theta\) are transformed to \(x^2 + y^2 = 2x\) and \(x^2 + y^2 = 2y\), respectively.

These transformations help identify the circle's centers and radii. The first circle, \(x^2 + y^2 = 2x\), centers at \((1, 0)\) with a radius of 1. The other, \(x^2 + y^2 = 2y\), centers at \((0, 1)\).

Understanding these conversions is crucial in solving the problem of finding the common area, as it allows you to work with the properties of circles that are more apparent in Cartesian format. It also provides the ability to find intersections and other key geometric relationships in a more algebraic sense.
Sector Area
The area of a sector is a portion of a circle, resembling a 'slice' defined by the central angle at the circle's center. It can be calculated using integrals, especially when dealing with polar coordinates. The formula for the area of a sector in polar coordinates is \[\text{Area} = \frac{1}{2} \int r^2 \, d\theta\]In this exercise, you compute the sector areas for each circle resulting from their respective sectors that form the common area.

For a better understanding, think of it as filling each 'slice' of the circle with small differential areas until the entire sector is covered. In the problem at hand, the sectors are bounded by polar angles \(\theta = 0\) to \(\theta = \pi/2\) and from \(\theta = \pi/2\) to \(\theta = \pi\), which define the overlapping regions.

Calculating sector areas accurately is vital when dealing with figures not entirely contained within one simple geometric shape. By adding up these sector areas from both circles, you can find the total common area. Understanding how to set the integration limits based on the problem is key to correctly determine these sector areas.

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