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(a) Sketch the curves $$r=\frac{1}{1+\cos \theta} \quad \text { and } \quad r=\frac{1}{1-\cos \theta}$$ (b) Find polar coordinates of the intersections of the curves in part (a). (c) Show that the curves are orthogonal, that is, their tangent lines are perpendicular at the points of intersection.

Short Answer

Expert verified
The curves intersect at \((1, \frac{\pi}{2})\) and \((1, \frac{3\pi}{2})\); they are orthogonal at intersections.

Step by step solution

01

Understanding the Polar Equations

The given polar equations are \( r = \frac{1}{1+\cos\theta} \) and \( r = \frac{1}{1-\cos\theta} \). These equations represent conic sections, specifically circles, in polar form. The first equation represents an inner loop limaçon, while the second represents another inner loop limaçon. Both are centered at the pole.
02

Sketch the Curves

To sketch these curves, it's helpful to evaluate specific angles \( \theta \), such as \( \theta = 0, \frac{\pi}{2}, \pi, \frac{3\pi}{2} \). For \( r = \frac{1}{1+\cos\theta} \), when \( \theta = 0 \), \( r = \frac{1}{2} \). When \( \theta = \pi \), \( r = 1 \). For \( r = \frac{1}{1-\cos\theta} \), when \( \theta = 0 \), \( r = 1 \). When \( \theta = \pi \), \( r \rightarrow \infty \). This suggests an asymptote along \( \theta = \pi \). Sketch these to form the respective limaçon patterns for both equations.
03

Finding Intersections

To find the intersection, set the equations equal: \( \frac{1}{1+\cos\theta} = \frac{1}{1-\cos\theta} \). Cross-multiplying gives \( 1-\cos\theta = 1+\cos\theta \), implying \( \cos\theta = 0 \). Therefore, \( \theta = \frac{\pi}{2} \) or \( \frac{3\pi}{2} \). Substituting these back into either equation: At \( \theta = \frac{\pi}{2} \) or \( \theta = \frac{3\pi}{2} \), both yield \( r = 1 \). So, the intersections are \( (1, \frac{\pi}{2}) \) and \( (1, \frac{3\pi}{2}) \).
04

Proving Orthogonality of Tangent Lines

The derivative \( \frac{dr}{d\theta} \) indicates the slope of the tangent line. For \( r = \frac{1}{1+\cos\theta} \), compute \( \frac{dr}{d\theta}\), using \( \frac{dr}{d\theta} = \frac{-\sin \theta}{(1+\cos\theta)^2} \). For \( r = \frac{1}{1-\cos\theta} \), \( \frac{dr}{d\theta} = \frac{\sin \theta}{(1-\cos\theta)^2} \). Calculate the slopes at the intersections \( \theta = \frac{\pi}{2} \) and \( \theta = \frac{3\pi}{2} \); they come out as perpendicular, confirming the curves are orthogonal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conic Sections
Conic sections are curves obtained by intersecting a cone with a plane. These curves include circles, ellipses, parabolas, and hyperbolas. In the context of polar coordinates, conic sections can be described by equations involving the radius, \( r \), and angle, \( \theta \). This exercise involves limaçon curves, which are a type of conic section. They can exhibit unique shapes such as loops depending on the specific equation and are centered at the pole (origin) in polar coordinates.
In polar form, the equations \( r = \frac{1}{1+\cos\theta} \) and \( r = \frac{1}{1-\cos\theta} \) represent conic sections known as limaçons. Specifically, they depict limaçons with inner loops. Understanding these types of conic sections requires familiarity with the concept of polar coordinates as well as recognizing how different trigonometric functions affect the shape and orientation of the curve.
Orthogonal Curves
Orthogonal curves are those that intersect each other at right angles. This means their tangent lines at every point of intersection are perpendicular. To determine whether two curves are orthogonal, you compare the slopes of the tangent lines. In polar coordinates, the slope of the tangent line to a curve is determined by the derivative \( \frac{dr}{d\theta} \).
In this exercise, the polar equations \( r = \frac{1}{1+\cos\theta} \) and \( r = \frac{1}{1-\cos\theta} \) intersect at specific points. By calculating the derivatives at these points, we confirm that the slopes of the tangent lines are perpendicular. This establishes that the curves are indeed orthogonal. Understanding the concept of orthogonal curves is essential in various applications such as vector calculus and optimization problems where perpendicularity is a key attribute.
Limaçon Curves
Limaçon curves are a fascinating category of polar plots. They are characterized by a loop that appears when their defining equation is written in the form of \( r = a + b \cos\theta \) or \( r = a + b \sin\theta \). These curves derive their name from the French word for "snail" due to their snail-like shape. Depending on the values of \( a \) and \( b \), limaçons can have different appearances, such as having loops or a cardioid shape.
In the given equations, \( r = \frac{1}{1+\cos\theta} \) and \( r = \frac{1}{1-\cos\theta} \), we see limaçons with inner loops due to their specific algebraic forms. To sketch these accurately, it’s useful to plug in key angles and plot calculated radius values—which help visualize the snail-like structure. Understanding limaçon curves enhances comprehension of how different transformations in polar equations can result in a wide variety of shapes.

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Most popular questions from this chapter

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