/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 Sketch the curve by eliminating ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Sketch the curve by eliminating the parameter, and indicate the direction of increasing \(t\) $$x=2 \sin ^{2} t, y=3 \cos ^{2} t \quad(0 \leq t \leq \pi / 2)$$

Short Answer

Expert verified
The curve is a line \( y = 3 - \frac{3}{2}x \) with direction from right to left as \( t \) increases.

Step by step solution

01

Use Trigonometric Identities

We start with the equations given: \( x = 2 \sin^2 t \) and \( y = 3 \cos^2 t \). Recall the trigonometric identity \( \sin^2 t + \cos^2 t = 1 \). Use this identity to express both \( \sin^2 t \) and \( \cos^2 t \).
02

Express in Terms of a Single Trigonometric Function

From the identity, express \( \cos^2 t \) in terms of \( \sin^2 t \): \( \cos^2 t = 1 - \sin^2 t \). Substitute \( \cos^2 t \) into the \( y \) equation to get \( y = 3(1 - \sin^2 t) = 3 - 3 \sin^2 t \).
03

Relate x and y

Substitute \( \sin^2 t = x/2 \) into the expression for \( y \). This gives \( y = 3 - 3(x/2) = 3 - \frac{3}{2}x \). Rearranging gives us the equation \( y = 3 - \frac{3}{2}x \), which describes a line.
04

Analyze the Direction

For direction, analyze the change with respect to \( t \). As \( t \) increases from \( 0 \) to \( \pi/2 \), \( \sin^2 t \) increases from 0 to 1, making \( x \) increase from 0 to 2. Meanwhile, \( \cos^2 t \) decreases, causing \( y \) to decrease from 3 to 0. Thus, the line is traversed from right to left as \( t \) increases.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Identities
In trigonometry, identities like \( \sin^2 t + \cos^2 t = 1 \) are foundational relationships that hold for all angles. Such identities are incredibly useful in converting and simplifying equations, especially when dealing with parametric equations. In the given exercise, knowing this identity allowed us to express \( \cos^2 t \) in terms of \( \sin^2 t \). This is critical because it helps us eliminate the parameter \( t \) from the equations by relating the expressions for \( x \) and \( y \) through the identity. By substituting \( \cos^2 t = 1 - \sin^2 t \) into the \( y \) equation, we gain a common ground to interconnect our expressions in a straightforward manner. This simplification is key for the elimination process, which we'll cover next.
Eliminating Parameters
The task of eliminating parameters in parametric equations involves expressing the relationship directly between the x and y variables, without referencing the parameter \( t \). This process often starts by using trigonometric identities to express one part of the equation in terms of another common element. In our exercise, by substituting \( \sin^2 t = x/2 \) into the equation for \( y \), we derive a direct relation: \( y = 3 - \frac{3}{2}x \). This transformation allows us to eliminate the parameter \( t \), unveiling the path of the curve in terms of \( x \) and \( y \) alone. This new equation represents a straight line, making further analysis and sketching much simpler and more intuitive.
Curve Sketching
Curve sketching involves understanding the behavior of a curve as influenced by the parameter \( t \). In our scenario, once we've related \( x \) and \( y \) directly through \( y = 3 - \frac{3}{2}x \), sketching becomes straightforward. It's key to note the direction of the curve as \( t \) changes. Here, as \( t \) moves from 0 to \( \pi/2 \), \( \sin^2 t \) increases, causing \( x \) to increase from 0 to 2 and \( y \) to decrease from 3 to 0. This indicates that the line is traversed from right to left. Noticing this direction is important since it informs us of how the curve evolves over the interval of \( t \). Such sketches help visualize the problem and enhance understanding of the overall transformation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the following values, where needed: $$\text { radius of the Earth }=4000 \mathrm{mi}=6440 \mathrm{km}$$ $$\text { 1 year (Earth year) =365 days (Earth days) }$$ $$1 \mathrm{AU}=92.9 \times 10^{6} \mathrm{mi}=150 \times 10^{6} \mathrm{km}$$ (a) Let \(a\) be the semimajor axis of a planet's orbit around the Sun, and let \(T\) be its period. Show that if \(T\) is measured in days and \(a\) is measured in kilometers, then \(T=\left(365 \times 10^{-9}\right)(a / 150)^{3 / 2}\). (b) Use the result in part (a) to find the period of the planet Mercury in days, given that its semimajor axis is \(a=57.95 \times 10^{6} \mathrm{km}\). (c) Choose a polar coordinate system with the Sun at the pole, and find an equation for the orbit of Mercury in that coordinate system given that the eccentricity of the orbit is \(e=0.206\) (d) Use a graphing utility to generate the orbit of Mercury from the equation obtained in part (c).

A line tangent to the hyperbola \(4 x^{2}-y^{2}=36\) intersects the \(y\) -axis at the point \((0,4) .\) Find the point(s) of tangency.

Use the following values, where needed: $$\text { radius of the Earth }=4000 \mathrm{mi}=6440 \mathrm{km}$$ $$\text { 1 year (Earth year) =365 days (Earth days) }$$ $$1 \mathrm{AU}=92.9 \times 10^{6} \mathrm{mi}=150 \times 10^{6} \mathrm{km}$$ The planet Jupiter is believed to have a rocky core of \(\mathrm{ra}-\) dius \(10,000 \mathrm{km}\) surrounded by two layers of hydrogen a \(40,000 \mathrm{km}\) thick layer of compressed metallic-like hydrogen and a \(20,000 \mathrm{km}\) thick layer of ordinary molecular hydrogen. The visible features, such as the Great Red Spot, are at the outer surface of the molecular hydrogen layer. On November 6,1997 the spacecraft Galileo was placed in a Jovian orbit to study the moon Europa. The orbit had eccentricity 0.814580 and semimajor axis \(3,514,918.9 \mathrm{km}\) Find Galileo's minimum and maximum heights above the molecular hydrogen layer (see the accompanying figure). Figure cannot copy

Find an equation for the ellipse that satisfies the given conditions. (a) Ends of major axis (0,±6)\(;\) passes through (-3,2) (b) Foci (-1,1) and (-1,3)\(;\) minor axis of length 4

Show that an ellipse with semi-major axis \(a\) and semi-minor axis \(b\) has area \(A=\pi a b\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.