/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 Given that \(\theta=\sec ^{-1} 2... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Given that \(\theta=\sec ^{-1} 2.6,\) find the exact values of \(\sin \theta\) \(\cos \theta, \tan \theta, \cot \theta,\) and \(\csc \theta\).

Short Answer

Expert verified
\(\cos \theta \approx 0.3846, \sin \theta \approx 0.922, \tan \theta \approx 2.398, \cot \theta \approx 0.417, \csc \theta \approx 1.084\).

Step by step solution

01

Understand the Angle Definition

We are given that \( \theta = \sec^{-1}(2.6) \). This means that the secant of \( \theta \) is 2.6. Therefore, \( \sec \theta = 2.6 \). Since secant is the reciprocal of cosine, we know that \( \cos \theta = \frac{1}{2.6} \).
02

Calculate \( \cos \theta \)

Using the reciprocal relation, calculate \( \cos \theta \) as follows: \( \cos \theta = \frac{1}{2.6} \approx 0.3846\).
03

Calculate \( \sin \theta \)

To find \( \sin \theta \), use the Pythagorean identity \( \sin^2 \theta = 1 - \cos^2 \theta \). First, calculate \( \cos^2 \theta = (0.3846)^2 \approx 0.1478 \). Then, \( \sin^2 \theta = 1 - 0.1478 \approx 0.8522 \). Thus, \( \sin \theta = \sqrt{0.8522} \approx 0.922 \).
04

Calculate \( \tan \theta \)

The tangent of \( \theta \) can be found using \( \tan \theta = \frac{\sin \theta}{\cos \theta} \). Substituting in the values: \( \tan \theta = \frac{0.922}{0.3846} \approx 2.398 \).
05

Calculate \( \cot \theta \)

\( \cot \theta \) is the reciprocal of \( \tan \theta \). Thus, \( \cot \theta = \frac{1}{2.398} \approx 0.417 \).
06

Calculate \( \csc \theta \)

\( \csc \theta \) is the reciprocal of \( \sin \theta \). Therefore, \( \csc \theta = \frac{1}{0.922} \approx 1.084 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Trigonometric Functions
Inverse trigonometric functions are used to obtain the angle from a known ratio of sides in a right triangle. These functions include the inverse sine (\(\sin^{-1}\)), inverse cosine (\(\cos^{-1}\)), inverse tangent (\(\tan^{-1}\)), among others. In trigonometry, these inverse functions serve the essential purpose of "undoing" the regular trigonometric functions, allowing us to solve for angles rather than side lengths.

For example, if we know that \(\theta = \sec^{-1}(2.6)\), it tells us that the secant of angle \(\theta\) is 2.6. Since secant is the reciprocal of the cosine function, \(\sec \theta = \frac{1}{\cos \theta}\), we can find \(\cos \theta\) through a simple reciprocal operation: \(\cos \theta = \frac{1}{2.6}\). This shows the beauty of inverse trigonometric functions in simplifying complex trigonometric relationships.

In practical applications, inverse trigonometric functions are crucial when working with angles in different quadrants and ensuring correct range outputs for calculations.
Pythagorean Identity
The Pythagorean identity is a fundamental relation in trigonometry, derived from the Pythagorean theorem. It states that for any angle \(\theta\):
  • \(\sin^2 \theta + \cos^2 \theta = 1\)
This identity is extremely helpful for finding one trigonometric ratio if the other is known. It essentially tells us that the square of sine plus the square of cosine is always equal to one. This relationship holds true regardless of the actual angle, provided it is within the valid range of angles.

For instance, in the given exercise, once \(\cos \theta = \frac{1}{2.6}\) is calculated, you can find \(\sin \theta\) by applying the Pythagorean identity. Calculating \(\cos^2 \theta\) first, and substituting it into the identity allows us to solve for \(\sin^2 \theta\) using \(1 - \cos^2 \theta\). The Pythagorean identity is a cornerstone of trigonometry that frequently appears in problems involving finding missing side ratios.
Reciprocal Functions
Reciprocal trigonometric functions are complementary functions to the primary sine, cosine, and tangent functions. These are the cosecant (\(\csc \theta\)), secant (\(\sec \theta\)), and cotangent (\(\cot \theta\)) functions.

Understanding these reciprocal relationships is vital, because they can simplify the manipulation and solving of trigonometric equations. Here's a quick guide to reciprocal functions:
  • The cosecant function is the reciprocal of the sine function: \(\csc \theta = \frac{1}{\sin \theta}\).
  • The secant function is the reciprocal of the cosine function: \(\sec \theta = \frac{1}{\cos \theta}\).
  • The cotangent function is the reciprocal of the tangent function: \(\cot \theta = \frac{1}{\tan \theta}\).
In the exercise, knowing \(\sec \theta = 2.6\) directly leads to \(\cos \theta = \frac{1}{2.6}\).Similarly, once \(\tan \theta\) is calculated, finding \(\cot \theta\) simply involves taking the reciprocal.These reciprocal identities allow us to derive any secondary trigonometric value from the primary one associated with a specific angle, enhancing problem-solving efficiency.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Graph the functions on the same screen of a graphing utility. [Use the change of base formula (9), where needed.] $$\log _{2} x, \ln x, \log _{5} x, \log x$$

The population \(p\) of the United States (in millions) in year \(t\) can be modeled by the function $$p(t)=\frac{525}{1+1.1 e^{-0.02225(t-1990)}}$$ (a) Based on this model, what was the U.S. population in \(1990 ?\) (b) Plot \(p\) versus \(t\) for the 200 -year period from 1950 to 2150 (c) By evaluating an appropriate limit, show that the graph of \(p\) versus \(t\) has a horizontal asymptote \(p=c\) for an appropriate constant \(c\) (d) What is the significance of the constant \(c\) in part (c) for the population predicted by this model?

A positive number \(\epsilon\) and the limit \(L\) of a function \(f\) at \(-\infty\) are given. Find a negative number \(N\) such that \(|f(x)-L|< \epsilon\) if \(x < N\) $$\lim _{x \rightarrow-\infty} \frac{x}{x+1}=1 ; \epsilon=0.001$$

Identify the domain and range of the function, and then sketch the graph of the function without using a graphing utility. (a) \(f(x)=1+\ln (x-2)\) (b) \(g(x)=3+e^{x-2}\)

According to Ohm's law, when a voltage of \(V\) volts is applied across a resistor with a resistance of \(R\) ohms, a current of \(I=V / R\) amperes flows through the resistor. (a) How much current flows if a voltage of 3.0 volts is applied across a resistance of 7.5 ohms? (b) If the resistance varies by ±0.1 ohm, and the voltage remains constant at 3.0 volts, what is the resulting range of values for the current? (c) If temperature variations cause the resistance to vary by \(\pm \delta\) from its value of 7.5 ohms, and the voltage remains constant at 3.0 volts, what is the resulting range of values for the current? (d) If the current is not allowed to vary by more than \(\epsilon=\pm 0.001\) ampere at a voltage of 3.0 volts, what variation of \(\pm \delta\) from the value of 7.5 ohms is allowable? (e) Certain alloys become superconductors as their temperature approaches absolute zero \(\left(-273^{\circ} \mathrm{C}\right),\) meaning that their resistance approaches zero. If the voltage remains constant, what happens to the current in a superconductor as \(R \rightarrow 0^{+} ?\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.