/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 First rationalize the numerator ... [FREE SOLUTION] | 91Ó°ÊÓ

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First rationalize the numerator and then find the limit. $$\lim _{x \rightarrow 0} \frac{\sqrt{x+4}-2}{x}$$

Short Answer

Expert verified
The limit is \( \frac{1}{4} \).

Step by step solution

01

Understanding the Problem

We are given the limit \( \lim_{x \rightarrow 0} \frac{\sqrt{x+4}-2}{x} \). To find this limit, we need to rationalize the numerator first because directly substituting \( x = 0 \) results in an indeterminate form \( \frac{0}{0} \).
02

Rationalizing the Numerator

To rationalize the numerator, multiply both the numerator and the denominator by the conjugate of the numerator: \( \frac{\sqrt{x+4}-2}{x} \times \frac{\sqrt{x+4}+2}{\sqrt{x+4}+2} \). This gives us: \[ \frac{(\sqrt{x+4}-2)(\sqrt{x+4}+2)}{x(\sqrt{x+4}+2)} \].
03

Simplifying the Expression

Using the identity \((a-b)(a+b) = a^2 - b^2\), the numerator becomes \((\sqrt{x+4})^2 - 2^2 = x + 4 - 4 = x\). So, the expression simplifies to: \( \frac{x}{x(\sqrt{x+4}+2)} \).
04

Cancel the Common Factor

Since there is a common term \(x\) in both the numerator and the denominator, cancel out \( x \) (assuming \( x eq 0 \)): \( \frac{1}{\sqrt{x+4}+2} \).
05

Compute the Limit

Now that we have eliminated the indeterminate form, substitute \( x = 0 \) into \( \frac{1}{\sqrt{x+4}+2} \): \( \frac{1}{\sqrt{0+4}+2} = \frac{1}{4} \). Thus, the limit is \( \frac{1}{4} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rationalizing the Numerator
Rationalizing the numerator is a technique used in calculus to simplify expressions before calculating the limit. It is often employed when the direct substitution of a variable results in an indeterminate form, such as \( \frac{0}{0} \).

In our exercise, the numerator is \( \sqrt{x+4} - 2 \). To rationalize it, we multiply both the numerator and the denominator by its conjugate, \( \sqrt{x+4} +2 \). This results in a difference of squares: \((\sqrt{x+4} - 2)(\sqrt{x+4} + 2)\).

Applying the identity \( (a-b)(a+b) = a^2 - b^2 \), we simplify the expression to \( x \). This new expression is easier to handle, which facilitates the elimination of the indeterminate form.
  • Multiply by the conjugate: \( \sqrt{x+4} + 2 \).
  • Apply the difference of squares: \( a^2 - b^2 \).
  • Simplify to obtain a more manageable expression.
Indeterminate Form
Indeterminate forms arise in calculus during limit calculations when both the numerator and the denominator approach 0 simultaneously. Such forms don't have an immediate value, and special techniques are required to resolve them. Indeterminate forms look like \( \frac{0}{0} \) among others such as \( \frac{\infty}{\infty} \), \( 0 \cdot \infty \), etc.

In our case, substituting \( x = 0 \) into \( \frac{\sqrt{x+4} - 2}{x} \) gives \( \frac{0}{0} \), which is indeterminate. This indicates that some initial manipulation of the expression is necessary before evaluating the limit.

Understanding and identifying when a form is indeterminate is crucial. It tells us we cannot directly substitute the variable into the expression without further simplification. The goal is to rewrite the limit in such a way that this undefined form is resolved or avoided altogether.
  • Identify when you have an indeterminate form.
  • Recognize the need for further simplification or manipulation.
  • Employ techniques like rationalization to resolve the indeterminacy.
Limit Calculation Techniques
When faced with a limit problem, there are several approaches we can use. Each technique helps us to simplify or manipulate the expression to find the limit without falling into traps like indeterminate forms. Here are some of the most common methods:

  • **Direct Substitution**: Check if substituting the value of the limit variable directly into the expression gives a definite answer.
  • **Factoring**: Rearrange the terms into factors that may cancel out problematic parts of the expression.
  • **Rationalization**: Mutiplying by a conjugate can eliminate roots or create a difference of squares, as seen in our exercise.
  • **L'Hôpital's Rule**: When you encounter \( \frac{0}{0} \) or \( \frac{\infty}{\infty} \), derivative techniques can resolve the limit.
  • **Simplification**: Algebraic simplification can sometimes make the problem more tractable.
Our exercise used rationalization to transform the indeterminate form \( \frac{0}{0} \) into a simple expression where \( x \) cancels out. This allowed us to compute the limit easily by substituting \( x = 0 \), thus obtaining \( \frac{1}{4} \).

Practicing these techniques can improve your mastery of limits in calculus and make problem-solving much more intuitive.

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Most popular questions from this chapter

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