Chapter 1: Problem 15
Rewrite the expression as a single logarithm. $$2 \ln (x+1)+\frac{1}{3} \ln x-\ln (\cos x)$$
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Chapter 1: Problem 15
Rewrite the expression as a single logarithm. $$2 \ln (x+1)+\frac{1}{3} \ln x-\ln (\cos x)$$
These are the key concepts you need to understand to accurately answer the question.
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A positive number \(\epsilon\) and the limit \(L\) of a function \(f\) at +\infty are given. Find a positive number \(N\) such that if \(x>N\) then \(|f(x)-L|<\epsilon\) $$\lim _{x \rightarrow+\infty} \frac{4 x-1}{2 x+5}=2 ; \epsilon=0.1$$
Prove: If \(p(x)\) is a polynomial of odd degree, then the equation \(p(x)=0\) has at least one real solution.
Suppose that \(f\) is an invertible function, \(f(0)=0, f\) is continuous at \(0,\) and \(\lim _{x \rightarrow 0} f(x) / x\) exists. Given that \(L=\lim _{x \rightarrow 0} f(x) / x,\) show $$\lim _{x \rightarrow 0} \frac{x}{f^{-1}(x)}=L$$ [Hint: Apply Theorem 1.5 .5 to the composition hog, where $$h(x)=\left\\{\begin{array}{ll} f(x) / x, & x \neq 0 \\ L, & x=0 \end{array}\right.$$ and \(\left.g(x)=f^{-1}(x)\right].\)
Use the Squeezing Theorem to show that $$\lim _{x \rightarrow 0} x \cos \frac{50 \pi}{x}=0$$ and illustrate the principle involved by using a graphing utility to graph the equations \(y=|x|, y=-|x|,\) and \(y=x \cos (50 \pi / x)\) on the same screen in the window \([-1,1] \times[-1,1]\).
Prove: If \(f\) and \(g\) are continuous on \([a, b],\) and \(f(a)>g(a)\) \(f(b)
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