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A parcel of land bought in 1990 for \(\$ 10,000\) was worth \(\$ 16,000\) in \(1995 .\) If the land continues to appreciate at this rate, in what year will it be worth \(\$ 45,000 ?\)

Short Answer

Expert verified
The land will be worth \$45,000 around the year 2007.

Step by step solution

01

Determine the Annual Appreciation Rate

First, calculate the annual appreciation rate. Use the formula for compound appreciation: \[ A = P (1 + r)^n \]Where:- \(A\) is the amount of the land after n years- \(P\) is the initial amount (\$10,000)- \(r\) is the annual appreciation rate- \(n\) is the number of yearsPlugging in the numbers: \[ 16000 = 10000 (1 + r)^5 \]\[ (1 + r)^5 = \frac{16000}{10000} \]\[ (1 + r)^5 = 1.6 \]Solve for \(r\): \[ 1 + r = (1.6)^{\frac{1}{5}} \]\[ r \thickapprox 0.099 or 9.9 \text{\times 10}\]
02

Set Up the Equation for the Future Value

Next, find how many years it will take for the land to be worth \$45,000. Using the same compound interest formula: \[ 45000 = 10000 (1 + 0.099)^n \] Solve for \(n\): \[ (1 + 0.099)^n = \frac{45000}{10000} \]\[ 1.099^n = 4.5 \]
03

Solve for the Number of Years

To find the value of \(n\), take the natural logarithm of both sides: \[ = \frac{\text{ln}(4.5)}{\text{ln}(1.099)} \]\[ n \thickapprox 17.3 \] So, it will take approximately 17.3 additional years from 1990 to reach \$45,000.
04

Determine the Year

Add the number of years determined in Step 3 to the initial year: \[ \text{Year} = 1990 + 17.3 \thickapprox 2007.3 \] The land will be worth \$45,000 around the year 2007.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Annual Appreciation Rate
When an asset, such as a parcel of land, increases in value over time, the rate at which this increase occurs each year is called the annual appreciation rate. This rate represents the percentage increase in the value of the asset on an annual basis.

In problems like our exercise, where we know the initial and final values over a period of years, we can use these values to calculate the annual appreciation rate. The formula used can be derived from the compound interest formula:

We have the final amount (\text{A}) = \$16,000, the initial principal (\text{P}) = \$10,000, and the period (\text{N}) = 5 years. Plug these into the compound interest formula: \[16000 = 10000 (1 + r)^5\] Then solve for the annual rate (\text{r}): \[1 + r = (1.6)^{\frac{1}{5}}\] This gives us an annual appreciation rate of about 9.9%. This means that, every year, the land's value is increasing by 9.9% of the previous year's value.
Compound Interest Formula
The compound interest formula helps us determine the future value of an investment based on an initial principal and an interest rate compounded over a certain number of periods.

The formula is expressed as: \[A = P (1 + r)^n\]
  • \text{A} is the amount of money accumulated after n years, including interest.
  • \text{P} is the principal amount (the initial sum of money).
  • \text{r} is the annual interest rate (as a decimal).
  • \text{n} is the number of years the money is invested or borrowed for.
In the given exercise to find when the land will be worth \$45,000, we use this formula and input our known values:

\[45000 = 10000 (1 + 0.099)^n\] By solving for \text{n}, we can determine how many years it will take for the investment to grow to \$45,000. This showcases the power of the compound interest formula in calculating future values over time.
Natural Logarithm
A natural logarithm is used in mathematics to solve for variables within equations involving exponential growth or decay. In this context, we use the natural logarithm to simplify solving for the number of years when working with compound interest and appreciation rates.

The natural logarithm, represented as \text{ln}, is particularly useful for 'undoing' the effects of exponentiation. For instance, if we encounter an equation of the form: \[1.099^n = 4.5\] Taking the natural logarithm of both sides gives us: \[ \text{ln}(1.099^n) = \text{ln}(4.5)\] Utilizing logarithmic properties, this simplifies to: \[ n \times \text{ln}(1.099) = \text{ln}(4.5)\] Finally, solving for \text{n}: \[ n = \frac{\text{ln}(4.5)}{\text{ln}(1.099)}\] This step-by-step method allows us to isolate \text{n} and compute the value accurately. The natural logarithm is critical in transforming complex exponential equations into manageable linear forms.

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