/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Differentiate the following func... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Differentiate the following functions. $$y=3 \frac{\ln x}{x}$$

Short Answer

Expert verified
The derivative is \( y' = \frac{3(1 - \ln x)}{x^2} \).

Step by step solution

01

Identify the function

Given the function, identify its components. The function to differentiate is: \[ y = 3 \frac{\ln x}{x} \]
02

Apply the constant multiple rule

The constant multiple rule states that the derivative of a constant times a function is the constant times the derivative of the function. In this case, 3 is the constant. Therefore, the problem simplifies to finding the derivative of \( \frac{\ln x}{x} \) and then multiplying by 3.
03

Use the quotient rule

Apply the quotient rule to differentiate \( \frac{\ln x}{x} \). The quotient rule states that if you have a function of the form \( \frac{u(x)}{v(x)} \), its derivative is: \[ \left( \frac{u}{v} \right)' = \frac{u'v - uv'}{v^2} \] Here, \( u = \ln x \) and \( v = x \).
04

Differentiate the numerator and the denominator

First, find the derivatives of the numerator and the denominator individually: \( u = \ln x \) \( u' = \frac{1}{x} \) \( v = x \) \( v' = 1 \)
05

Apply the quotient rule formula

Substitute the derivatives into the quotient rule formula: \[ \left( \frac{\ln x}{x} \right)' = \frac{ \left( \frac{1}{x} \right) x - (\ln x)(1) }{x^2} \]
06

Simplify the expression

Simplify the expression: \[ \left( \frac{\ln x}{x} \right)' = \frac{1 - \ln x}{x^2} \]
07

Multiply by the constant

Finally, multiply the result by the constant 3: \[ y' = 3 \cdot \frac{1 - \ln x}{x^2} = \frac{3(1 - \ln x)}{x^2} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constant Multiple Rule
When differentiating functions, you'll often encounter constants multiplied by a function. The **constant multiple rule** simplifies our task of differentiation. This rule states that if you have a function of the form \( y = c \times f(x) \), where \( c \) is a constant and \( f(x) \) is a function of \( x \), then the derivative is simply the constant multiplied by the derivative of \( f(x) \).

Let's break this down with an example. Suppose we have:
  • \( y = 3 \times f(x) \)
According to the constant multiple rule, its derivative is:
  • \( y' = 3 \times f'(x) \)
In our exercise, the function given is \( y = 3 \frac{\text{ln} x}{x} \). Here, \( 3 \) is our constant, and \( \frac{\text{ln} x}{x} \) is our function \( f(x) \). By the constant multiple rule, to find the derivative, we first differentiate \( \frac{\text{ln} x}{x} \) and then multiply the result by 3.
Quotient Rule
When we deal with fractions where the numerator and the denominator are both functions of \( x \), we use the **quotient rule**. The quotient rule states that if you have a function of form \( \frac{u(x)}{v(x)} \), its derivative is given by:
\[ \frac{d}{dx}\frac{u(x)}{v(x)} = \frac{u'v - uv'}{v^2} \] This ensures that we accurately account for the changes in both the numerator \( u(x) \) and the denominator \( v(x) \).
Here’s how we apply it in our exercise: we are given the function:
  • \( \frac{\text{ln} x}{x} \)
Let's identify our numerator and denominator:
  • \( u = \text{ln} x \), so \( u' = \frac{1}{x} \)
  • \( v = x \), so \( v' = 1 \)
Substituting these into our quotient rule formula, we get:
\[ \frac{u'v - uv'}{v^2} = \frac{\frac{1}{x} \times x - \text{ln} x \times 1}{x^2} = \frac{1 - \text{ln} x}{x^2} \] By correctly applying the quotient rule, we find the derivative is \( \frac{1 - \text{ln} x}{x^2} \).
Differentiation
Differentiation is a fundamental concept in calculus. It involves finding the rate at which a function changes at any given point. The derivative of a function gives us the slope of the tangent line to the function at any point.

In our exercise, we are asked to differentiate the function \( y = 3 \frac{\text{ln} x}{x} \). To differentiate:
  • We first identified the constant and applied the constant multiple rule to simplify our task.
  • Next, we used the quotient rule to differentiate the fraction \( \frac{\text{ln} x}{x} \).
  • Finally, we multiplied our result by the constant 3.
Breaking it down step-by-step: 1. **Identify the function parts**: Determine the constant and the function to be differentiated. 2. **Apply Constant Multiple Rule**: Take out the constant and focus on differentiating the function. 3. **Quotient Rule**: Use the rule for fractions with functions in both numerator and denominator.

This gave us our final derivative:
  • \( y' = \frac{3(1 - \text{ln} x)}{x^2} \)
Differentiation allows us to understand how a function behaves at any point, making it a crucial tool in calculus and various real-world applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.