/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 A store manager wants to establi... [FREE SOLUTION] | 91Ó°ÊÓ

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A store manager wants to establish an optimal inventory policy for an item. Sales are expected to be at a steady rate and should total \(Q\) items sold during the year. Each time an order is placed a cost of \(h\) dollars is incurred. Carrying costs for the year will be \(s\) dollars per item, to be figured on the average number of items in storage during the year. Show that the total inventory cost is minimized when each order calls for \(\sqrt{2 h Q / s}\) items.

Short Answer

Expert verified
The total inventory cost is minimized when each order is \(q = \frac{\text{\textbackslash }\text{\textbackslash }\text{\textbackslash }\textbackslash \textbackslash }\text{\textbackslash sqrt\text{\textbackslash }{2hQ}\text{\textbackslash }{s\text{\textbackslash }}1pt\text{\textbackslash }}

Step by step solution

01

Understand the Given Information

Identify the variables in the exercise:- Sales per year, total items: \(Q\) - Cost per order: \(h\) dollars - Carrying cost per item per year: \(s\) dollars
02

Define the Variables

Let's define additional variables necessary for solving the problem:- Number of orders placed per year: \(N\)- Quantity ordered each time (optimal order quantity): \(q\)
03

Establish Relationships Between Variables

Relate the annual sales and the number of orders placed per year: \[Q = q \times N\]This means the total sales per year (\(Q\)) equals the quantity ordered each time (\(q\)) times the number of orders placed per year (\(N\)).
04

Calculate Ordering Costs

The total ordering cost for the year depends on the number of orders placed:\[ \text{Total\text{ }}\text{ordering\text{ }}\text{cost} = h \times N \]
05

Calculate Carrying Costs

Carrying costs depend on the average number of items in storage. Since items are continuously ordered and consumed, the average inventory is \(q / 2\):\[ \text{Total\text{ }}\text{carrying\text{ }}\text{cost} = s \times \frac{q}{2} \]
06

Calculate Total Inventory Cost

Combine both ordering and carrying costs to find the total inventory cost for the year:\[\text{Total\text{ }}\text{inventory\text{ }}\text{cost} = h \times N + s \times \frac{q}{2}\]
07

Substitute \(N\)

We know \(N = \frac{Q}{q}\). Substitute this into the total inventory cost equation:\[\text{Total\text{ }}\text{inventory\text{ }}\text{cost} = h \times \frac{Q}{q} + s \times \frac{q}{2}\]
08

Optimize the Total Inventory Cost

To find the optimal order quantity \(q\) that minimizes the total inventory cost, take the first derivative with respect to \(q\) and set it to zero: \[\frac{d}{dq}\bigg(h \frac{Q}{q} + s \frac{q}{2}\bigg) = 0\]
09

Calculate the First Derivative

Calculate the derivative: \[-h \frac{Q}{q^2} + \frac{s}{2} = 0\]
10

Solve for \(q\)

Isolate \(q\) to find the optimal quantity:\[-h \frac{Q}{q^2} = - \frac{s}{2}\]Multiply both sides by \[2 q^2 \]:\[-2hQ = -s q^2\]Solve for \(q\):\[q^2 = \frac{2hQ}{s}\]\[q = \frac{\text{\textbackslash }\text{\textbackslash }\text{\textbackslash \textbackslash \textbackslash }\text{\textbackslash sqrt\text{\textbackslash }{2hQ\text{\textbackslash }{s\text{\textbackslash }}1pt\text{\textbackslash }}1pt}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

inventory costs
To understand optimal inventory policies, we first need to delve into **inventory costs**. These costs include two key components: _ordering costs_ and _carrying costs_.
Ordering costs are incurred each time an order is placed. This could involve costs related to processing the order, shipping, and handling, represented by the variable \( h \), which is the cost per order. On the other hand, carrying costs reflect the expenses of holding inventory over time, such as storage, insurance, and opportunity costs. This is represented by \( s \), which is the carrying cost per item per year.
Thus, a crucial part of minimizing total inventory costs involves understanding and balancing these two components.
order quantity
The **order quantity** determines how many items should be ordered each time to balance out the costs. We denote the optimal order quantity as \( q \). The goal is to find the value of \( q \) that minimizes total inventory costs.
Let's first consider the frequency of ordering. If \( Q \) represents the total sales per year, and \( N \) is the number of orders placed each year, then:
  • \( N \) can be calculated as \( N = \frac{Q}{q} \), which shows how frequently we place orders based on our annual sales \( Q \) and our order quantity \( q \).

Balancing order frequency with quantity per order is essential for cost minimization.
cost minimization
Achieving **cost minimization** implies combining both ordering and carrying costs and finding a balance that minimizes them. The total inventory cost function is given by combining these individual costs:
When we combine the ordering cost \( h \textbackslash times N \) and the carrying cost \( s \textbackslash times \textbackslash \frac{q}{2} \), we obtain:
  • \(\text{Total inventory cost} = h \textbackslash times \textbackslash \frac{Q}{q} + s \textbackslash \times \textbackslash \frac{q}{2}\)

The goal is to find the quantity \( q \) that minimizes this total cost function.
calculus application
We utilize **calculus** to find the value of \( q \) that minimizes our total inventory cost. This involves taking the derivative of the total cost function with respect to \( q \) and setting it to zero:
  • \(\frac{d}{dq}\bigg(h \textbackslash times \textbackslash \frac{Q}{q} + s \textbackslash times \textbackslash \frac{q}{2}\bigg) = 0\)

After taking the derivative, we simplify and solve for \( q \):
  • \[-h \textbackslash \frac{Q}{q^2} + \textbackslash \frac{s}{2} = 0\]
  • Rearranging and solving, we get: \( q^2 = \textbackslash \frac{2hQ}{s} \)
  • Thus, \( q = \textbackslash sqrt{ \textbackslash \frac{2hQ}{s} } \)

This gives us the optimal order quantity for minimizing total inventory costs.

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Most popular questions from this chapter

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