Chapter 2: Problem 2
Each of the graphs of the functions has one relative maximum and one relative minimum point. Find these points using the first-derivative test. Use a variation chart as in Example 1. $$f(x)=x^{3}-6 x^{2}+1$$
Short Answer
Expert verified
Relative maximum at (0, 1) and relative minimum at (4, -31).
Step by step solution
01
Find the first derivative of the function
To apply the first-derivative test, start by finding the first derivative of the function. Compute the derivative of the function f(x) = x^3 - 6x^2 + 1 The first derivative is determined using the power rule: f'(x) = 3x^2 - 12x.
02
Find critical points
Next, set the first derivative equal to zero and solve for x: 3x^2 - 12x = 0 Factor out the common term 3x: 3x(x - 4) = 0 Thus, the critical points are: x = 0 and x = 4.
03
Set up a variation chart
To determine the sign of the first derivative in the intervals defined by the critical points, construct a variation chart: Consider the intervals: (-∞, 0), (0, 4), and (4, ∞) Test points from each interval in the first derivative function f'(x): For x = -1 in (-∞, 0): f'(-1) = 3(-1)^2 - 12(-1) = 3 + 12 = 15 (positive) For x = 2 in (0, 4): f'(2) = 3(2)^2 - 12(2) = 12 - 24 = -12 (negative) For x = 5 in (4, ∞): f'(5) = 3(5)^2 - 12(5) = 75 - 60 = 15 (positive) This means the sign of f'(x) changes as follows: + (from -∞ to 0), - (from 0 to 4), + (from 4 to ∞)
04
Identify relative extrema
Using the variation chart, determine the relative extrema: At x = 0, f'(x) changes from positive to negative, indicating a relative maximum at x = 0 At x = 4, f'(x) changes from negative to positive, indicating a relative minimum at x = 4
05
Compute function values at critical points
Find f(x) at the critical points to get the coordinates of the relative extrema: f(0) = 0^3 - 6(0)^2 + 1 = 1 Thus, the relative maximum is at (0, 1) f(4) = 4^3 - 6(4)^2 + 1 = 64 - 96 + 1 = -31 Thus, the relative minimum is at (4, -31)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
relative extrema
Relative extrema are points on the graph where a function reaches a local maximum or minimum value. These points are important for understanding the behavior of the function. To find relative extrema, one common method is the first-derivative test.
When the first derivative of a function changes sign, it indicates a relative extremum. For example, if the derivative changes from positive to negative, the function has a relative maximum at that point. Conversely, if it changes from negative to positive, there is a relative minimum. In the given problem, we use this concept to find where the graph of the function has these turning points.
These points are valuable in many real-world applications like finding the highest points (peaks) on a road or the lowest points (valleys) in business profit graphs. Understanding relative extrema helps in making informed decisions based on these peaks and valleys.
When the first derivative of a function changes sign, it indicates a relative extremum. For example, if the derivative changes from positive to negative, the function has a relative maximum at that point. Conversely, if it changes from negative to positive, there is a relative minimum. In the given problem, we use this concept to find where the graph of the function has these turning points.
These points are valuable in many real-world applications like finding the highest points (peaks) on a road or the lowest points (valleys) in business profit graphs. Understanding relative extrema helps in making informed decisions based on these peaks and valleys.
power rule
The power rule is a fundamental technique in calculus for finding the derivative of a function of the form \(f(x) = x^n\), where \(n\) is any real number. The power rule states:
\(f'(x) = nx^{(n-1)}\)
Applying the power rule makes it easy to compute derivatives quickly. For example, in the exercise, the function is given as \(f(x) = x^3 - 6x^2 + 1\). Using the power rule, we find:
\(f'(x) = nx^{(n-1)}\)
Applying the power rule makes it easy to compute derivatives quickly. For example, in the exercise, the function is given as \(f(x) = x^3 - 6x^2 + 1\). Using the power rule, we find:
- For \(x^3\), the derivative is \(3x^2\)
- For \(-6x^2\), the derivative is \(-12x\)
- For the constant term \(1\), the derivative is \(0\)
variation chart
A variation chart is a valuable tool for understanding how the sign of the first derivative changes over different intervals. This helps to locate relative extrema. We set up the variation chart by:
- Identifying the critical points where \(f'(x) = 0\)
- Dividing the number line into intervals based on these critical points
- Testing a point within each interval to determine whether \(f'(x)\) is positive or negative
- For \(x = -1\), \(f'(-1) > 0\)
- For \(x = 2\), \(f'(2) < 0\)
- For \(x = 5\), \(f'(5) > 0\)