/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 Radioactive cobalt 60 has a half... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Radioactive cobalt 60 has a half-life of \(5.3\) years. Find its decay constant.

Short Answer

Expert verified
The decay constant is approximately 0.1308 years^{-1}.

Step by step solution

01

Understand the concept of half-life

The half-life of a substance is the time it takes for half of the substance to decay. For cobalt 60, the half-life is given as 5.3 years.
02

Identify the formula for decay constant

The decay constant \(\lambda\) can be found using the relationship between the half-life \(T_{1/2}\) and the decay constant: \[\lambda = \frac{\ln(2)}{T_{1/2}}\].
03

Substitute the given half-life

Plug in the given half-life of 5.3 years into the formula: \[\lambda = \frac{\ln(2)}{5.3}\].
04

Calculate the decay constant

Perform the calculation: \[\lambda = \frac{0.693}{5.3} \approx 0.1308 \text{ years}^{-1}\].

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

half-life calculation
Radioactive decay is a process where unstable atomic nuclei lose energy by emitting radiation. The half-life is a crucial concept in this process. It refers to the time required for half of a radioactive substance to decay. For instance, if we start with a certain amount of radioactive cobalt-60, after one half-life of 5.3 years, only half of the initial amount will remain. This concept helps us predict the rate at which a radioactive material will diminish over time. To calculate the half-life, we generally use the decay constant, which provides a more detailed understanding of the decay process.
decay constant
The decay constant (\textbackslash \lambda) represents the probability per unit of time that a given nucleus will decay. It's a key parameter in understanding the decay process. To calculate the decay constant, use the formula: \[\lambda = \frac{\ln(2)}{T_{1/2}}\]. Here, \(T_{1/2}\) is the half-life. The natural logarithm of 2 (\text \ln(2)) is approximately 0.693. By dividing this value by the half-life of the substance, we get the decay constant. For Cobalt-60, with a half-life of 5.3 years, the decay constant (\text \lambda) is: \[ \lambda = \frac{0.693}{5.3} \approx 0.1308 \text{ years}^{-1}\]. This value. 0.1308, tells us the fraction of the substance that decays per year. Understanding the decay constant allows you to predict the behavior of radioactive materials over time.
Cobalt-60
Cobalt-60 is a radioactive isotope of cobalt. It has a significant application in various fields such as medical therapy and industrial radiography. One of its most important characteristics is its half-life of 5.3 years. This means every 5.3 years, the amount of cobalt-60 in a sample reduces by half due to radioactive decay. Because of this predictable rate of decay, cobalt-60 is very useful in contexts where precise radiation doses are required.
Understanding how to calculate the decay constant and the half-life for cobalt-60 helps in many practical applications, including safety protocols, medical treatments, and scientific research.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.