Chapter 2: Problem 5
Find the \(x\) -intercepts of the given function. $$ y=4 x-4 x^{2}-1 $$
Short Answer
Expert verified
The x-intercept is \(x = \frac{1}{2}\).
Step by step solution
01
Understand the problem
The goal is to find the x-intercepts of the function. This means we need to find the values of x when y is zero.
02
Set the function equal to zero
Start by setting the equation of the function equal to zero:\(4x - 4x^2 - 1 = 0\)
03
Rearrange the equation
Rearrange the equation in standard quadratic form, which is \(ax^2 + bx + c = 0\). Here, the equation is already in this form: \(-4x^2 + 4x - 1 = 0\).
04
Identify coefficients
Identify the coefficients: \(a = -4\), \(b = 4\), \(c = -1\).
05
Use the quadratic formula
Use the quadratic formula to find the roots of the equation: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
06
Calculate the discriminant
Calculate the discriminant, which is the value under the square root. Discriminant = \(b^2 - 4ac\):\(b^2 - 4ac = 4^2 - 4(-4)(-1) = 16 - 16 = 0\).
07
Solve for x
Since the discriminant is 0, there is only one x-intercept. Substitute a, b, and the discriminant into the quadratic formula:\(x = \frac{-4 \pm \sqrt{0}}{2(-4)}\)This simplifies to \(x = \frac{-4}{-8} = \frac{1}{2}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
quadratic function
A quadratic function is a polynomial function of degree two. It typically takes the form \(y = ax^2 + bx + c\), where \(a, b,\) and \(c\) are constants and \(a eq 0\). Quadratic functions graph as parabolas, which are U-shaped curves that can open upwards or downwards depending on the sign of \(a\). If \(a > 0\), the parabola opens upwards; if \(a < 0\), it opens downwards.
The x-intercepts of a quadratic function are the points where the graph crosses the x-axis, meaning the value of \(y\) at these points is zero. To find the x-intercepts, you set the quadratic function equal to zero and solve for \(x\).
In the given example, the function is \(y = 4x - 4x^2 - 1\). This can be rearranged into standard form: \(-4x^2 + 4x - 1\). To find the x-intercepts, we need to solve \(-4x^2 + 4x - 1 = 0\).
The x-intercepts of a quadratic function are the points where the graph crosses the x-axis, meaning the value of \(y\) at these points is zero. To find the x-intercepts, you set the quadratic function equal to zero and solve for \(x\).
In the given example, the function is \(y = 4x - 4x^2 - 1\). This can be rearranged into standard form: \(-4x^2 + 4x - 1\). To find the x-intercepts, we need to solve \(-4x^2 + 4x - 1 = 0\).
quadratic formula
The quadratic formula is a powerful tool to find the solutions (or roots) of any quadratic equation. The formula is derived from the process of completing the square and provides the solutions to \(ax^2 + bx + c = 0\). The quadratic formula is given by: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
Using the quadratic formula involves:
For the equation \(-4x^2 + 4x - 1 = 0\), we identified \(a = -4\), \(b = 4\), and \(c = -1\). Substituting these into the quadratic formula, we find the x-intercepts as \(x = \frac{-4 \pm \sqrt{0}}{2(-4)}\), which simplifies to \(x = \frac{1}{2}\).
Using the quadratic formula involves:
- Identifying the coefficients \(a, b,\) and \(c\) from the quadratic equation.
- Calculating the discriminant \(b^2 - 4ac\).
- Substituting the values of \(a\), \(b\), and the discriminant into the formula to find the values of \(x\).
For the equation \(-4x^2 + 4x - 1 = 0\), we identified \(a = -4\), \(b = 4\), and \(c = -1\). Substituting these into the quadratic formula, we find the x-intercepts as \(x = \frac{-4 \pm \sqrt{0}}{2(-4)}\), which simplifies to \(x = \frac{1}{2}\).
discriminant
The discriminant is a key part of the quadratic formula found under the square root symbol, \(b^2 - 4ac\). It helps determine the nature and number of roots of the quadratic equation. The value of the discriminant can be:
In our example, the discriminant is calculated as \(4^2 - 4(-4)(-1) = 16 - 16 = 0\). Since the discriminant is 0, this means our quadratic equation \(-4x^2 + 4x - 1 = 0\) has exactly one real root, which is \(x = \frac{1}{2}\). This single root indicates that the parabola touches the x-axis at one point only, making this point the sole x-intercept.
- Positive: If the discriminant is greater than 0, the quadratic equation has two distinct real roots.
- Zero: If the discriminant is exactly 0, the quadratic equation has one real root (also called a repeated or double root).
- Negative: If the discriminant is less than 0, the quadratic equation has no real roots but two complex roots.
In our example, the discriminant is calculated as \(4^2 - 4(-4)(-1) = 16 - 16 = 0\). Since the discriminant is 0, this means our quadratic equation \(-4x^2 + 4x - 1 = 0\) has exactly one real root, which is \(x = \frac{1}{2}\). This single root indicates that the parabola touches the x-axis at one point only, making this point the sole x-intercept.