/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 Find the quadratic function \(f(... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the quadratic function \(f(x)=a x^{2}+b x+c\) that goes through \((2,0)\) and has a local maximum at \((0,1)\).

Short Answer

Expert verified
The quadratic function is \(f(x) = -\frac{1}{4}x^2 + 1\).

Step by step solution

01

Set Up the General Form of the Quadratic Function

The general form of the quadratic function is given by: \(f(x) = ax^2 + bx + c\).
02

Use the Point (2,0)

Substitute the point (2,0) into the quadratic function to get one equation:\(0 = a(2)^2 + b(2) + c\) which simplifies to \(4a + 2b + c = 0\).
03

Use the Point (0,1)

Substitute the point (0,1) into the quadratic function to get another equation:\(1 = a(0)^2 + b(0) + c\) which simplifies to \(c = 1\).
04

Use the Local Maximum Condition at (0,1)

The local maximum at \((0,1)\) means that the derivative of the quadratic function is 0 at \(x=0\). Compute the derivative: \(f'(x) = 2ax + b\).Substitute \(x=0\):\(0 = 2a(0) + b\) which simplifies to \(b = 0\).
05

Solve the System of Equations

Substitute \(b=0\) and \(c=1\) into the equation from Step 2:\(4a + 2(0) + 1 = 0\), which simplifies to \(4a + 1 = 0\).Solve for \(a\):\(4a = -1\)\(a = -\frac{1}{4}\).
06

Write the Quadratic Function

Now that the values of \(a\), \(b\), and \(c\) are known, substitute them back into the general form of the quadratic function:\(f(x) = -\frac{1}{4}x^2 + 0x + 1\) which simplifies to \(f(x) = -\frac{1}{4}x^2 + 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

System of Equations
A system of equations is a set of multiple equations that one needs to solve together. For this quadratic function, we derive:
  • 4a + 2b + c = 0 (from point (2, 0)).
  • c = 1 (from point (0, 1)).
  • b = 0 (from the local maximum condition).
We solve these equations step by step:
  • Substitute b = 0 and c = 1 into the first equation to find a.
  • Simplify to get the specific values of a, b, and c.
This process ultimately leads to the final quadratic function.

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