/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 A person took out a loan of $$\$... [FREE SOLUTION] | 91Ó°ÊÓ

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A person took out a loan of $$\$ 100,000$$ from a bank that charges \(7.5 \%\) interest compounded continuously. What should be the annual rate of payments if the loan is to be paid in full in exactly 10 years? (Assume that the payments are made continuously throughout the year.)

Short Answer

Expert verified
The annual rate of payments is \$14,211.89.

Step by step solution

01

Understand the Formula

We need to find the annual rate of payments for a loan with continuous compounding. The formula to find the future value of a continuously compounded loan is \[A = Pe^{rt}\] where A is the amount of loan, P is the principal, r is the interest rate, and t is the time in years.
02

Substitute Known Values

Substitute the given values into the formula: P = \$100,000, r = 0.075, and t = 10 years. \[A = 100,000e^{0.075 \times 10\}\]
03

Calculate the Future Value

Calculate the exponential part:\[e^{0.75} \approx 2.117\]Now multiply this by the principal:\[A = 100,000 \times 2.117 = 211,700\]Therefore, the loan amount grows to \$211,700 after 10 years.
04

Set Up the Continuous Payment Formula

The continuous payment formula to pay off the amount is: \[P = \frac{A}{\frac{e^{rt} - 1}{r}}\]We need to find A, which is \$211,700, and r is the annual rate we are solving for.
05

Calculate Annual Rate of Payments

Rearrange the formula:\[P = \frac{211,700 \times 0.075}{e^{0.75} - 1} \Since we know that \[e^{0.75} \approx 2.117\],\]We get:\[P = \frac{211,700 \times 0.075}{2.117 - 1} = \frac{15,877.5}{1.117} = 14,211.89\]Therefore, the annual rate of payments is \$14,211.89.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Loan Repayment
When you take out a loan, you borrow money with the agreement to pay it back over time, usually with interest. Let's break down how this works with continuously compounded interest. With a traditional loan, interest might be compounded monthly or yearly, meaning interest is calculated and added to the loan balance at specific intervals. In continuous compounding, interest is calculated and added continuously, leading to exponential growth.

To repay a loan with continuous interest, you need to understand the future value formula: equation (\( A = Pe^{rt} \)). Here,
  • \(A\) is the amount you owe after a certain period.
  • \(P\) is the initial principal (amount borrowed).
  • \(r\) is the annual interest rate.
  • \(t\) is the time in years.
For our example, the loan of \(100,000 grows to \)211,700 in 10 years at an interest rate of 7.5%, compounded continuously.
Annual Rate of Payments
To pay off the loan in a specified period, like 10 years, borrowers need to make continuous payments annually. The formula to find the annual rate of payments for continuous compounding is \( P = \frac{A}{\frac{e^{rt} - 1}{r}} \), where:
  • \(P\) is the annual payment rate.
  • \(A\) is the future value of the loan.
  • \(r\) is the interest rate.
  • \(t\) is the time.
Using the values from our exercise, we calculated that the loan grows to \(211,700 in 10 years. Substituting these values in the continuous payment formula, we find:\( P = \frac{211,700 \times 0.075}{e^{0.75} - 1} \)This is simplified to approximately \( P \approx 14,211.89 \). So, the annual rate of payments needed to repay this loan in full over 10 years is about \)14,211.89.
Exponential Growth in Finance
Exponential growth is a key concept in finance, especially with continuously compounded interest. Unlike linear growth, where a quantity increases by a fixed amount over time, exponential growth increases by a fixed percentage, leading to rapid escalation. This principle is embedded in the formula \( A = Pe^{rt} \).Using it, we can see how money multiplies over time when interest is compounded continuously.

For students and potential borrowers, understanding this concept is crucial. Even small changes in the interest rate or the duration of the loan can significantly affect the total amount owed. It’s like planting a tree — initially, growth may appear slow, but it picks up pace and eventually becomes very large in a short period.

Consider continuous compounding as a snowball effect. Each small increase in the principal makes the next interest calculation larger, and so on. This model is not just applicable to loans but also investments, savings, and many other financial products where compound interest is a factor.

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Most popular questions from this chapter

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