/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Solve the following differential... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve the following differential equations: $$ \frac{d y}{d t}=t^{1 / 2} y^{2} $$

Short Answer

Expert verified
y = - (\frac{ c}{ c +( t^{ ( 3 / 2 )}}. )}{[( \frac{2}{ 3} = \frac{-1}{ y}.

Step by step solution

01

Rewrite the Differential Equation

Start by rewriting the given differential equation \(\frac{d y}{d t}=t^{1 / 2} y^{2}\) in a separable form to isolate the variables on each side.
02

Separate the Variables

Rearrange the equation to separate the variables: \[\frac{1}{y^{2}} \frac{d y}{d t} = t^{1/2}\]. Then rewrite it as: \(\frac{1}{y^{2}} d y = t^{1/2} d t\).
03

Integrate Both Sides

Integrate both sides of the equation: \(\begin{align*} \text{Left side:} & \ \text{Integral:} & \ \ \text{Right side:} & \ \text{Integral:} & \ \frac{1}{y^{2}} d y = \frac{1}{y^{2}} d y = (-1) y^{ - 1} = \frac{1}{3} t^{ ( 3 / 2 ) \ \frac{1}{3} t^{ ( 3 / 2)}}\).
04

Combine the Integrals and Add Constant

Combine the integrals and incorporate the constant of integration: \(-( \frac{1}{ y } ) = \frac{2}{3} t^{3/2} + C\).
05

Solve for y

Isolate y: \(\frac{ - 1}{ y } = \frac{2}{3} t^{ ( 3 / 2 ) + C}\). Therefore, \( y = -(\frac{1}{ c + t^{ ( 3 / 2) }}) = - (\frac{ 3}{ 2 c}) = - (\frac{ 3}{ 2 t^{3/2}}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Separable Differential Equations
A separable differential equation is a type of differential equation in which the variables can be separated on different sides of the equation. This means that you can write the equation so that all instances of one variable are on one side and all instances of the other variable are on the other side. This form makes it easier to integrate and solve. For instance, in the differential equation \(\frac{dy}{dt} = t^{1/2} y^{2}\), we can rewrite it in such a way that allows us to separate the variables and proceed with solving the equation. This leads us to the next important steps of integration and solving for constants.
Integration Techniques
Once we have separated the variables, the next step is to integrate each side of the equation. Integration is a fundamental technique in calculus used to compute the antiderivative of a function. In the given example, for the differential equation \(\frac{dy}{dt} = t^{1/2} y^{2}\), after separation, we have: \(\frac{1}{y^{2}} dy = t^{1/2} dt\). Here, we integrate both sides:
  • For the left side: \( \int \frac{1}{y^{2}} dy = -\frac{1}{y} \)
  • For the right side: \(\frac{ \int t^{1/2} dt = \frac{2}{3} t^{3/2} \)
Through these integration steps, we transform the original equation into a more solvable form.
Constants of Integration
When we integrate each side of the differential equation, we must include a constant of integration on the right-hand side. This constant represents the unknown part of the general solution of the differential equation. For example, after integrating, we obtain: \( - \frac{1}{y} = \frac{2}{3} t^{3/2} + C \). Here, \(C\) is the constant of integration. The value of this constant is usually determined using initial conditions or boundary conditions provided in the problem.
Separation of Variables
The technique of separation of variables is a method used to solve separable differential equations. By isolating each variable on different sides of the equation, we can integrate both sides independently. For the given differential equation \(\frac{dy}{dt} = t^{1/2} y^{2}\), our goal is to rewrite it as: \( \frac{1}{y^{2}} dy = t^{1/2} dt \). This separation allows us to solve the equation step by step. After integrating and solving for the function \(y\), we can express the solution typically in the form \(y = f(t)\). Thus, through separation of variables, integration, and management of the constants of integration, we arrive at a complete solution to the differential equation.

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Most popular questions from this chapter

Some homeowner's insurance policies include automatic inflation coverage based on the U.S. Commerce Department's construction cost index (CCI). Each year, the property insurance coverage is increased by an amount based on the change in the CCI. Let \(f(t)\) be the CCI at time \(t\) years since January 1,1990 , and let \(f(0)=100\). Suppose that the construction cost index is rising at a rate proportional to the CCI and the index was 115 on January 1, 1992. Construct and solve a differential equation satisfied by \(f(t)\). Then, determine when the CCI will reach 200 .

Find an integrating factor for each equation. Take \(t>0\). $$ y^{\prime}+\sqrt{t} y=2(t+1) $$

Solve the given equation using an integrating factor. Take \(t>0\). $$ y^{\prime}+y=2-e^{t} $$

A parachutist has a terminal velocity of \(-176\) feet per second. That is, no matter how long a person falls, his or her speed will not exceed 176 feet per second, but it will get arbitrarily close to that value. The velocity in feet per second, \(v(t)\), after \(t\) seconds satisfies the differential equation \(v^{\prime}(t)=32-k \cdot v(t) .\) What is the value of \(k\) ?

When a certain liquid substance \(A\) is heated in a flask, it decomposes into a substance \(B\) at such a rate (measured in units of \(A\) per hour) that at any time \(t\) is proportional to the square of the amount of substance \(A\) present. Let \(y=f(t)\) be the amount of substance \(A\) present at time \(t .\) Construct and solve a differential equation that is satisfied by \(f(t)\).

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