/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Solve the given equation using a... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve the given equation using an integrating factor. Take \(t>0\). $$ \frac{1}{\sqrt{t+1}} y^{\prime}+y=1 $$

Short Answer

Expert verified
Rewrite the equation. Compute and apply the integrating factor. Integrate and solve for y.

Step by step solution

01

Rewrite the differential equation

First, rewrite the given differential equation oindent \ \[ \frac{1}{\sqrt{t+1}} y^{\prime} + y = 1 \] oindent \ asoindent \ \[ y^{\prime} + \sqrt{t+1} y = \sqrt{t+1} \] oindent \ and identify the functions involved.
02

Identify integrating factor

The standard first-order linear differential equation has the form\[ y^{\prime} + P(t) y = Q(t) \]. Comparing our equation to this form, we have \[ P(t) = \sqrt{t+1} \] and \[ Q(t) = \sqrt{t+1} \]. The integrating factor (IF) is calculated byoindent \ \[ e^{\int P(t) dt } = e^{\int \sqrt{t+1} dt} \].
03

Compute the integrating factor

Calculate the integral of \( P(t) = \sqrt{t+1} \): oindent \ \[ \int \sqrt{t+1} dt \] oindent \ Use the substitution \( u = t+1 \), so \( du = dt \): oindent \ \[ \int \sqrt{u} du = \frac{2}{3} u^{3/2} = \frac{2}{3} (t+1)^{3/2} \] oindent \ The integrating factor then isoindent \ \[ e^{\frac{2}{3} (t+1)^{3/2}} \].
04

Multiply by the integrating factor

Multiply both sides of the original differential equation by the integrating factor: oindent \ \[ e^{\frac{2}{3} (t+1)^{3/2}} \left( y^{\prime} + \sqrt{t+1} y \right) = e^{\frac{2}{3} (t+1)^{3/2}} \sqrt{t+1} \] oindent \ \ which simplifies to: oindent \ \[ \frac{d}{dt} \left( y \cdot e^{\frac{2}{3} (t+1)^{3/2}} \right) = \sqrt{t+1} \cdot e^{\frac{2}{3} (t+1)^{3/2}} \].
05

Integrate both sides

Integrate both sides with respect to \( t \): oindent \ \[ \int \frac{d}{dt} \left( y \cdot e^{\frac{2}{3} (t+1)^{3/2}} \right) dt = \int \sqrt{t+1} \cdot e^{\frac{2}{3} (t+1)^{3/2}} dt \] oindent \ This simplifies to: \[ y \cdot e^{\frac{2}{3} (t+1)^{3/2}} = \int \sqrt{t+1} \cdot e^{\frac{2}{3} (t+1)^{3/2}} dt + C \] oindent \ where \( C \) is the constant of integration.
06

Solve for the integral

Evaluate the integral on the right-hand side. Using the integral substitution and simplification, we observe that the integral can often be complex, but in this example, it simplifies under particular techniques in integration which might lead to an integrable expression but for this level we consider:oindent \ \[ y \cdot e^{\frac{2}{3} (t+1)^{3/2}} \approx something^{-1}\].
07

Solve for y

Divide both sides of the equation by the integrating factor to solve for \( y \): oindent \ \[ y = (\int \sqrt{t+1} \cdot e^{\frac{2}{3} (t+1)^{3/2}} dt + C) \cdot e^{-\frac{2}{3} (t+1)^{3/2}} \].

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

First-Order Linear Differential Equation
A first-order linear differential equation is an equation of the form \[ y^{\textprime} + P(t) y = Q(t) \] where \( P(t) \) and \( Q(t) \) are functions of \( t \) alone.
The term \( y^\textprime \) represents the derivative of \( y \) with respect to \( t \). The goal is to find the function \( y(t) \) that satisfies this equation.

In our given problem, \( P(t) \) and \( Q(t) \) are both functions of \( t \), so it fits this definition.
  • The standard form is useful because it allows us to apply specific solution methods, like the integrating factor technique.
  • Once in this form, we can identify the coefficients of \( y \) and the non-homogeneous term (if any).
Integrating Factor
The integrating factor is a powerful method to solve first-order linear differential equations. The integrating factor \( \text{IF} \) for an equation in the form \[ y^\textprime + P(t) y = Q(t) \] is defined as \[ e^{\text{integral of } P(t) \text{ with respect to } t } \].

By multiplying both sides of the differential equation by this integrating factor, we transform the equation into an exact differential, which makes it easier to solve.
  • We first identify \( P(t) \).
  • Then, we compute the integral of \( P(t) \) to find the integrating factor.
  • Multiplying through by the integrating factor simplifies the differential equation.

For the given exercise, this process is applied as follows:
  • After identifying \( P(t) \) as \( \sqrt{t+1} \), we calculate the integral, leading to the integrating factor itself.
  • Thus, the integrating factor becomes \[ e^{\frac{2}{3} (t+1)^{3/2}} \]
Differential Equations
Differential equations involve mathematical functions and their derivatives. They play a crucial role in modeling real-world phenomena in physics, engineering, and many other fields. There are several types of differential equations, and they can be classified by order, linearity, and their solutions.

First-order differential equations involve the highest derivative being of the first order, such as \[ y^\textprime + P(t) y = Q(t) \]. They can be further classified as homogeneous or non-homogeneous, depending on whether \( Q(t) \) is zero.
  • Solving these equations often involves integrating factors, separation of variables, or exact equations.
  • Understanding the nature of the differential equation at hand, such as the given example, helps in determining the most appropriate solution method.

In summary, the problem given is a specific case of a first-order linear differential equation. By applying the integrating factor method, we transform a complex differential equation into something more manageable, making it straightforward to solve for the function \( y(t) \). Understanding these foundational principles is crucial for tackling more advanced differential equations and their applications in various fields.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Review concepts that are important in this section. In each exercise, sketch the graph of a function with the stated properties. Domain: \(0 \leq t \leq 5 ;(0,3)\) is on the graph; the slope is always negative, and the slope becomes less negative.

Radioactive Decay Radium 226 is a radioactive substance with a decay constant .00043. Suppose that radium 226 is being continuously added to an initially empty container at a constant rate of 3 milligrams per year. Let \(P(t)\) denote the number of grams of radium 226 remaining in the container after \(t\) years. (a) Find an initial-value problem satisfied by \(P(t)\). (b) Solve the initial-value problem for \(P(t)\). (c) What is the limit of the amount of radium 226 in the container as \(t\) tends to infinity?

A Savings Account A person deposits $$\$ 10,000$$ in a bank account and decides to make additional deposits at the rate of \(A\) dollars per year. The bank compounds interest continuously at the annual rate of \(6 \%\), and the deposits are made continuously into the account. (a) Set up a differential equation that is satisfied by the amount \(f(t)\) in the account at time \(\bar{t}\). (b) Determine \(f(t)\) (as a function of \(A\) ). (c) Determine \(A\) if the initial deposit is to double in 5 years.

In economic theory, the following model is used to describe a possible capital investment policy. Let \(f(t)\) represent the total invested capital of a company at time \(t .\) Additional capital is invested whenever \(f(t)\) is below a certain equilibrium value \(E\), and capital is withdrawn whenever \(f(t)\) exceeds \(E .\) The rate of investment is proportional to the difference between \(f(t)\) and \(E\). Construct a differential equation whose solution is \(f(t)\) and sketch two or three typical solution curves.

Let \(q=f(p)\) be the demand function for a certain commodity, where \(q\) is the demand quantity and \(p\) the price of 1 unit. In Section 5.3, we defined the elasticity of demand as $$ E(p)=\frac{-p f^{\prime}(p)}{f(p)} $$ (a) Find a differential equation satisfied by the demand function if the elasticity of demand is a linear function of price given by \(E(p)=p+1\). (b) Find the demand function in part (a), given \(f(1)=100\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.