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A continuous annuity is a steady stream of money that is paid to some person. Such an annuity may be established, for example, by making an initial deposit in a savings account and then making steady withdrawals to pay the continuous annuity. Suppose that an initial deposit of $$\$ 5400$$ is made into a savings account that earns \(5 \frac{1}{2} \%\) interest compounded continuously, and immediately continuous withdrawals are begun at the rate of $$\$ 300$$ per year. Set up the differential equation that is satisfied by the amount \(f(t)\) of money in the account at time \(t .\) Sketch the solution.

Short Answer

Expert verified
The differential equation is: \[ \frac{df}{dt} = 0.055 f(t) - 300 \]. Start with an initial amount of $$5400$$.

Step by step solution

01

Understand the Problem

An initial deposit of $$\text{ } 5400$$ is made in a savings account with a continuous interest rate of \ 5.5 \. Immediate withdrawals of $$\text{ } 300$$ per year begin right away. We need to find the differential equation for the amount in the account over time, denoted as \( f(t) \).
02

Define the Variables

Let \( f(t) \) be the function representing the amount of money in the account at time \( t \) (in years).
03

Write Down the Interest Earned

The continuous interest earned on the account can be represented using the rate \( r = 0.055 \) (since 5.5% as a decimal is 0.055). The rate of change of the amount in the account due to interest is \( 0.055 f(t) \).
04

Write Down the Withdrawals

Withdrawals are taking place continuously at a constant rate of $300 per year. Thus, the negative contribution to \( f(t) \) from withdrawals is a constant \( 300 \).
05

Combine to Form the Differential Equation

The total rate of change of the function \( f(t) \) is the summation of the interest earned and the amount withdrawn. This gives us the differential equation: \[ \frac{df}{dt} = 0.055 f(t) - 300 \]
06

Solve the Differential Equation

This is a first-order linear differential equation which can be solved using the integrating factor method or other appropriate methods. However, the exercise specifically asks only for the setup of the differential equation and its sketch.
07

Sketch the Solution

To visualize the solution, note that if withdrawals are greater than the interest earned, the account balance declines over time. Plotting this differential equation would show an initial amount starting at $$\text{ } 5400$$ gradually decreasing, based on withdrawals over time. Exact solution and sketching are beyond our current steps but understanding the general trend is essential.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

differential equation
A differential equation is a mathematical equation that involves functions and their derivatives. It describes how a particular quantity changes over time. In this problem, we are concerned with how the amount of money in a savings account changes. The differential equation incorporates both the continuous interest earned and the withdrawals made from the account. This helps describe the overall behavior of the account balance over time.

A good example is given by the differential equation derived in the exercise: \[\begin{equation} \frac{df}{dt} = 0.055 f(t) - 300 . \text(Here, \frac{df}{dt} denotes the rate of change of the account balance over time t.)\end{equation}\]

This formulation ensures that all factors influencing the account are considered, including interest growth and steady withdrawals.
continuous interest
Continuous interest means that the interest on the savings account compounds continuously, leading to exponential growth. Unlike simple or annual compound interest, continuous compounding maximizes the effect of interest over time.

The formula for continuous interest is given by: \[\begin{equation} A = P e^{rt}\end{equation}\]where A is the amount in the account after time t, P is the initial deposit, r is the interest rate, and e represents the base of the natural logarithms.

In the exercise, the continuous interest shows as part of the differential equation. The growth rate of the account balance due to interest is given by: \[\begin{equation} 0.055f(t)\end{equation}\]

This term reflects how the account value, f(t), increases over time just because of the continuous interest compounded at a rate of 5.5%.
withdrawal rate
Withdrawal rate refers to the rate at which money is taken out of the savings account. It is a steady, continuous inflow, impacting the overall balance negatively. In our case, withdrawals are happening at a constant rate of $300 per year, creating a steady decrease in the account balance.

With a continuous annuity, this withdrawal rate is reflected in the differential equation as a constant term: \[\begin{equation} -300\end{equation}\]

The negative sign indicates that this is an outflow or reduction in the account balance. This makes it clear that while interest is trying to grow the balance, withdrawals continuously pull it down, creating a dynamic balance in the account.
first-order linear differential equation
A first-order linear differential equation is a type of differential equation defined by its order and linearity. It involves the first derivative of the function and takes the form: \[\begin{equation} \frac{df}{dt} + P(t)f(t) = Q(t)\end{equation}\]

In our case, the equation: \[\begin{equation} \frac{df}{dt} = 0.055 f(t) - 300\end{equation}\]

is first-order because it involves the first derivative, \[\begin{equation}\frac{df}{dt}\end{equation}\]and it is linear because it can be expressed in the standard linear form.First-order linear differential equations are often solved using an integrating factor, ensuring the solution reflects both the growth and decay components (interest vs. withdrawals) impacting the account balance.Understanding this type of equation is crucial for modeling various continuous processes, like our continuous annuity scenario.

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Most popular questions from this chapter

The fish population in a pond with carrying capacity 1000 is modeled by the logistic equation $$ \frac{d N}{d t}=\frac{.4}{1000} N(1000-N) $$ Here, \(N(t)\) denotes the number of fish at time \(t\) in years. When the number of fish reached 250, the owner of the pond decided to remove 50 fish per year. (a) Modify the differential equation to model the population of fish from the time it reached 250 . (b) Plot several solution curves of the new equation, including the solution curve with \(N(0)=250\). (c) Is the practice of catching 50 fish per year sustainable or will it deplete the fish population in the pond? Will the size of the fish population ever come close to the carrying capacity of the pond?

Use Euler's method with \(n=2\) on the interval \(0 \leq t \leq 1\) to approximate the solution \(f(t)\) to \(y^{\prime}=t^{2} y, y(0)=-2\). In particular, estimate \(f(1)\).

The Federal Housing Finance Board reported that the national average price of a new one-family house in 2012 was $$\$ 278,900$$. At the same time, the average interest rate on a conventional 30 -year fixedrate mortgage was \(3.1 \% .\) A person purchased a home at the average price, paid a down payment equal to \(10 \%\) of the purchase price, and financed the remaining balance with a 30 -year fixed-rate mortgage. Assume that the person makes payments continuously at a constant annual rate \(A\) and that interest is compounded continuously at the rate of \(3.1 \% .\) (Source: The Federal Housing Finance Board, www.fhfb.gov.) (a) Set up a differential equation that is satisfied by the amount \(f(t)\) of money owed on the mortgage at time \(t\) (b) Determine \(A\), the rate of annual payments, that is required to pay off the loan in 30 years. What will the monthly payments be? (c) Determine the total interest paid during the 30 -year term mortgage.

The differential equation \(y^{\prime}=2 t y+e^{t^{2}}, y(0)=5\), has solution \(y=(t+5) e^{t^{2}} .\) In the following table, fill in the second row with the values obtained from the use of a numerical method and the third row with the actual values calculated from the solution. What is the greatest difference between corresponding values in the second and third rows? $$ \begin{array}{c|c|c|c|c|c|c|c|c|c|c|c} t_{i} & 0 & .2 & .4 & .6 & .8 & 1 & 1.2 & 1.4 & 1.6 & 1.8 & 2 \\ \hline y_{i} & 5 & & & & & & & & & & \\ \hline y & 5 & 5.412 & & & & & & & & & 382.2 \\ \hline \end{array} $$

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