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In Exercises \(1-28\), compute the numbers. $$ 1^{100} $$

Short Answer

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Step by step solution

01

- Understand the Problem

The task is to compute the number when 1 is raised to the power of 100.
02

- Recall the Exponent Properties

Recall that any number raised to the power of zero is 1, and for any number raised to any power, if the base is 1, the result is always 1.
03

- Apply the Property

Since the base in this problem is 1, apply the property that 1 raised to any power remains 1: \(1^{100} = 1\).
04

- Confirm the Result

Verify by logical reasoning: Multiplying 1 by itself any number of times will always give 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponent Properties
Exponent properties are essential in simplifying expressions and solving equations involving powers. These properties include:
1. **Product of Powers Property**: When multiplying two numbers with the same base, you add the exponents: \(a^m \times a^n = a^{m+n}\).
2. **Power of a Power Property**: When raising a power to another power, you multiply the exponents: \( (a^m)^n = a^{m \times n}\).
3. **Power of a Product Property**: When raising a product to a power, you distribute the exponent to each factor in the product: \( (ab)^n = a^n \times b^n\).
4. **Quotient of Powers Property**: When dividing two numbers with the same base, you subtract the exponents: \( \frac{a^m}{a^n} = a^{m-n}\), where a is not zero.
5. **Zero Exponent Rule**: Any non-zero number raised to the power of zero equals one: \(a^0 = 1\).
These properties help in handling expressions with exponents more effectively and can simplify complex problems.
Base and Exponent
In exponentiation, the base and the exponent play distinct roles.
The **base** is the number that gets multiplied. The **exponent** (or power) tells you how many times to multiply the base by itself. For instance, in \(2^3\), 2 is the base and 3 is the exponent. This means you multiply 2 by itself three times: \(2 \times 2 \times 2 = 8\).
Understanding the roles of the base and exponent is crucial for solving problems involving powers and exponents. Practice recognizing and separating these components in different problems to make it easier to apply the correct exponent properties.
Powers of One
One of the simplest but often overlooked exponent properties is the rule for the power of one. If the **base** is 1, no matter what the **exponent** is, the result will always be 1. This is because multiplying 1 by itself any number of times does not change its value.
For example:
  • \(1^5 = 1 \times 1 \times 1 \times 1 \times 1 = 1\)
  • \(1^{100} = 1 \times 1 \times 1 \text{(repeated 100 times)} = 1\)
  • \(1^{1000} = 1 \times 1 \text{(repeated 1000 times)} = 1\)
This property makes calculations involving base 1 very straightforward. It simplifies problems significantly and allows us to quickly find the answer without extensive multiplication.

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Most popular questions from this chapter

During the first \(\frac{1}{2}\) hour, the employees of a machine shop prepare the work area for the day's work. After that, they turn out 10 precision machine parts per hour, so the output after \(t\) hours is \(f(t)\) machine parts, where \(f(t)=10\left(t-\frac{1}{2}\right)=10 t-5, \frac{1}{2} \leq t \leq 8\). The total cost of producing \(x\) machine parts is \(C(x)\) dollars, where \(C(x)=.1 x^{2}+25 x+200\). (a) Express the total cost as a (composite) function of \(t\). (b) What is the cost of the first 4 hours of operation?

Velocity When a car is moving at \(x\) miles per hour and the driver decides to slam on the brakes, the car will travel \(x+\frac{1}{20} x^{2}\) feet. (The general formula is \(f(x)=a x+b x^{2}\), where the constant \(a\) depends on the driver's reaction time and the constant \(b\) depends on the weight of the car and the type of tires.) If a car travels 175 feet after the driver decides to stop, how fast was the car moving? (Source: Applying Mathematics: A Course in Mathematical Modelling.)

Compute the numbers. \(9^{1.5}\)

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