/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 Find the volume generated by rot... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the volume generated by rotating the area bounded by the graphs of each set of equations around the \(y\) -axis. $$ y=\sqrt[3]{x}, x=1, x=8 $$

Short Answer

Expert verified
The volume is \( \frac{62\pi}{5} \) cubic units.

Step by step solution

01

Identify the Functions and Bounds

We have the function \(y = \sqrt[3]{x}\) and we want to find the volume of the solid formed by rotating the area between this curve and the lines \(x = 1\) and \(x = 8\) around the \(y\)-axis.
02

Express x in terms of y

To use the method of cylindrical shells, we need to express \(x\) in terms of \(y\). From \(y = \sqrt[3]{x}\), we can write \(x = y^3\).
03

Set up the Integral for Volume

We use the formula for the volume of a solid of revolution around the \(y\)-axis using cylindrical shells: \[ V = \int_{c}^{d} 2\pi x f(x) \, dx \]In this case, our bounds for \(y\) are \(y = \sqrt[3]{1} = 1\) to \(y = \sqrt[3]{8} = 2\). Thus, the integral becomes \[ V = \int_{1}^{2} 2\pi (y^3)(y) \, dy = 2\pi \int_{1}^{2} y^4 \, dy \]
04

Solve the Integral

First, compute the integral: \[ \int y^4 \, dy = \frac{y^5}{5} \]So, \[ V = 2\pi \left[ \frac{y^5}{5} \right]_{1}^{2} = 2\pi \left( \frac{2^5}{5} - \frac{1^5}{5} \right) \] Calculate \(2^5 = 32\) and \(1^5 = 1\), so\[ V = 2\pi \left( \frac{32}{5} - \frac{1}{5} \right) = 2\pi \left( \frac{31}{5} \right) \] Finally, calculate: \[ V = \frac{62\pi}{5} \]
05

Simplify the Result

The calculated volume is \( \frac{62\pi}{5} \), which is approximately 38.986 cubic units if evaluated numerically (optional for confirmation).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cylindrical Shells Method
The cylindrical shells method is a powerful technique for finding the volume of a solid of revolution. This method is particularly useful when rotating a region around an axis and the region is defined in terms of another variable. In this exercise, we're revolving the region around the y-axis.It involves breaking down the solid into thin cylindrical shells. Imagine wrapping a strip around the y-axis, which forms a shell. The volume of each shell is derived from its circumference, height, and thickness. By integrating these elements over a specified range, you can find the total volume of the solid.Volume using the cylindrical shells method is calculated with:\[ V = \int_{c}^{d} 2\pi x f(x) \, dx \] Here, - **2Ï€x**: The circumference of an elemental shell.- **f(x)**: Height of the shell, given by the function.- **dx**: Thickness of the shell.For our particular problem, we had to turn the given function and bounds into an appropriate form for use with this method, ultimately integrating over suitable limits derived from the functions given.
Integral Calculus
Integral calculus acts as the backbone when computing the volume of a solid using methods like cylindrical shells. In essence, it provides a tool to sum infinitely many tiny volumes into an exact total.The central concept to grasp is that we're integrating over a range to accumulate these small volumes. That range, in our exercise, was for **y-values** between 1 and 2. Integrating the specific function indicated how those tiny volumes accumulate as you move along the y-axis.Here, the core steps for solving the integral include:- Transform the original function, in this case, switching from **x to y**. That required substituting **x = y^3** based on the original function \( y = \sqrt[3]{x} \).- Set up the integral with these expressions, collecting all parts needed for the cylindrical shell volume formula.- Solve the integral by computing the expression, connecting calculus theory to practical computation.Successfully completing this integration reveals the total volume of the solid after revolution about the y-axis.
Solids of Revolution
Solids of revolution occur when a region in the coordinate plane is revolved around an axis, generating a three-dimensional shape. Understanding this geometric transformation is crucial for applying techniques like the cylindrical shells method effectively.In this specific situation, the region bounded by \( y = \sqrt[3]{x} \), \( x = 1 \), and \( x = 8 \) was revolved around the y-axis to form the solid.Key considerations include:- **Identification of Bounds**: Recognize where the function and the axis bound the region. Our bounds from **x** translated to bounds in **y** thanks to our function's transformation.- **Choice of Method**: The cylindrical shells method was particularly advantageous here, simplifying the integration process when the region is around the **y-axis**.- **Result Analysis**: After computing the volume, understanding the shape intuitively ensures the volume makes sense considering the formation of the solid.Grasping solids of revolution distinctly helps in visualizing complex problems, turning abstract calculus into more tangible geometric reasoning.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Solve for \(y .\) \(y^{\prime}=7 y^{-2} ; \quad y=3\) when \(x=1\)

Gusto Stick is a professional baseball player who has just become a free agent. His attorney begins negotiations with an interested team by asking for a contract that provides Gusto with an income stream given by \(R_{1}(t)=800,000+340,000 t,\) over \(10 \mathrm{yr}\), where \(t\) is in years. (Round all answers to the nearest \(\$ 100 .)\) a) What is the accumulated future value of the offer. assuming an interest rate of \(5 \%,\) compounded continuously? b) What is the accumulated present value of the offer, assuming an interest rate of \(5 \%,\) compounded continuously? c) The team counters by offering an income stream given by \(R_{2}(t)=600,000+210,000 t\). What is the accumulated present value of this counteroffer? d) Gusto comes back with a demand for an income stream given by \(R_{3}(t)=1,000,000+250,000 t\). What is the accumulated present value of this income stream? e) Gusto signs a contract for the income stream in part (d) but decides to live on \(\$ 500,000\) each year, investing the rest at \(5 \%,\) compounded continuously. What is the accumulated future value of the remaining income, assuming an interest rate of \(5 \%,\) compounded continuously?

Median. Let \(x\) be a continuous random variable over \([a, b]\) with probability density function \(f .\) Then the median of the \(x\) -values is that number \(m\) for which $$ \int_{a}^{m} f(x) d x=\frac{1}{2} $$ Find each median. $$ f(x)=\frac{1}{2} x,[0,2] $$

Mail orders. The number of orders, \(N\), received daily by an online vendor of used Blu-ray discs is normally distributed with mean 250 and standard deviation 20 The company has to hire extra help or pay overtime on those days when the number of orders received is 300 or higher. On what percentage of days will the company have to hire extra help or pay overtime?

Let \(x\) be a continuous random variable with a standard normal distribution. Using Table A, find each of the following. a) \(P(-1 \leq x \leq 1)\) b) What percentage of the area is from -1 to \(1 ?\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.