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Find the volume generated by rotating the area bounded by the graphs of each set of equations around the \(x\) -axis. $$ y=x, x=0, x=1 $$

Short Answer

Expert verified
The volume is \( \frac{\pi}{3} \).

Step by step solution

01

Understand the Region

We need to visualize the region bounded by the equations in the xy-plane. The line \( y = x \) from \( x = 0 \) to \( x = 1 \) is a straight line forming a right triangle with the x-axis. The base runs from \( x = 0 \) to \( x = 1 \) on the x-axis, and the height of the triangle is the same, reaching up to \( y = 1 \).
02

Set Up the Volume Integral

To find the volume of the solid generated by rotating the region around the x-axis, we use the disk method. The formula for the volume \( V \) of a solid of revolution about the x-axis is: \[ V = \pi \int_{a}^{b} [f(x)]^2 \, dx \] Here, \( f(x) = x \), \( a = 0 \), and \( b = 1 \).
03

Integrate to Find the Volume

Substitute the function and limits into the integral. \[ V = \pi \int_{0}^{1} (x)^2 \, dx \] To evaluate the integral, compute \int x^2 \, dx: \[ \int x^2 \, dx = \frac{x^3}{3} \] Evaluate this from 0 to 1: \[ V = \pi \left[ \frac{x^3}{3} \right]_{0}^{1} = \pi \left( \frac{1^3}{3} - \frac{0^3}{3} \right) \] \[ V = \frac{\pi}{3} \]
04

State the Volume

The volume of the solid generated by rotating the region bounded by \( y = x \), \( x = 0 \), and \( x = 1 \) around the x-axis is \( \frac{\pi}{3} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Disk Method
The Disk Method is a technique used to find the volume of a solid of revolution. This method is particularly useful when you are revolving a region around one of the coordinate axes. Imagine breaking up that region into many thin slices, shaped like disks. Each disk has a small thickness, typically denoted by \( dx \). The idea is to sum up the volumes of all these disks to determine the entire volume of the solid.To apply the Disk Method:
  • Visualize the region to be revolved. This helps you see how each slice contributes to the solid as a whole.
  • Find the radius of each disk, which is determined by the function that describes the boundary of your region. In this situation, the function is \( f(x) = x \).
  • Use the formula for the volume of a disk, which uses the area formula \( \pi [f(x)]^2 \). Multiply it by the thickness, \( dx \), and integrate from the lower to the upper boundary of your region.
This results in the formula: \[ V = \pi \int_{a}^{b} [f(x)]^2 \, dx \]This integrates the volumes of all the disks to give the whole volume of the solid of revolution.
Definite Integral
The definite integral is a powerful mathematical tool used to compute the net area under a curve over a specific interval, \([a, b]\). When applied to the Disk Method, it helps in calculating the total volume of a solid. The bounds \(a\) and \(b\) describe the limits of integration, which denote where the accumulation starts and ends along the x-axis.Here's how a definite integral works in this context:
  • The integral symbol \( \int \) represents the summation process. It adds up infinitely small quantities from the starting point \(a\) to the endpoint \(b\), across the interval.
  • The integrand, which is \((x)^2\) in this situation, describes the function whose area or, in this instance, volume is being calculated.
  • To evaluate, apply the rules of integration to find an antiderivative (a function whose derivative results in the original integrand) and calculate it at the limits \(a\) and \(b\).
For example, the integral \[ \int_{0}^{1} x^2 \, dx = \frac{x^3}{3} \] when evaluated from 0 to 1 results in \( \frac{1}{3} - 0 \), revealing the total volume contribution of the specified interval.
Function Rotation
Function rotation involves creating a three-dimensional solid by revolving a two-dimensional region around an axis. This transformation is what allows us to apply concepts like the Disk Method to find the volume of these solids.Key aspects of Function Rotation include:
  • Choosing the Axis: Decide whether the axis of rotation is horizontal or vertical, which influences the choice of integration method and setup.
  • Determining the Radius: The radius of rotation is the distance from the axis to the function or to the edge of the region being revolved. In this problem, it's simply the value of \(x\), the function itself.
  • Visualizing the Solid: Understanding the shape and boundaries of the resulting three-dimensional object helps in setting up the correct calculus problem and ensuring the accuracy of integration limits.
By rotating a function like \(y = x\) around the x-axis from \(x = 0\) to \(x = 1\), you form a solid that resembles a cone or trumpet-like shape. Calculating its volume helps in understanding how areas in two dimensions translate into spaces in three dimensions.

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Most popular questions from this chapter

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