Chapter 4: Problem 81
Solve each integral. Each can be found using rules developed in this section, but some algebra may be required. $$ \int(t+1)^{3} d t $$
Short Answer
Expert verified
\( \int (t+1)^3 \, dt = \frac{(t+1)^4}{4} + C \).
Step by step solution
01
Identify the Integral Form
The integral given is \( \int (t+1)^3 \, dt \). Recognize that this integral is in the form \( \int (u)^n \, du \), where \( u = t+1 \) and \( n = 3 \).
02
Apply the Power Rule for Integration
The power rule for integration states that \( \int u^n \, du = \frac{u^{n+1}}{n+1} + C \) where \( n eq -1 \). For our integral, this implies \( \int (t+1)^3 \, dt = \frac{(t+1)^{3+1}}{3+1} + C \).
03
Evaluate the Integral
Substitute \( n = 3 \) into the formula: \( \int (t+1)^3 \, dt = \frac{(t+1)^4}{4} + C \). This results from performing the integration using the power rule.
04
Simplify the Expression
Our final answer is \( \frac{(t+1)^4}{4} + C \). This is a simplified form of the integral using the power rule.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule for Integration
The Power Rule for Integration is a fundamental technique in integral calculus that simplifies the process of finding integrals of polynomial functions. It is particularly useful when dealing with expressions of the form \( u^n \), where \( u \) is a variable expression, and \( n \) is a real number that's not equal to -1. In our given expression \( \int (t+1)^3 \, dt \), the power rule helps us easily find the antiderivative by transforming it into the expression \( \frac{u^{n+1}}{n+1} + C \), where \( C \) is the constant of integration. When using the power rule, remember:
- Identify the base expression \( u \) and exponent \( n \) in your integral.
- Ensure \( n eq -1 \) to apply the rule directly.
- Add 1 to the exponent \( n \) and divide by the same value \( n+1 \).
- Don't forget to add the constant of integration \( C \) at the end.
Integral Calculus
Integral Calculus is a branch of calculus focusing on the accumulation of quantities and the areas under and between curves. It fundamentally involves finding an antiderivative, or integral, of a function. In the context of our exercise, we employ these concepts to solve for \( \int (t+1)^3 \, dt \).Integral calculus assists in:
- Determining total quantities from rates of change.
- Calculating areas under curves, which is useful in many applied fields such as physics and engineering.
- Analyzing how different functions accumulate or distribute values over an interval.
Indefinite Integral
An indefinite integral represents a family of functions and is the inverse process of differentiation. Unlike definite integrals that calculate a specific numerical value, indefinite integrals give a generalized formula containing an arbitrary constant \( C \). Consider the expression \( \int (t+1)^3 \, dt \), which aims at determining the antiderivative of the polynomial function \((t+1)^3\):
- The notation \( \int \) signifies integration, looking for a function whose derivative would result in \( (t+1)^3 \).
- The result is \( \frac{(t+1)^4}{4} + C \), capturing all potential forms of the original function including constants.
- \( C \) is crucial because differentiating a constant leads to zero, thus maintaining the family of antiderivatives.