Chapter 4: Problem 37
Find the average function value over the given interval. $$ y=e^{-x} ; \quad[0,1] $$
Short Answer
Expert verified
1 - \frac{1}{e}
Step by step solution
01
Identify the Formula for Average Function Value
The average value of a function \( y=f(x) \) on an interval \([a,b]\) is given by the formula \( f_{\text{avg}} = \frac{1}{b-a} \int_{a}^{b} f(x) \, dx \). For this problem: \( f(x) = e^{-x} \), \( a = 0 \), and \( b = 1 \).
02
Set Up the Integral
Substitute the values into the formula: \( f_{\text{avg}} = \frac{1}{1-0} \int_{0}^{1} e^{-x} \, dx \). Simplifying this gives \( f_{\text{avg}} = \int_{0}^{1} e^{-x} \, dx \).
03
Integrate the Function
To perform the integration, note that the integral of \( e^{-x} \) is \( -e^{-x} \). So, evaluate \( \int e^{-x} \, dx = -e^{-x} + C \).
04
Evaluate the Definite Integral
Compute \( \int_{0}^{1} e^{-x} \, dx = \left[-e^{-x} \right]_{0}^{1} = \left(-e^{-1}\right) - \left(-e^{0}\right) = -\frac{1}{e} + 1 \).
05
Simplify the Result
Simplifying \( 1 - \frac{1}{e} \), we find \( f_{\text{avg}} = 1 - \frac{1}{e} \).
06
Conclude with the Average Value
Hence, the average value of the function \( y = e^{-x} \) over the interval \([0,1]\) is \( 1 - \frac{1}{e} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definite Integral
A definite integral is a fundamental tool in calculus that allows us to calculate the signed area under a curve between two points on the x-axis. This concept is pivotal when determining the average value of a function over a specific interval.
The process starts by setting up the integral \[ \int_{a}^{b} f(x) \, dx \] where \(a\) and \(b\) are the lower and upper bounds, respectively. In essence, a definite integral not only computes the cumulative "amount" of a function over an interval but also does it in a way that accounts for both positive and negative area contributions.
This characteristic makes it a versatile and powerful tool for understanding various quantities in mathematics and applied sciences. In our exercise, computing the definite integral of \( e^{-x} \) from 0 to 1 helps us find the function's value over that interval.
The process starts by setting up the integral \[ \int_{a}^{b} f(x) \, dx \] where \(a\) and \(b\) are the lower and upper bounds, respectively. In essence, a definite integral not only computes the cumulative "amount" of a function over an interval but also does it in a way that accounts for both positive and negative area contributions.
This characteristic makes it a versatile and powerful tool for understanding various quantities in mathematics and applied sciences. In our exercise, computing the definite integral of \( e^{-x} \) from 0 to 1 helps us find the function's value over that interval.
Exponential Function
Exponential functions are defined by their continually increasing or decreasing rate of change. In the form \( f(x) = a^x \) or \( f(x) = e^x \), these functions grow or decay at a rate proportional to their current value. Understanding exponential functions is critical as they frequently model real-world phenomena like population growth or radioactive decay.
In our exercise, the function in question is \( y = e^{-x} \), which is a classic example of exponential decay. This decay means as \(x\) increases, \(e^{-x}\) decreases, approaching zero. While its values diminish quickly, when integrated, each slice or value can still accumulate in a significant way over an interval.
In our exercise, the function in question is \( y = e^{-x} \), which is a classic example of exponential decay. This decay means as \(x\) increases, \(e^{-x}\) decreases, approaching zero. While its values diminish quickly, when integrated, each slice or value can still accumulate in a significant way over an interval.
Integration Techniques
Integration is the process of finding the integral of a function, which is essentially the reverse operation of differentiation. Various techniques can be employed to perform integration, each suitable for different types of functions and problems.
For exponential functions like \( e^{-x} \), a straightforward integration can be conducted as these functions tend to lend themselves to simple integration rules. For example, \[ \int e^{-x} \, dx = -e^{-x} + C \] is a fundamental result derived from the derivative of \(-e^{-x}\).
This integration helps us reintegrate an exponential term across a defined boundary, which when combined with the process of definite integration, allows us to arrive at a concrete numerical value that represents the average or total effect of the function over a given interval.
For exponential functions like \( e^{-x} \), a straightforward integration can be conducted as these functions tend to lend themselves to simple integration rules. For example, \[ \int e^{-x} \, dx = -e^{-x} + C \] is a fundamental result derived from the derivative of \(-e^{-x}\).
This integration helps us reintegrate an exponential term across a defined boundary, which when combined with the process of definite integration, allows us to arrive at a concrete numerical value that represents the average or total effect of the function over a given interval.