Chapter 4: Problem 37
Evaluate each integral. Then state whether the result indicates that there is more area above or below the \(x\) -axis or that the areas above and below the axis are equal. $$ \int_{-1}^{1}\left(x^{3}-3 x\right) d x $$
Short Answer
Expert verified
The integral evaluates to 0, meaning the areas above and below the x-axis are equal.
Step by step solution
01
Understanding the Function
The given function is \( f(x) = x^3 - 3x \). This is a cubic polynomial, which can have sections where it is above or below the x-axis. Our goal is to evaluate the definite integral from \(-1\) to \(1\) and determine if there is more area above or below the x-axis.
02
Set Up the Integral
We want to compute the definite integral: \[ \int_{-1}^{1} (x^3 - 3x) \, dx \]. This will involve finding an antiderivative of the function \( x^3 - 3x \).
03
Find the Antiderivative
The antiderivative of \( x^3 \) is \( \frac{x^4}{4} \) and the antiderivative of \(-3x\) is \(-\frac{3x^2}{2} \). Therefore, an antiderivative of \( x^3 - 3x \) is \( F(x) = \frac{x^4}{4} - \frac{3x^2}{2} \).
04
Evaluate the Definite Integral
Use the Fundamental Theorem of Calculus to evaluate \[ \left[ \frac{x^4}{4} - \frac{3x^2}{2} \right]_{-1}^{1} = \left( \frac{1^4}{4} - \frac{3 \cdot 1^2}{2} \right) - \left( \frac{(-1)^4}{4} - \frac{3 \cdot (-1)^2}{2} \right). \] Simplifying each term gives \( \frac{1}{4} - \frac{3}{2} - (\frac{1}{4} - \frac{3}{2}) \).
05
Simplify the Result
The values \( \left( \frac{1}{4} - \frac{3}{2} \right) - \left( \frac{1}{4} - \frac{3}{2} \right) \) give \( -\frac{5}{4} - (-\frac{5}{4}) = 0 \). This implies that the areas above and below the x-axis within the interval are equal.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cubic Polynomial
A cubic polynomial is a polynomial of degree three, which means its highest power of the variable is three. In general, a cubic polynomial is expressed in the form \( ax^3 + bx^2 + cx + d \), where \( a, b, c, \text{ and } d \) are constants and \( a eq 0 \). These types of polynomials have unique characteristics that define their behavior.
- Shape: The graph of a cubic polynomial is an S-shaped curve, with potential for one or two turning points where it can go from increasing to decreasing or vice versa.
- Roots: A cubic polynomial might have up to three real roots, corresponding to the x-intercepts of the graph.
- Sign changes: The function may cross the x-axis multiple times, resulting in regions above and below the axis.
Fundamental Theorem of Calculus
The Fundamental Theorem of Calculus is a central theorem that links differentiation and integration, two main concepts in calculus. It consists of two parts that provide a powerful way to evaluate definite integrals.
- Part 1: This part states that the integral of a function gives the accumulation of the area under the curve and is related to its antiderivative. If \( F \) is an antiderivative of \( f \) on an interval, then \( \int_{a}^{b} f(x) \, dx = F(b) - F(a) \).
- Part 2: It suggests that if \( f \) is continuous on \([a, b]\), then its antiderivative \( F \) is also continuous, and the rate of change of the accumulation function is the original function itself.
Antiderivative
An antiderivative, also known as an indefinite integral, of a function is a new function whose derivative is the original function. Finding an antiderivative is the reverse process of differentiation.
- Basic Concept: If \( F(x) \) is an antiderivative of \( f(x) \), then \( F'(x) = f(x) \). This means differentiating \( F(x) \) will return \( f(x) \).
- General Form: The most general form of an antiderivative includes a constant \( C \), written as \( F(x) + C \), because the derivative of a constant is zero.
- Finding Antiderivatives: The process of finding an antiderivative involves rules such as power rule: the antiderivative of \( x^n \) is \( \frac{x^{n+1}}{n+1} + C \) if \( n eq -1 \).