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91Ó°ÊÓ

Find the area under the given curve over the indicated interval. $$ y=4 ; \quad[1,3] $$

Short Answer

Expert verified
The area under the curve \(y = 4\) over the interval \([1, 3]\) is 8 square units.

Step by step solution

01

Understand the Problem

The problem asks us to find the area under the constant function \(y = 4\) over the interval \([1, 3]\). This means we are looking for the area of a region defined by a horizontal line at \(y = 4\) from \(x = 1\) to \(x = 3\).
02

Set up the Area Calculation

Because the function \(y = 4\) is constant, the graph is a horizontal line. The area under the curve in the interval \([1, 3]\) can be calculated as a rectangle, where the base is the interval length and the height is the value of the function. The base length is \(3 - 1 = 2\), and the height is \(4\).
03

Calculate the Area

The area \(A\) under the curve can be calculated using the formula for the area of a rectangle, \(A = ext{base} imes ext{height}\). Here, the base is \(2\) and the height is \(4\), so the area is \[A = 2 imes 4 = 8.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constant Function
A constant function is one of the simplest types of mathematical functions you can encounter. It is defined as a function that has the same output for any input in its domain. The constant function is expressed as \(y = c\), where \(c\) is a constant number, meaning it does not change regardless of the value of \(x\).

An example is the function \(y = 4\). No matter what \(x\) value is chosen within the interval, the \(y\)-value will always be \(4\). This characteristic makes the graph of a constant function a horizontal line parallel to the \(x\)-axis.

Constant functions are noteworthy because calculating the area under such a curve (or line in this case) often boils down to simple geometric calculations rather than complex integration.

Simply put, for a constant function, the key aspects to remember are:
  • The graph is a horizontal line.
  • The value remains "constant" across the entire domain.
  • The area under this horizontal line involves straightforward calculations.
Rectangle Area
Finding the area under the curve of a constant function involves understanding the basic principle of calculating the area of a rectangle. In geometry, the area of a rectangle is calculated by multiplying its base by its height. For constant functions, this calculation becomes a straightforward task.

Why a rectangle, you ask? Because the graph of a constant function like \(y = 4\) is a horizontal line. When you visualize the area under this line from the point \(x = 1\) to \(x = 3\), you're essentially looking at a rectangle. The base of this rectangle corresponds to the stretch on the \(x\)-axis, and the height is the constant value, here it's \(4\).

So the area of the rectangle under the curve is calculated as:
  • **Base** = Difference between start and end of the interval, which is \(3 - 1 = 2\).
  • **Height** = Constant value of the function, in this instance, \(4\).
  • **Area** = Base \(\times\) Height, which amounts to \(2 \times 4 = 8\).
Recognizing this simple geometry can greatly simplify problems involving constant functions.
Interval Length
The interval length is a crucial factor when determining the area under a constant function on a specified stretch of the \(x\)-axis. In mathematics, when you speak of intervals, you are specifying a range of \(x\)-values.

For this exercise, the interval is given as \([1, 3]\), which means we are interested in this segment on the \(x\)-axis.

To find the interval length, you need to calculate the difference between the end point and the start point of the interval. This is done using the formula:
  • Interval Length \( = (\text{Upper limit of the interval}) - (\text{Lower limit of the interval}) \).

In this case, the interval length would be \(3 - 1 = 2\). This length serves as the base of the rectangle when calculating the area under the constant function \(y = 4\) within the specific interval you are interested in.

Thus, understanding the interval length is not only essential for area calculations but also provides insight into the extent of the \(x\)-range you are dealing with in any such problem.

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