Chapter 3: Problem 94
Find the equation of the line tangent to the graph of \(y=\ln \left(4 x^{2}-7\right)\) at \(x=2\).
Short Answer
Expert verified
The tangent line at \( x = 2 \) is \( y - \ln(9) = \frac{16}{9}(x - 2) \).
Step by step solution
01
Find the value of the function at the given point
The equation of the tangent line requires a point on the line. First, substitute \( x = 2 \) into the original function to find \( y \): \( y = \ln(4(2)^2 - 7) = \ln(16 - 7) = \ln(9) \). Therefore, the point on the function is \((2, \ln(9))\).
02
Differentiate the function
To find the slope of the tangent line, take the derivative of the function \( y = \ln(4x^2 - 7) \). Using the chain rule, the derivative is \( \frac{d}{dx}[\ln(u)] = \frac{1}{u} \cdot \frac{du}{dx} \) where \( u = 4x^2 - 7 \). The derivative is therefore \( \frac{d}{dx}[\ln(4x^2 - 7)] = \frac{1}{4x^2 - 7} \cdot 8x = \frac{8x}{4x^2 - 7} \).
03
Evaluate the derivative at the given point
Substitute \( x = 2 \) into the derivative to find the slope of the tangent line at this point. \( \frac{8(2)}{4(2)^2 - 7} = \frac{16}{16 - 7} = \frac{16}{9} \). So, the slope of the tangent line is \( \frac{16}{9} \).
04
Write the equation of the tangent line
Using the point-slope form of a line \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \((x_1, y_1)\) is the point. We have \( y - \ln(9) = \frac{16}{9}(x - 2) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Tangent line
A tangent line is a straight line that just 'touches' a curve at a specific point. This point is where the line has the same slope as the curve. Think of it like a line gently resting on the edge of a mountain. It doesn't cross through, it stays right on the curve at one specific area.
To find the equation of a tangent line to a function at a specific point, we often need:
To find the equation of a tangent line to a function at a specific point, we often need:
- A point on the curve, which usually comes from plugging in an x-value into the function.
- The slope of the curve at that point, found using derivatives.
Derivative
The derivative measures how a function changes as its input changes. It is the rate at which the y-value of a function changes as the x-value changes. In simpler terms, the derivative tells us the slope of a function at any given point.
To find the derivative of a function, we apply different rules depending on the form of the function:
To find the derivative of a function, we apply different rules depending on the form of the function:
- Power Rule: This is used when dealing with terms like \(x^n\).
- Product Rule: Used when two functions are multiplied together.
- Chain Rule: Used when a function is inside another function, such as \(\ln(4x^2 - 7)\).
Logarithmic function
A logarithmic function is the inverse of an exponential function. If you think of exponentiation as a balloon expanding, logarithms are like figuring out how big the balloon was before it started expanding. Logarithms help 'undo' exponents by determining the original input.
- For a logarithmic function \(\log_b(x)\), it is asking: to what power must we raise \(b\) to get \(x\)?
- Natural logs use the number \(e\), approximately 2.718, and is denoted as \(\ln(x)\).
- Properties include \(\ln(ab) = \ln(a) + \ln(b)\) and \(\ln(a^b) = b\ln(a)\).
Chain rule
The chain rule is a formula for finding the derivative of a composite function. Think of a composite function as a "function inside a function", like a box inside another box. The chain rule helps us take a peek inside all the boxes.
Essentially, the chain rule states:\[(\text{out}'(\text{in})) \times \text{in}'\]- Where "out" is the outer function and "in" is the inner function.- Derivate the outer, keeping the inner the same, then multiply by the derivative of the inner.
In the problem, we used the chain rule to differentiate \(\ln(4x^2 - 7)\). The outer function is \(\ln(u)\) and the inner function is \(u = 4x^2 - 7\). So, the derivative becomes: \(\frac{d}{dx}[\ln(u)] \times \frac{d}{dx}[u]\). Applying the rule, we ended up with a derivative that showed how the function changes for any \(x\).
Essentially, the chain rule states:\[(\text{out}'(\text{in})) \times \text{in}'\]- Where "out" is the outer function and "in" is the inner function.- Derivate the outer, keeping the inner the same, then multiply by the derivative of the inner.
In the problem, we used the chain rule to differentiate \(\ln(4x^2 - 7)\). The outer function is \(\ln(u)\) and the inner function is \(u = 4x^2 - 7\). So, the derivative becomes: \(\frac{d}{dx}[\ln(u)] \times \frac{d}{dx}[u]\). Applying the rule, we ended up with a derivative that showed how the function changes for any \(x\).