/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 93 Find the equation of the line ta... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the equation of the line tangent to the graph of \(y=(\ln x)^{2}\) at \(x=3\).

Short Answer

Expert verified
The equation of the tangent line is \( y = \frac{2\ln 3}{3}x - \frac{6\ln 3}{3} + (\ln 3)^2 \).

Step by step solution

01

Determine the y-value of the function at x = 3

To begin, substitute the value of \( x = 3 \) into the original function to find the y-value. The function is \( y = (\ln x)^2 \). Evaluating it gives: \( y = (\ln 3)^2 \).
02

Find the derivative of the function for the slope

To find the equation of the tangent line, we need the slope, which requires us to find the derivative of \( y = (\ln x)^2 \). Using the chain rule, the derivative is: \( \frac{dy}{dx} = 2(\ln x) \cdot \frac{1}{x} = \frac{2\ln x}{x} \).
03

Evaluate the derivative at x = 3

Substitute \( x = 3 \) into the derivative to find the slope at this point. This yields \( \frac{dy}{dx} = \frac{2\ln 3}{3} \).
04

Write the equation of the tangent line

Using the point-slope form, \( y - y_1 = m(x - x_1) \), where \( m \) is the slope found in Step 3, \( x_1 = 3 \), and \( y_1 = (\ln 3)^2 \) from Step 1, the equation becomes: \[ y - (\ln 3)^2 = \frac{2\ln 3}{3}(x - 3) \]. Simplify this to find the equation of the tangent line.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative Calculus
Derivative calculus is a fundamental concept in mathematics that helps us understand how a function changes. The derivative of a function gives us its rate of change at any given point. In simple terms, it is a way to measure how a function's output value changes as its input value changes. For example, if we have a graph of a function, the derivative at a particular point will tell us the slope of the tangent line at that point.

When working with derivatives, we use a range of rules and techniques. These include the power rule, product rule, quotient rule, and the chain rule. Each of these rules helps to find the derivative of more complex functions based on simpler functions. In the current exercise, derivative calculus was used to find the slope of the tangent line to the curve represented by the function \( y = (\ln x)^2 \).

This step is crucial in various applications, such as physics and engineering, where understanding how systems change over time is often key to finding solutions.
Chain Rule
The chain rule is an essential tool in calculus, used to find the derivative of a composite function. A composite function is when one function is applied within another, like \( y = (\ln x)^2 \) in our example. Here, the logarithmic function \( \ln x \) is inside the squaring function.

The chain rule states that to differentiate a composite function, you multiply the derivative of the outer function by the derivative of the inner function. For the function \( y = (\ln x)^2 \), we first consider the outer function, \( u^2 \), where \( u = \ln x \). The derivative of \( u^2 \) is \( 2u \) multiplied by the derivative of \( u \), which is \( \frac{1}{x} \).

This leads to the final derivative \( \frac{dy}{dx} = 2(\ln x) \cdot \frac{1}{x} = \frac{2\ln x}{x} \). The chain rule unravels the layers of a function, allowing us to calculate the derivative of even the most complex expressions.
Logarithmic Function
The logarithmic function is an inverse function to the exponential function. For our problem, the natural logarithm, denoted as \( \ln x \), is the function used. The natural logarithm specifically refers to the logarithm with base \( e \), where \( e \approx 2.718 \).

Logarithmic functions have unique properties that make them useful in solving equations involving exponential growth or decay and in models of population growth and financial calculations. They simplify multiplication into addition, and exponential functions into linear functions.

In calculus, the derivative of the \( \ln x \) function is particularly straightforward: \( \frac{d}{dx}(\ln x) = \frac{1}{x} \). This simplicity makes it easier to work with when applying the chain rule, which was essential in our original exercise when differentiating \( y = (\ln x)^2 \) to find the tangent line equation.
Slope of Tangent Line
The slope of the tangent line is a key concept in understanding how a function behaves at a certain point. When you draw a tangent line to a curve at a particular point, the slope of this line represents the instantaneous rate of change of the function at that point.

In calculus, finding the slope of the tangent line usually involves determining the derivative of the function. Once the derivative is found, we can evaluate it at the given point to obtain the slope. In our exercise, we evaluated the derivative \( \frac{2\ln x}{x} \) at \( x = 3 \) to find the slope of the tangent line as \( \frac{2\ln 3}{3} \).

With the slope known, we can use the point-slope form of a line to write the equation of the tangent line. This form looks like \( y - y_1 = m(x - x_1) \), where \( m \) is the slope of the tangent line, and \( (x_1, y_1) \) are the coordinates of the point of tangency on the function. By finding the slope of the tangent line, we access deeper insights into the behavior and shape of the function at the point of interest.

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