Chapter 3: Problem 71
Differentiate. $$ y=\frac{\ln x}{x^{5}} $$
Short Answer
Expert verified
The derivative is \( y' = \frac{1 - 5\ln x}{x^6} \).
Step by step solution
01
Apply the Quotient Rule
The given function is \( y = \frac{\ln x}{x^5} \). To differentiate this, you'll use the quotient rule for derivatives, which states that if you have a function \( y = \frac{u}{v} \), then \( y' = \frac{u'v - uv'}{v^2} \). Here, \( u = \ln x \) and \( v = x^5 \).
02
Differentiate the Numerator and Denominator
First, differentiate \( u = \ln x \). The derivative is \( u' = \frac{1}{x} \). Next, differentiate \( v = x^5 \). The derivative is \( v' = 5x^4 \).
03
Plug into the Quotient Rule Formula
Substitute \( u' = \frac{1}{x} \), \( u = \ln x \), \( v' = 5x^4 \), and \( v = x^5 \) into the quotient rule: \[ y' = \frac{\frac{1}{x} \cdot x^5 - \ln x \cdot 5x^4}{(x^5)^2} \] Simplify each part: \( u'v = x^4 \) and \( uv' = 5x^4 \ln x \).
04
Simplify the Expression
Simplify the differentiated function: \[ y' = \frac{x^4 - 5x^4 \ln x}{x^{10}} \] Combine terms in the numerator: \[ y' = \frac{x^4(1 - 5\ln x)}{x^{10}} \] Further simplify by canceling \( x^4 \): \[ y' = \frac{1 - 5\ln x}{x^6} \]
05
Write the Final Answer
The final derivative of the function \( y = \frac{\ln x}{x^5} \) is \[ y' = \frac{1 - 5\ln x}{x^6} \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quotient Rule
The quotient rule is a powerful tool in calculus for differentiating a division between two functions. Imagine that when you divide one function by another, the rules for finding the derivative get a bit more complex than just differentiating each part separately. With the quotient rule, you can find the derivative of a function that is the quotient of two other functions.
For a function, say, where you have \( y = \frac{u}{v} \), the quotient rule gives you a formula to follow:
For a function, say, where you have \( y = \frac{u}{v} \), the quotient rule gives you a formula to follow:
- The numerator's derivative, \( u' \), in our example is the derivative of the natural logarithm, \( \ln x \).
- The denominator's derivative, \( v' \), is simply differentiating \( x^5 \).
Derivatives
Derivatives are at the heart of calculus, describing how a function changes as its input changes. To differentiate a function means to find its derivative. This gives us a mathematical way to analyze how something is changing at each point.
In our example, we are looking at the derivatives of \( \ln x \) and \( x^5 \) as parts of a larger function. Here's what happens:
By doing so, we see the derivative of the whole expression, not just the parts.
In our example, we are looking at the derivatives of \( \ln x \) and \( x^5 \) as parts of a larger function. Here's what happens:
- The derivative of \( \ln x \) is \( \frac{1}{x} \). This tells us how the natural log function changes.
- The derivative of \( x^5 \) is \( 5x^4 \). This indicates the rate of change of \( x^5 \) at any point.
By doing so, we see the derivative of the whole expression, not just the parts.
Natural Logarithm
The natural logarithm is a special type of logarithm often used in calculus and complex mathematics, represented as \( \ln x \). The base of the natural logarithm is the number \( e \), which is approximately equal to 2.718.
When you encounter \( \ln x \) in differentiation, its properties become very useful, especially since it has a straightforward derivative:
Understanding how \( \ln x \) behaves helps untangle its behavior when used as part of more complex functions or equations.
When you encounter \( \ln x \) in differentiation, its properties become very useful, especially since it has a straightforward derivative:
- The derivative of \( \ln x \) is \( \frac{1}{x} \).
- This derivative means that as \( x \) increases, the rate of change of \( \ln x \) decreases, making it a fascinating unique function.
Understanding how \( \ln x \) behaves helps untangle its behavior when used as part of more complex functions or equations.