/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 Differentiate. $$ y=1-e^{-3 ... [FREE SOLUTION] | 91Ó°ÊÓ

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Differentiate. $$ y=1-e^{-3 x} $$

Short Answer

Expert verified
The derivative is \( y' = 3e^{-3x} \).

Step by step solution

01

Identify the Function

The given function is a combination of constant terms and an exponential function. Specifically, it is of the form \( y = 1 - e^{-3x} \).
02

Differentiate Constant Terms

Differentiate the constant term \( 1 \). The derivative of a constant is zero, so the derivative of \( 1 \) is \( 0 \).
03

Apply Exponential Differentiation

Now, differentiate the term \( -e^{-3x} \). Recall that the derivative of \( e^{u} \) with respect to \( x \), where \( u \) is a function of \( x \), is \( e^{u} \cdot \frac{du}{dx} \).
04

Differentiate the Exponential Argument

Here, \( u = -3x \), so \( \frac{du}{dx} = -3 \).
05

Compute the Derivative

Using the chain rule, the derivative of \( -e^{-3x} \) is \( -e^{-3x} \cdot (-3) = 3e^{-3x} \).
06

Combine the Results

Combine the results of the differentiated components: derivative of constant is zero, and derivative of \( -e^{-3x} \) is \( 3e^{-3x} \). Thus, the overall derivative of the function is \( y' = 0 + 3e^{-3x} = 3e^{-3x} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Function
The exponential function is one of the most important functions in mathematics, especially when dealing with continuous growth or decay. An exponential function is typically written as \( e^{x} \), where \( e \) is approximately equal to 2.71828 - a constant known as Euler's number. This function has unique properties, such as the rate of change being proportionate to the function's current value.

An important feature of exponential functions is that they grow or decay at a constant rate. They are incredibly useful in modeling various real-world scenarios, such as population growth, radioactive decay, and continuously compounded interest. In differentiation, recognizing the form of an exponential function is crucial, as it dictates the rules and steps needed to find derivatives effectively.
Chain Rule
The chain rule is a fundamental technique in calculus for finding derivatives of composite functions. A composite function is formed when one function is applied to the result of another function, like \( f(g(x)) \).

To apply the chain rule, follow these steps:
  • Differentiate the outer function while keeping the inner function unchanged.
  • Multiply the result by the derivative of the inner function.
The rule can be expressed mathematically as:\[ \frac{d}{dx} f(g(x)) = f'(g(x)) \cdot g'(x) \]In the original problem, the chain rule is used to differentiate the function \( -e^{-3x} \). First, the derivative of \( e^{u} \) is taken, resulting in \( e^{u} \cdot \frac{du}{dx} \), where \( u = -3x \) and \( \frac{du}{dx} = -3 \). This process converts complex differentiation into manageable pieces.
Derivative of a Constant
The derivative of a constant is one of the simplest yet foundational ideas in calculus. A constant is a number without any variable attached, like 1, \( \pi \), or -7. When you differentiate any constant term, the result is always zero because constants do not change. Thus, their rate of change is zero.

For example, if you have a function \( y = 5 \) or in the original exercise, \( y = 1 \), differentiating it yields 0. This principle is extremely useful as it simplifies differentiation by eliminating terms that do not depend on the variable in question, allowing focus on those that do. Recognizing and applying the derivative of a constant efficiently is essential in quickly solving more complex calculus problems.

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Most popular questions from this chapter

Differentiate. $$ f(x)=\ln \frac{1+\sqrt{x}}{1-\sqrt{x}} $$

More Americans are buying organic fruit and vegetables and products made with organic ingredients. The amount \(A(t)\), in billions of dollars, spent on organic food and beverages \(t\) years after 1995 can be approximated by $$ A(t)=2.43 e^{0.18 t} $$ a) Estimate the amount that Americans spent on organic food and beverages in \(2009 .\) b) Estimate the rate at which spending on organic food and beverages was growing in \(2006 .\)

Describe the differences in the graphs of an exponential function and a logistic function.

The tortoise population, \(P(t),\) in a square mile of the Mojave Desert after \(t\) years can be approximated by the logistic equation $$ P(t)=\frac{3000}{20+130 e^{-0.214 t}} $$ a) Find the tortoise population after \(0 \mathrm{yr}, 5 \mathrm{yr}, 15 \mathrm{yr},\) and 25 yr. b) Find the rate of change in the population, \(P^{\prime}(t)\). c) Find the rate of change in the population after \(0 \mathrm{yr}\) \(5 \mathrm{yr}, 15, \mathrm{yr},\) and \(25 \mathrm{yr}\) d) What is the limiting value (see Exercise 42 ) for the population of tortoises in a square mile of the Mojave Desert?

At a price of \(x\) dollars, the demand, in thousands of units, for a certain turntable is given by the demand function $$ q=240 e^{-0.003 x} $$ a) How many turntables will be bought at a price of \(\$ 250 ?\) Round to the nearest thousand. b) Graph the demand function for \(0 \leq x \leq 400\). c) Find the marginal demand, \(q^{\prime}(x)\). d) Interpret the meaning of the derivative.

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