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Chapter 3: Problem 24

Write an equivalent logarithmic equation. $$ M^{p}=V $$

Short Answer

Expert verified
The equivalent logarithmic equation is \(p = \log_{M}(V)\).

Step by step solution

01

Understand the Exponential Form

The given equation is in exponential form, where \(M^p = V\). Here, \(M\) is the base of the exponent, \(p\) is the exponent, and \(V\) is the result of raising \(M\) to the power \(p\).
02

Identify Components for Logarithmic Form

To convert the equation into a logarithmic form, identify the base \(M\), the exponent \(p\), and the result \(V\). The logarithmic form asks: 'What exponent do we raise the base \(M\) to get \(V\)?' This is essentially finding \(p\).
03

Write the Logarithmic Form

Rephrase the exponential equation \(M^p = V\) into its equivalent logarithmic form. The logarithmic equation asks: 'What power do we raise \(M\) to, in order to obtain \(V\)?' This is denoted as: \(p = \log_{M}(V)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Form
When dealing with equations, it's important to recognize different forms and their purposes. The exponential form is one where a number, called the base, is raised to a power. This power is known as the exponent. For example, in the equation \( M^p = V \),
  • \( M \) is the base
  • \( p \) is the exponent, determining how many times the base is multiplied by itself
  • \( V \) is the result achieved by multiplying the base by itself, \( p \) times
Understanding exponential form is crucial because it represents situations of rapid growth, such as population increase or compound interest. Recognizing the base, exponent, and result in such equations is the first step in transforming them into other mathematical forms that might shed new light on the relationships involved.
Conversion to Logarithmic Form
Once you understand the exponential form, conversion to logarithmic form is a helpful next step. Logarithms help us answer the question: "What power do we need to raise the base to obtain the given result?" Let's see how this works with the equation \( M^p = V \).To convert, you'll need to identify:
  • The base 鈥� it's what is being raised to a power; in our example, \( M \).
  • The result 鈥� this is \( V \), which the base raised to the exponent yields.
  • The exponent itself, which is \( p \) in the equation.
With these components identified, we can write the equivalent in logarithmic form: \( p = \log_{M}(V) \). Here, the logarithm \( \log_{M}(V) \) explicitly states that \( p \) is the power to which we raise \( M \) to achieve \( V \). This transformation uncovers the underlying power relationship in a more direct and question-oriented way.
Understanding Logarithms
Logarithms can be considered the inverse of exponential operations. They help simplify problems involving power relationships and make them more manageable. In our equation linear transformation鈥擻( p = \log_{M}(V) \)鈥攍ogarithms are asking, "to what power must we raise M to achieve V?"Here's a breakdown:
  • Logarithms transform multiplicative relationships into additive ones, making calculations easier.
  • The base of the logarithm corresponds to the base of the exponential equation.
  • Logarithmic calculations answer specific questions about growth rates and scaling factors in various scientific and real-world applications.
Understanding the concept of logarithms allows you to solve equations where finding the power is essential, providing a valuable tool in fields like biology, physics, and finance. Integrating exponential and logarithmic equations opens up a world of mathematical exploration and application, giving you the flexibility to approach problems from multiple angles.

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Most popular questions from this chapter

At a price of \(x\) dollars, the demand, in thousands of units, for a certain turntable is given by the demand function $$ q=240 e^{-0.003 x} $$ a) How many turntables will be bought at a price of \(\$ 250 ?\) Round to the nearest thousand. b) Graph the demand function for \(0 \leq x \leq 400\). c) Find the marginal demand, \(q^{\prime}(x)\). d) Interpret the meaning of the derivative.

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