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Differentiate. $$ f(x)=e^{-x} $$

Short Answer

Expert verified
The derivative is \( f'(x) = -e^{-x} \).

Step by step solution

01

Identify the Rule of Differentiation

To differentiate the function \( f(x) = e^{-x} \), we first identify the rule of differentiation applicable. Here, we apply the chain rule because we have an exponential function with a composite exponent \(-x\). The derivative of \( e^u \) with respect to \( u \) is \( e^u \), while the derivative of \(-x\) with respect to \( x \) is \(-1\).
02

Apply the Chain Rule

Using the chain rule, the derivative \( f'(x) \) is found by differentiating the outer function and multiplying it by the derivative of the inner function: \[ f'(x) = e^{-x} \cdot (-1) \]
03

Simplify the Expression

Simplify the expression obtained by applying the chain rule. The derivative of \( e^{-x} \) becomes: \[ f'(x) = -e^{-x} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule in Differentiation
The chain rule is a fundamental tool in calculus used to differentiate composite functions. A composite function is essentially a function within another function, often represented as \( f(g(x)) \). The chain rule allows us to take derivatives of these complex functions by breaking them down into their simpler components. When using the chain rule, you differentiate the outer function first and then multiply by the derivative of the inner function.

For example, if you have a function like \( f(x) = e^{-x} \), you identify two distinct parts:
  • The outer function: \( e^u \)
  • The inner function: \( u = -x \)
Now, the chain rule directs us to:

- Differentiate the outer function considering the inner function as a variable. So, the derivative of \( e^u \) is \( e^u \).
- Multiply this by the derivative of the inner function: the derivative of \(-x\) is \(-1\).

Thus, for \( f(x) = e^{-x} \), applying the chain rule results in multiplying \( e^{-x} \) by \(-1\), giving us a final derivative of \(-e^{-x} \).
Exponential Function Characteristics
Understanding an exponential function is crucial in calculus, especially since they frequently appear in various scientific applications. The general form of an exponential function is \( f(x) = a^x \). However, when the base is Euler's number \( e \), it becomes \( f(x) = e^x \), a special type of exponential function that is particularly nice to differentiate.

When differentiating an exponential function like \( e^x \), it's important to note:
  • The derivative of \( e^x \), interestingly, is itself \( e^x \).
  • This self-replicating property showcases the distinct and unique nature of the exponential function.
The situation changes slightly when the exponent itself is more complex. For functions like \( e^{-x} \), you need to apply the chain rule, as discussed, because of the composite nature of the exponent.

Exponential functions widely appear in natural growth processes, compounding interest, and in fields like physics and biology, as they represent processes with constant relative growth rates. Understanding their differentiation helps tackle many real-world problems smoothly.
Understanding Derivatives
Derivatives lie at the heart of calculus, acting as a measure of how a function changes as its input changes. At its core, the derivative of a function at a given point reflects the rate of change or the slope of the tangent line at that point.

The act of differentiating involves calculating this instantaneous rate of change. For any function \( f(x) \), the derivative \( f'(x) \) informs us about how \( f(x) \) changes with a small change in \( x \).

When differentiating different types of functions, several rules and techniques, like the chain rule, make the process streamlined. In our particular function, \( f(x) = e^{-x} \), the chain rule plays a crucial role in simplifying the derivative calculation.
  • Identifying when a chain rule is required, such as in composite functions, is a vital calculus skill.
  • Once differentiated correctly, the derivative \( f'(x) = -e^{-x} \) serves as a tool to understand the decreasing nature and slope dynamics of the original function.
Derivatives are essential in various fields, including physics for motion and dynamics, economics for understanding marginal concepts, and engineering for design and analysis. Grasping the basics of derivatives opens the door to more advanced topics in calculus.

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Most popular questions from this chapter

Use the Tangent feature from the DRAW menu to find the rate of change in part (b). Pelican Fabrics purchases a new video surveillance system. The value of the system is modeled by $$ V(t)=17,500(0.92)^{t} $$ where \(V\) is the value of the system, in dollars, \(t\) years after its purchase. a) Use the model to estimate the value of the system \(5 \mathrm{yr}\) after it was purchased. b) What is the rate of change in the value of the system at the end of 5 yr? c) When will the system be worth half of its original value?

Differentiate. $$ y=\frac{e^{3 t}-e^{7 t}}{e^{4 t}} $$

A lake is stocked with 400 rainbow trout. The size of the lake, the availability of food, and the number of other fish restrict population growth to a limiting value of 2500 trout. The population of trout in the lake after time \(t\), in months, is approximated by $$ P(t)=\frac{2500}{1+5.25 e^{-0.32 t}} $$ a) Find the population after 0 months, 1 month, 5 months, 10 months, 15 months, and 20 months. b) Find the rate of change, \(P^{\prime}(t)\). c) Sketch a graph of the function.

Differentiate. $$ y=\ln \left|\frac{x^{5}}{(8 x+5)^{2}}\right| $$

As part of a study, students in a psychology class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. After \(t\) months, the average score \(S(t),\) as a percentage, was found to be given by $$ S(t)=78-15 \ln (t+1), \quad t \geq 0 $$. a) What was the average score when they initially took the test, \(t=0 ?\) b) What was the average score after 4 months? c) What was the average score after 24 months? d) What percentage of their original answers did the students retain after 2 years ( 24 months)? e) Find \(S^{\prime}(t)\). f) Find the maximum and minimum values, if they exist. g) Find \(\lim _{t \rightarrow \infty} S(t)\) and discuss its meaning.

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