Chapter 2: Problem 79
Draw a graph to match the description given. Answers will vary. \(F(x)\) has a negative derivative over \((-\infty,-1)\) and a positive derivative over \((-1, \infty),\) and \(F^{\prime}(-1)\) does not exist.
Short Answer
Expert verified
Graph a function that decreases to \( x = -1 \), then increases, with a sharp point at \( x = -1 \).
Step by step solution
01
Understand the Problem
We need to draw a graph of a function \( F(x) \) where the derivative, \( F'(x) \), is negative for \( x \) values in the interval \((- \infty, -1)\), and positive for \( x \) values in the interval \((-1, \infty)\), with \( F'(-1) \) not existing.
02
Identify the Key Point
The point \( x = -1 \) is crucial here. At this point, the derivative \( F'(x) \) changes from negative to positive, meaning \( F(x) \) has a local minimum there. Additionally, \( F'(-1) \) does not exist, suggesting a sharp point or cusp at \( x = -1 \).
03
Consider Derivative Behavior
Since \( F'(x) \) is negative on \((- \infty, -1)\), \( F(x) \) is decreasing on this interval. Since \( F'(x) \) is positive on \((-1, \infty)\), \( F(x) \) is increasing on this interval. The transition at \( x = -1 \) must cause \( F'(x) \) to not exist.
04
Sketch the Graph
Draw the graph of \( F(x) \), making sure that it decreases towards \( x = -1 \) and increases after \( x = -1 \). Ensure that \( x = -1 \) presents a sharp point, where the slope instantaneously changes, reflecting the non-existence of \( F'(-1) \).
05
Verify the Graph Matches Description
Check if the graph corresponds to \( F'(x) < 0 \) for \((- \infty, -1)\) and \( F'(x) > 0 \) for \((-1, \infty)\), with \( F'(-1) \) not existing. Ensure the graph shows a decrease before and increase after \( x = -1 \), with a sharp point.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Derivatives
Derivatives help us understand how a function changes at any given point. They represent the rate at which a function is changing, which is crucial in determining if a function is increasing or decreasing. For the function \(F(x)\), if the derivative \(F'(x) < 0\), it means that \(F(x)\) is decreasing over that interval. Conversely, if \(F'(x) > 0\), \(F(x)\) is increasing.The derivative's behavior is a strong indicator of the function's slope:
- A negative derivative indicates a downward slope, meaning the function is decreasing.
- A positive derivative implies an upward slope, suggesting the function is increasing.
- If the derivative does not exist at a point, it could mean there's a sharp turn, like a cusp or corner.
Graph Sketching Techniques
Graph sketching involves drawing a graph based on characteristics described by the function and its derivatives. It's about visualizing the behavior of a function given certain derivative conditions. Here’s a guide to sketch \(F(x)\):1. **Identify Intervals:** Look at where \(F'(x)\) is positive or negative. - Decrease on \((-\infty, -1)\). - Increase on \((-1,\, \infty)\).2. **Find Critical Points:** These points often occur where the derivative changes or doesn't exist. - At \(x = -1\), \(F'(x)\) shifts from negative to positive, creating a potential local minimum.3. **Determine the Nature of the Critical Point:** Since \(F'(x)\) at \(x = -1\) does not exist, anticipate a sharp turn or cusp.When sketching:
- Begin by plotting the intervals affected by the derivative’s sign.
- Mark the critical point \(x = -1\) with a sharp point to showcase the non-existing derivative.
- Ensure the graph is descending before \(x = -1\) and ascending afterwards, capturing the local minimum.
Exploring Local Minimum
A local minimum is a point where the function value is smaller than all other function values on some interval around it. It's like a "valley" on a graph. For \(F(x)\) at \(x = -1\):- The function decreases before this point and increases after it.- This pattern typically suggests \(x = -1\) is a local minimum.Let’s explore this step-by-step:
- Before \(x = -1\), the negative derivative implies a declining function – falling towards "valley bottom."
- After \(x = -1\), a positive derivative indicates the function climbs – rising from the "valley bottom."
- The non-existence of \(F'(-1)\) emphasizes a dramatic change, often depicted as a cusp, rather than a smooth curve.